## Very important Maths questions for SSC CGL-13 Series#5

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Note: Next 2-3 series will contain questions of ssc CGl tier-2 solved questions.

1. The product of 2 numbers is 1575 and their quotient is 9/7. Then the sum of the numbers is –

a. 74

b. 78

c. 80

d. 90

Ans : Let the numbers be x and y .

We know xy = 1575

And x/y = 9/7

We know xy/x/y = 1575/9/7

We know y2 = 1225

We know y = 35 and x = 45

We know The sum of the numbers = 45+35

= 80

2. The value of (81)3.6 * (9)2.7/ (81)4.2 * (3) is __

a. 3

b. 6

c. 9

d. 8.2

Ans : (81)3.6 * (9)2.7/(81)4.2 * (3) = (3)14.4 * (3)5.4/(3)16.8 * (3)

= 314.4+5.4-16.8-1

= 32

= 9

3. . ?6+?6+?6+… is equal to –

a. 2

b. 5

c. 4

d. 3

Ans : Let ?6+?6+?6+…. be x.

We know x =?6+x

We know x2 = 6+x

We know x2 + x – 6 = 0

We know (x-3) (x+2) = 0

We know x = 3

4. The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is –

a. 24

b. 32

c. 40

d. 28

Ans : Let the consecutive odd numbers be x and (x+2)

We know that x2 + (x + 2)2 = 394

We know x2 + x2 + 4x + 4 = 394

We know 2 x2 +4x – 390 = 0

We know x2 + 2x – 195 = 0

We know (x +15) (x-13) = 0

We know x = 13

We know Required sum = 13 +15 =28

5. When (6767 +67) is divided by 68, the remainder is-

a. 1

b. 63

c. 66

d. 67

Ans: (6767+ 67) = 67(6766 + 166)

As 66 is an even number

We know 6766 is an even number

We know (6766 + 1) is perfectly divisible by (67 + 1)

i.e. 68

We know The remainder = 67

6. In a division sum, the divisor is 4 times the quotient and twice the remainder. If a and b are respectively the divisor and the dividend then-

a. 4b-a2 /a =3

b. 4b-2a /a2 =2

c. (a+1)2 = 4b

d. A(a+2)/b = 4

Ans : As divisor is a, and dividend is b.

We know Quotient = a/4

And Remainder = a/2

We know b = a * a/4 + a/2

We know 4b = a2 + 2a

We know a(a+2)/b = 4

7. If 738 A6A is divisible by 11, then the value of A is-

a. 6

b. 3

c. 9

d. 1

Ans : As 738A6 A is divisible by 11.

We know A + A + 3 = 6 + 8 + 7

We know A = 9

8. The east positive integer that should be subtracted from 3011 * 3012 so that the difference is perfect square is-

a. 3009

b. 3010

c. 3011

d. 3012

Ans : We know that 3011 * 3012 = 3011 (3011 + 1)

= (3011)2 + 3011

We know Required least number = 3011

9. P, Q, R are employed to do a work for Rs. 5750. P and Q together finished 19/23 of work and Q and R together finished 8/23 of work. Wage of Q, in rupees, is-

a. 2850

b. 3750

c. 2750

d. 1000

Ans : Work done by Q = 19/23 + 8/23 – 1

4/23

We know Wage of Q = 4/23 * 5750

= Rs. 1000

10. A can do a piece of work in 24 day, B in 32 days and C in 64 days. All begin to do it together, but A leaves after 6 days and B leaves 6 days before the completion of the work. How many days did the work last?

a. 15

b. 20

c. 18

d. 30

Ans : Work done by A = 6/24 = ¼

Work done by B = (x-6)/32

(where x is no. of days in which work is competed)

We know that ¼ + x – 6/32 + x/64 = 1

We know 16 + 24 – 12 + x /64 = 1

We know 3x + 4 = 64

We know x = 60/3 = 20 days

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