A straight line parallel to the base QR of the ∆PQR intersect PQ and PR at the points S and T respectively. If the area of the ∆PQT be 36 cm2 then area of the ∆PRS is:
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Q:
A straight line parallel to the base QR of the ∆PQR intersect PQ and PR at the points S and T respectively. If the area of the ∆PQT be 36 cm2 then area of the ∆PRS is:
- 1$$ {18 {\ cm^{2}}}$$false
- 2$$ {36 {\ cm^{2}}}$$true
- 3$$ {28 {\ cm^{2}}}$$false
- 4$$ {48 {\ cm^{2}}}$$false
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