Maths Practice Question and Answer

Q:

If the population of a town is 12.000 and the population increases at the rate of 10% per annum, then find the population. after 3 years.

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  • 1
    15,972
    Correct
    Wrong
  • 2
    12,200
    Correct
    Wrong
  • 3
    11,200
    Correct
    Wrong
  • 4
    10,200
    Correct
    Wrong
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Answer : 1. "15,972"
Explanation :

To find the population after 3 years given that it increases at a rate of 10% per annum, you can use the formula for exponential growth:

𝑃=𝑃0×(1+𝑟)𝑛P=P0×(1+r)n

Where:

  • 𝑃P = Population after 𝑛n years
  • 𝑃0P0 = Initial population
  • 𝑟r = Rate of increase (in decimal form)
  • 𝑛n = Number of years

Given:

  • 𝑃0=12,000P0=12,000 (Initial population)
  • 𝑟=0.10r=0.10 (10% increase per annum)
  • 𝑛=3n=3 (Number of years)

Substitute these values into the formula:

𝑃=12,000×(1+0.10)3P=12,000×(1+0.10)3

𝑃=12,000×(1.10)3P=12,000×(1.10)3

𝑃=12,000×(1.331)P=12,000×(1.331)

𝑃=15,972P=15,972

So, the population after 3 years would be approximately 15,972.


Q:

The price of sugar increases by 15%. By what percentage should the consumption of sugar be decreased so that the expenditure on the purchase of sugar remains the same? [Give your answer correct to 2 decimal places.]

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  • 1
    11.11%
    Correct
    Wrong
  • 2
    12.5%
    Correct
    Wrong
  • 3
    14.16%
    Correct
    Wrong
  • 4
    13.04%
    Correct
    Wrong
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Answer : 4. "13.04%"
Explanation :

To solve this problem, let's denote:

  • Initial price of sugar = P
  • Initial quantity consumed = Q
  • Initial expenditure = PQ

After the price increases by 15%, the new price becomes 1.15P.

To keep the expenditure constant, the new quantity consumed (let's call it Q') can be calculated using the formula:

New expenditure = New price × New quantity

Setting the new expenditure equal to the initial expenditure:

PQ = (1.15P) * Q'

Now, solve for Q':

Q' = PQ / (1.15P)

Simplify:

Q' = Q / 1.15

Now, let's find the percentage decrease in consumption:

Percentage decrease = [(Q - Q') / Q] * 100

Substituting the value of Q':

Percentage decrease = [(Q - (Q / 1.15)) / Q] * 100

Percentage decrease = [(Q * (1 - 1/1.15)) / Q] * 100

Percentage decrease ≈ [(1 - 0.8696) * 100] ≈ 13.04%

Therefore, the consumption of sugar should be decreased by approximately 13.04% to keep the expenditure on the purchase of sugar the same after a 15% increase in price.

Q:

In an examination, 92% of the students passed and 480 students failed. If so, how many students appeared in the examination?

404 0

  • 1
    5800
    Correct
    Wrong
  • 2
    6200
    Correct
    Wrong
  • 3
    6000
    Correct
    Wrong
  • 4
    5000
    Correct
    Wrong
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Answer : 3. "6000"
Explanation :

Let's denote the total number of students who appeared in the examination as 𝑥x.

Given that 92% of the students passed, it means 8% failed because the total percentage is 100%.

We can set up the equation:

8% of 𝑥=4808% of x=480

To find 8% of 𝑥x, we multiply 𝑥x by 81001008 (which is the same as multiplying by 0.08):

0.08𝑥=4800.08x=480

Now, we can solve for 𝑥x:

𝑥=4800.08x=0.08480𝑥=6000x=6000

So, 6000 students appeared in the examination.


Q:

The sum of weights of A and B is 80 kg. 50% of A's weight is $${5\over6}$$ times the weight of B. Find the difference between their weights. 

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  • 1
    20 kg
    Correct
    Wrong
  • 2
    10 kg
    Correct
    Wrong
  • 3
    25 kg
    Correct
    Wrong
  • 4
    15 kg
    Correct
    Wrong
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Answer : 1. "20 kg"
Explanation :

Let's denote the weight of A as 𝑥x kg and the weight of B as 𝑦y kg.

Given:

  1. 𝑥+𝑦=80x+y=80 (Sum of weights of A and B is 80 kg)
  2. 0.5𝑥=56𝑦0.5x=65y (50% of A's weight is 5665 times the weight of B)

We can solve these two equations to find the values of 𝑥x and 𝑦y, and then calculate the difference between their weights.

From equation 2: 0.5𝑥=56𝑦0.5x=65y Multiply both sides by 2 to get rid of the fraction: 𝑥=56𝑦×2x=65y×2 𝑥=106𝑦x=610y 𝑥=53𝑦x=35y

Now substitute this expression for 𝑥x into equation 1: 53𝑦+𝑦=8035y+y=80 83𝑦=8038y=80 Multiply both sides by 3883: 𝑦=80×38y=80×83 𝑦=30y=30

Now that we have found the weight of B, we can find the weight of A using equation 1: 𝑥+30=80x+30=80 𝑥=80−30x=80−30 𝑥=50x=50

So, the weight of A is 50 kg and the weight of B is 30 kg.

Now, let's find the difference between their weights: Difference=Weight of A−Weight of BDifference=Weight of A−Weight of B Difference=50−30Difference=50−30 Difference=20Difference=20

Therefore, the difference between their weights is 20 kg.

Q:

If 40% of (A+B) = 60% of (A-B) then $${2A-3B}\over {A+B}$$ is

328 0

  • 1
    $${7\over 6}$$
    Correct
    Wrong
  • 2
    $${6\over 7}$$
    Correct
    Wrong
  • 3
    $${5\over 6}$$
    Correct
    Wrong
  • 4
    $${6\over 5}$$
    Correct
    Wrong
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Answer : 1. "$${7\over 6}$$"
Explanation :

Q:

A sofa-set listed at ₹ 800 is sold to a retailer at successive discounts of 25% and 15% by the wholesaler. Then the cost price of the sofa-set for retailer is-

657 0

  • 1
    500
    Correct
    Wrong
  • 2
    510
    Correct
    Wrong
  • 3
    550
    Correct
    Wrong
  • 4
    560
    Correct
    Wrong
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Answer : 2. "510"
Explanation :

Q:

A shopkeeper gives rebate of 20% and 10% successively on print price of a chair. If cost of chair is 2,000, then how much amount will customer pay?

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  • 1
    1400
    Correct
    Wrong
  • 2
    1500
    Correct
    Wrong
  • 3
    1600
    Correct
    Wrong
  • 4
    1440
    Correct
    Wrong
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Answer : 4. " 1440 "
Explanation :

Q:

Alex sold his goods after announcing two successive discounts of 30% each. The effective discount altogether is-

526 0

  • 1
    52%
    Correct
    Wrong
  • 2
    49%
    Correct
    Wrong
  • 3
    50%
    Correct
    Wrong
  • 4
    51%
    Correct
    Wrong
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Answer : 4. "51%"
Explanation :

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