Quantitative Aptitude Practice Question and Answer
8Q:What was the day of the week on 17th June, 1998 ? 2735 65b5cc761e4d2b4197774fd16
5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse
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Answer : 3. "Wednesday"
Explanation :
Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.
Q:If the true discount on sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ? 3302 45b5cc723e4d2b4197774f6a4
5b5cc723e4d2b4197774f6a4- 1Rs.948false
- 2Rs.876false
- 3Rs.768true
- 4Rs.658false
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Answer : 3. "Rs.768"
Explanation :
Answer: C) Rs.768 Explanation: P.W. = 100×T.DR×T = 100×16814×2 = 600. Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
Q:A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, is: 1805 35b5cc7d7e4d2b4197775151f
5b5cc7d7e4d2b4197775151f- 120%false
- 225%true
- 333.33%false
- 418%false
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Answer : 2. "25%"
Explanation :
Answer: B) 25% Explanation: When the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 litres of milk. Since, the profit % = ProfitCostPricex100 Therefore, profit percentage = 520x100 = 25%
Q:The total number of females are what percent of the total number of males in the organization?
4612 25d4abda611160f205237578e
5d4abda611160f205237578e- 190false
- 270false
- 380true
- 460false
- 5None of thesefalse
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Answer : 3. "80"
Q:What should come in place of the question mark(?) in the following number series?
1, 5, 13 , 29 ,? , 125 , 253
2093 25d4a9746822faf1e4e7fd7b6
5d4a9746822faf1e4e7fd7b61, 5, 13 , 29 ,? , 125 , 253
- 183false
- 269false
- 361true
- 465false
- 581false
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Answer : 3. "61"
Explanation :
The difference between number will be 4, 8, 16, 32, 64
Q:From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is 19705 25b5cc7d7e4d2b4197775151a
5b5cc7d7e4d2b4197775151a- 181.92Lfalse
- 296Lfalse
- 3118.08Ltrue
- 4None of thesefalse
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Answer : 3. "118.08L"
Explanation :
Answer: C) 118.08L Explanation: The amount of petrol left after 4 operations = 200 × 1-402004 = 200 × 454 = 200 × 256625 = 81.92 litres Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres
Q:A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C which is at midway between A and B. If the velocity of the stream is 4 kmph and the speed of the boat in still water is 14 kmph, what is the distance between A and B ? 4179 15b5cc6e9e4d2b4197774ee41
5b5cc6e9e4d2b4197774ee41- 1180 kmtrue
- 2160 kmfalse
- 3140 kmfalse
- 4120 kmfalse
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Answer : 1. "180 km"
Explanation :
Answer: A) 180 km Explanation: Speed in downstream = (14 + 4) km/hr = 18 km/hr; Speed in upstream = (14 – 4) km/hr = 10 km/hr. Let the distance between A and B be x km. Then, x/18 + (x/2)/10 = 19 ⇔ x/18 + x/20 = 19 ⇒ x = 180 km.
Q:K can build a wall in 30 days. L can demolish that wall in 60 days. If K and L work on alternate days, when will the wall be completed ? 297 15b5cc6f8e4d2b4197774f081
5b5cc6f8e4d2b4197774f081- 1120 daysfalse
- 2119 daysfalse
- 3118 daysfalse
- 4117 daystrue
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Answer : 4. "117 days"
Explanation :
Answer: D) 117 days Explanation: K's work in a day(1st day) = 1/30L's work in a day(2nd day)= -1/60(demolishing)hence in 2 days, combined work= 1/30 - 1/60 =1/60since both works alternatively, K will work in odd days and L will work in even days.1/60 unit work is done in 2 days58/60 unit work will be done in 2 x 58 days = 116 daysRemaining work = 1-58/60 = 1/30Next day, it will be K's turn and K will finish the remaining 1/30 work.hence total days = 116 + 1 = 117.