Quantitative Aptitude Practice Question and Answer
8Q: What was the day of the week on 17th June, 1998 ? 3890 75b5cc761e4d2b4197774fd16
5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse
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Answer : 3. "Wednesday"
Explanation :
Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.
Q: If the true discount on sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ? 4186 55b5cc723e4d2b4197774f6a4
5b5cc723e4d2b4197774f6a4- 1Rs.948false
- 2Rs.876false
- 3Rs.768true
- 4Rs.658false
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Answer : 3. "Rs.768"
Explanation :
Answer: C) Rs.768 Explanation: P.W. = 100×T.DR×T = 100×16814×2 = 600. Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
Q: There are Rs.300 in a box in denomination of Rs.1, 50 paisa and 25 paisa and in the ratio 2:4:8. Find the number of coins of 25 paisa 2967 35d1b179d1fc62311c773687f
5d1b179d1fc62311c773687f- 1300false
- 2200false
- 3400true
- 4100false
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Answer : 3. "400"
Q: A milkman has 20 liters of milk. If he mixes 5 liters of water, which is freely available, in 20 liters of pure milk. If the cost of pure milk is Rs. 18 per litre, then the profit of the milkman, when he sells all the mixture at cost price, is: 2718 35b5cc7d7e4d2b4197775151f
5b5cc7d7e4d2b4197775151f- 120%false
- 225%true
- 333.33%false
- 418%false
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Answer : 2. "25%"
Explanation :
Answer: B) 25% Explanation: When the water is freely available and all the water is sold at the price of the milk, then the water gives the profit on the cost of 20 litres of milk. Since, the profit % = ProfitCostPricex100 Therefore, profit percentage = 520x100 = 25%
Q: A and B together can complete a work in 10 days. A alone can do it in 40 days. In how many days B alone can complete it? 2062 35d14622a249afd05f7b7b405
5d14622a249afd05f7b7b405- 1\({40\over3}\)true
- 210false
- 38false
- 430/7false
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Answer : 1. "\({40\over3}\)"
Q: Ratan can complete a work in \(5 {1 \over 2}\) days while Rupesh can complete it in \(10 {1 \over 2}\) days. In how many days can they both complete it working on it together? 2096 25d147c239aeb0a08f1e67215
5d147c239aeb0a08f1e67215- 1\(3 {39 \over 64 }\)true
- 2\(4 {39 \over 64 }\)false
- 3\(5 {39 \over 64 }\)false
- 4\(6 {39 \over 64 }\)false
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Answer : 1. "\(3 {39 \over 64 }\) "
Q: A machine was sold at 10% Profit had it been sold for Rs 80 less the seller would have incurred 10% loss. What is cost price of Machine? 963 25d132ae909a40f38019e53ab
5d132ae909a40f38019e53ab- 1350false
- 2400true
- 3450false
- 4520false
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Answer : 2. "400"
Q: From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is 25393 25b5cc7d7e4d2b4197775151a
5b5cc7d7e4d2b4197775151a- 181.92Lfalse
- 296Lfalse
- 3118.08Ltrue
- 4None of thesefalse
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Answer : 3. "118.08L"
Explanation :
Answer: C) 118.08L Explanation: The amount of petrol left after 4 operations = 200 × 1-402004 = 200 × 454 = 200 × 256625 = 81.92 litres Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres
