△ABC is right-angle triangle at B and tan A = $$3\over 4$$, then sin A + sin B + sin C will be equal to:
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Q:
△ABC is right-angle triangle at B and tan A = $$3\over 4$$, then sin A + sin B + sin C will be equal to:
- 1$$2{4\over 5}$$false
- 2$$2{2\over 5}$$true
- 3$$3{1\over 5}$$false
- 4$$1{1\over 5}$$false
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