An isosceles triangle ABC is right angled at B.D is a point inside the triangle ABC. P and Q are the feet of the perpendiculars drawn from D on the side AB and AC respectively of ∆ ABC. If AP = a cm, AQ = b cm and ∠BAD = 15°, sin 75°=
5 347 645ce3a019bbd20a9ac5550c
Q:
An isosceles triangle ABC is right angled at B.D is a point inside the triangle ABC. P and Q are the feet of the perpendiculars drawn from D on the side AB and AC respectively of ∆ ABC. If AP = a cm, AQ = b cm and ∠BAD = 15°, sin 75°=
- 1$${2b\over \sqrt {3} a}\ $$false
- 2$${a\over 2b} $$false
- 3$${ \sqrt {3} a\over 2b} $$true
- 4$${ 2b \over \sqrt {3} a} $$false
- Show Answer
- Workspace
- Discuss