**GATE **Practice Question and Answer

8## Q: Mr. Shankar spends 25% of his monthly salary on household expenditure, 20% of the remaining on children’s education, and the remaining is equally invested in three different schemes. If the amount invested in each scheme is Rs.5600, what is the monthly salary of Shankar ? 789 05b5cc74fe4d2b4197774fb30

5b5cc74fe4d2b4197774fb30- 1Rs. 34000false
- 2Rs. 31245false
- 3Rs. 24315false
- 4Rs. 28000true

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## Answer : 4. "Rs. 28000"

Explanation :

Answer: D) Rs. 28000 Explanation: Let the monthly salary of Shankar be = Rs.xAmount invested on expenditure = 25% = x/4;Remaning amount = 3x/4;Amount invested on children education = 20% i.e = 3x/20;Remaining amount = 3x/4 - 3x/20 = 3x/5;Remaining amount invested in three different schemes i.e is 1/3(3x/5) => x/5 = 5600Therefore x = 28000Hence, Monthly salary of Shankar is Rs. 28,000.

## Q: What was the day of the week on 17th June, 1998 ? 2235 65b5cc761e4d2b4197774fd16

5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse

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## Answer : 3. "Wednesday"

Explanation :

Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.

## Q: If the third day of a month is Tuesday, which of the following would be the 4th day before the 27th day of that month? 660 15b5cc7f3e4d2b41977751ed9

5b5cc7f3e4d2b41977751ed9- 1Tuesdayfalse
- 2Mondaytrue
- 3Wednesdayfalse
- 4Sundayfalse

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## Answer : 2. "Monday"

Explanation :

Answer: B) Monday Explanation: Dates on which Tuesday fall are 3,10,17, and 24 Hence, the 27th day of the month will be (Tuesday + 3 days=)Friday Required day of the month = Friday - 4 = Monday

## Q: What should come next in the following number series? 9 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 7 6 5 4 3 2 1 561 05b5cc7f2e4d2b41977751ea7

5b5cc7f2e4d2b41977751ea7- 19false
- 28false
- 37false
- 46true

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## Answer : 4. "6"

Explanation :

Answer: D) 6 Explanation: Here the series is: 987654321, 87654321, 7654321, 65...

## Q: The purest form of iron is 297 05b5cc7efe4d2b41977751d76

5b5cc7efe4d2b41977751d76- 1wrought irontrue
- 2steelfalse
- 3pig ironfalse
- 4nickel steelfalse

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## Answer : 1. "wrought iron"

Explanation :

Answer: A) wrought iron Explanation: Wrought Iron is the purest form of iron. It contains 0.12 to 0.25% carbon and so it is the purest form of iron.

## Q: From a tank of petrol, which contains 200 litres of petrol, the seller replaces each time with kerosene when he sells 40 litres of petrol(or its mixture). Everytime he sells out only 40 litres of petrol(pure or impure). After replacing the petrol with kerosen 4th time, the total amount of kerosene in the mixture is 16925 25b5cc7d7e4d2b4197775151a

5b5cc7d7e4d2b4197775151a- 181.92Lfalse
- 296Lfalse
- 3118.08Ltrue
- 4None of thesefalse

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## Answer : 3. "118.08L"

Explanation :

Answer: C) 118.08L Explanation: The amount of petrol left after 4 operations = 200 × 1-402004 = 200 × 454 = 200 × 256625 = 81.92 litres Hence the amount of kerosene = 200 - 81.92 = 118. 08 litres

## Q: From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was: 3695 15b5cc7d7e4d2b41977751510

5b5cc7d7e4d2b41977751510- 175 litresfalse
- 2100 litresfalse
- 3150 litresfalse
- 4120 litrestrue

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## Answer : 4. "120 litres"

Explanation :

Answer: D) 120 litres Explanation: wine(left)wine(added) = 343169 It means wine(left)wine(initial amount) = 343512 (since 343 + 169 = 512) Thus, 343x = 512x1 - 15k3 343512 = 783 = 1 - 15k3 1-15k=78=1-18 Thus the initial amount of wine was 120 liters.

## Q: 5 men and 4 women are to be seated in a row so that the women occupy the even places . How many such arrangements are possible? 630 15b5cc7d1e4d2b4197775129f

5b5cc7d1e4d2b4197775129f- 12880true
- 21440false
- 3720false
- 42020false

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## Answer : 1. "2880"

Explanation :

Answer: A) 2880 Explanation: There are total 9 places out of which 4 are even and rest 5 places are odd. 4 women can be arranged at 4 even places in 4! ways. and 5 men can be placed in remaining 5 places in 5! ways. Hence, the required number of permutations = 4! x 5! = 24 x 120 = 2880