Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.

Answer: C) Rs.768 Explanation: P.W. = 100×T.DR×T = 100×16814×2 = 600. Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.

Answer: B) 44 Explanation: No. of boys up to the 34th rank = 34-18 = 16    Total no of boys = 180x1/2+1 = 60    number of boys after the rank of Rupesh = 60 - 16 = 44

Answer: A) 22 Explanation: M is 8th from the top.   H is (50 - 20 + 1 =) 31 st from the top.   Number of students between M and H = (31 - 8- 1=)22

Answer: B) 16 Explanation: W = 10th from the left   R = 4th from the right = (30 - 4 + 1= ) 27th from left    No of boys between R and W = (27 - 10) - 1 = 16

Answer: C) 28 Explanation: Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.   We may consider the two cases as under: Case I:  ←3C↔8B↔5A→21   Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40   Case II:  ←3C A↔5B   Number of persons between A and C                     = (8 - 6) = 2    ∵[C↔8B A→21B]   Clearly number of persons in the queue = (3+1+2+1+21) = 28   Now, 28 < 40. So, 28 is the minimum number of persons in the queue.

Answer: D) 6 Explanation: Here the series is:   987654321, 87654321, 7654321, 65...

Answer: C) 4 Explanation: We have to find out even number - even number - odd number sequence.  8 5 8 6 7 6 8 9 3 2 7 5 3 4 2 2 3 5 5 2 2 8 1 1 9 3 1 7 5 1  There are four such such even numbers: 6,8,2 and 8.