IIT JEE Practice Question and Answer

Q: Mr. Shankar spends 25% of his monthly salary on household expenditure, 20% of the remaining on children’s education, and the remaining is equally invested in three different schemes. If the amount invested in each scheme is Rs.5600, what is the monthly salary of Shankar ? 760 0

  • 1
    Rs. 34000
    Correct
    Incorrect
  • 2
    Rs. 31245
    Correct
    Incorrect
  • 3
    Rs. 24315
    Correct
    Incorrect
  • 4
    Rs. 28000
    Correct
    Incorrect
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Answer : 4. "Rs. 28000"
Explanation :

Answer: D) Rs. 28000 Explanation: Let the monthly salary of Shankar be = Rs.xAmount invested on expenditure = 25% = x/4;Remaning amount = 3x/4;Amount invested on children education = 20% i.e = 3x/20;Remaining amount = 3x/4 - 3x/20 = 3x/5;Remaining amount invested in three different schemes i.e is 1/3(3x/5) => x/5 = 5600Therefore x = 28000Hence, Monthly salary of Shankar is Rs. 28,000.

Q: What was the day of the week on 17th June, 1998 ? 2227 6

  • 1
    Monday
    Correct
    Incorrect
  • 2
    Tuesday
    Correct
    Incorrect
  • 3
    Wednesday
    Correct
    Incorrect
  • 4
    Friday
    Correct
    Incorrect
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Answer : 3. "Wednesday"
Explanation :

Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.

Q: If the true discount on sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ? 3071 4

  • 1
    Rs.948
    Correct
    Incorrect
  • 2
    Rs.876
    Correct
    Incorrect
  • 3
    Rs.768
    Correct
    Incorrect
  • 4
    Rs.658
    Correct
    Incorrect
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Answer : 3. "Rs.768"
Explanation :

Answer: C) Rs.768 Explanation: P.W. = 100×T.DR×T = 100×16814×2 = 600. Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.

Q: In a class of 180, where girls are twice the number of boys, Rupesh[a boy]  ranked 34th from the top. If there are 18 girls ahead of Rupesh, how many boys are after him in rank? 910 0

  • 1
    45
    Correct
    Incorrect
  • 2
    44
    Correct
    Incorrect
  • 3
    60
    Correct
    Incorrect
  • 4
    can't be determined
    Correct
    Incorrect
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Answer : 2. "44"
Explanation :

Answer: B) 44 Explanation: No. of boys up to the 34th rank = 34-18 = 16    Total no of boys = 180x1/2+1 = 60    number of boys after the rank of Rupesh = 60 - 16 = 44

Q: In a class of 50 students M is eighth from top. H is 20th from bottom. How many students are there between M and H? 618 0

  • 1
    22
    Correct
    Incorrect
  • 2
    23
    Correct
    Incorrect
  • 3
    24
    Correct
    Incorrect
  • 4
    can't be determined
    Correct
    Incorrect
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Answer : 1. "22"
Explanation :

Answer: A) 22 Explanation: M is 8th from the top.   H is (50 - 20 + 1 =) 31 st from the top.   Number of students between M and H = (31 - 8- 1=)22

Q: In a row of thirty boys, R is fourth from the right end and W is tenth from the left end . How many boys are there between R and W? 609 0

  • 1
    15
    Correct
    Incorrect
  • 2
    16
    Correct
    Incorrect
  • 3
    17
    Correct
    Incorrect
  • 4
    can't be determined
    Correct
    Incorrect
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Answer : 2. "16"
Explanation :

Answer: B) 16 Explanation: W = 10th from the left   R = 4th from the right = (30 - 4 + 1= ) 27th from left    No of boys between R and W = (27 - 10) - 1 = 16

Q: Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue? 742 0

  • 1
    41
    Correct
    Incorrect
  • 2
    40
    Correct
    Incorrect
  • 3
    28
    Correct
    Incorrect
  • 4
    27
    Correct
    Incorrect
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Answer : 3. "28"
Explanation :

Answer: C) 28 Explanation: Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB.   We may consider the two cases as under: Case I:  ←3C↔8B↔5A→21   Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40   Case II:  ←3C A↔5B   Number of persons between A and C                     = (8 - 6) = 2    ∵[C↔8B A→21B]   Clearly number of persons in the queue = (3+1+2+1+21) = 28   Now, 28 < 40. So, 28 is the minimum number of persons in the queue.

Q: What should come next in the following number series? 9 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 7 6 5 4 3 2 1 551 0

  • 1
    9
    Correct
    Incorrect
  • 2
    8
    Correct
    Incorrect
  • 3
    7
    Correct
    Incorrect
  • 4
    6
    Correct
    Incorrect
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Answer : 4. "6"
Explanation :

Answer: D) 6 Explanation: Here the series is:   987654321, 87654321, 7654321, 65...

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