IIT JEE Practice Question and Answer
8Q: Mr. Shankar spends 25% of his monthly salary on household expenditure, 20% of the remaining on children’s education, and the remaining is equally invested in three different schemes. If the amount invested in each scheme is Rs.5600, what is the monthly salary of Shankar ? 850 05b5cc74fe4d2b4197774fb30
5b5cc74fe4d2b4197774fb30- 1Rs. 34000false
- 2Rs. 31245false
- 3Rs. 24315false
- 4Rs. 28000true
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 4. "Rs. 28000"
Explanation :
Answer: D) Rs. 28000 Explanation: Let the monthly salary of Shankar be = Rs.xAmount invested on expenditure = 25% = x/4;Remaning amount = 3x/4;Amount invested on children education = 20% i.e = 3x/20;Remaining amount = 3x/4 - 3x/20 = 3x/5;Remaining amount invested in three different schemes i.e is 1/3(3x/5) => x/5 = 5600Therefore x = 28000Hence, Monthly salary of Shankar is Rs. 28,000.
Q: What was the day of the week on 17th June, 1998 ? 2285 65b5cc761e4d2b4197774fd16
5b5cc761e4d2b4197774fd16- 1Mondayfalse
- 2Tuesdayfalse
- 3Wednesdaytrue
- 4Fridayfalse
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 3. "Wednesday"
Explanation :
Answer: C) Wednesday Explanation: 17th June, 1998 = (1997 years + Period from 1.1.1998 to 17.6.1998)Odd days in 1600 years = 0Odd days in 300 years = 197 years has 24 leap years + 73 ordinary years.Number of odd days in 97 years ( 24 x 2 + 73) = 121 = 2 odd days.Jan. Feb. March. April. May. June.(31 + 28 + 31 + 30 + 31 + 17) = 168 days168 days = 24 weeks = 0 odd day.Total number of odd days = (0 + 1 + 2 + 0) = 3.Given day is Wednesday.
Q: If the true discount on sum due 2 years hence at 14% per annum be Rs. 168, the sum due is ? 3102 45b5cc723e4d2b4197774f6a4
5b5cc723e4d2b4197774f6a4- 1Rs.948false
- 2Rs.876false
- 3Rs.768true
- 4Rs.658false
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 3. "Rs.768"
Explanation :
Answer: C) Rs.768 Explanation: P.W. = 100×T.DR×T = 100×16814×2 = 600. Sum = (P.W. + T.D.) = Rs. (600 + 168) = Rs. 768.
Q: In a class of 180, where girls are twice the number of boys, Rupesh[a boy] ranked 34th from the top. If there are 18 girls ahead of Rupesh, how many boys are after him in rank? 935 05b5cc7f3e4d2b41977751ec0
5b5cc7f3e4d2b41977751ec0- 145false
- 244true
- 360false
- 4can't be determinedfalse
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 2. "44"
Explanation :
Answer: B) 44 Explanation: No. of boys up to the 34th rank = 34-18 = 16 Total no of boys = 180x1/2+1 = 60 number of boys after the rank of Rupesh = 60 - 16 = 44
Q: In a class of 50 students M is eighth from top. H is 20th from bottom. How many students are there between M and H? 644 05b5cc7f3e4d2b41977751ebb
5b5cc7f3e4d2b41977751ebb- 122true
- 223false
- 324false
- 4can't be determinedfalse
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 1. "22"
Explanation :
Answer: A) 22 Explanation: M is 8th from the top. H is (50 - 20 + 1 =) 31 st from the top. Number of students between M and H = (31 - 8- 1=)22
Q: In a row of thirty boys, R is fourth from the right end and W is tenth from the left end . How many boys are there between R and W? 633 05b5cc7f3e4d2b41977751eb6
5b5cc7f3e4d2b41977751eb6- 115false
- 216true
- 317false
- 4can't be determinedfalse
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 2. "16"
Explanation :
Answer: B) 16 Explanation: W = 10th from the left R = 4th from the right = (30 - 4 + 1= ) 27th from left No of boys between R and W = (27 - 10) - 1 = 16
Q: Three persons A, B and C are standing in a queue. There are five persons between A and B and eight persons between B and C. If there be three persons ahead of C and 21 persons behind A, what could be the minimum number of persons in the queue? 774 05b5cc7f2e4d2b41977751eac
5b5cc7f2e4d2b41977751eac- 141false
- 240false
- 328true
- 427false
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 3. "28"
Explanation :
Answer: C) 28 Explanation: Three persons A, B, C can be arranged in a queue in six different ways, ie ABC, CBA, BAC, CAB, BCA, ACB. But since there are only 3 persons ahead of C, so C should be in front of the queue. Thus, there are only two possible arrangements, ie CBA and CAB. We may consider the two cases as under: Case I: ←3C↔8B↔5A→21 Clearly, number of persons in the queue = (3+1+8+1+5+1+21=) 40 Case II: ←3C A↔5B Number of persons between A and C = (8 - 6) = 2 ∵[C↔8B A→21B] Clearly number of persons in the queue = (3+1+2+1+21) = 28 Now, 28 < 40. So, 28 is the minimum number of persons in the queue.
Q: What should come next in the following number series? 9 8 7 6 5 4 3 2 1 8 7 6 5 4 3 2 1 7 6 5 4 3 2 1 592 05b5cc7f2e4d2b41977751ea7
5b5cc7f2e4d2b41977751ea7- 19false
- 28false
- 37false
- 46true
- Show Answer
- Workspace
- Discuss
- SingleChoice
Answer : 4. "6"
Explanation :
Answer: D) 6 Explanation: Here the series is: 987654321, 87654321, 7654321, 65...