Algebra Practice Question and Answer

Q:

Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 21x² + 10x + 1 = 0
 (ii) 24y²+ 26y + 5 = 0

212 0

  • 1
    x ≤ y
    Correct
    Wrong
  • 2
    x ≥ y
    Correct
    Wrong
  • 3
    x > y
    Correct
    Wrong
  • 4
    x < y
    Correct
    Wrong
  • 5
    x = y or no relation can be established between x & y.
    Correct
    Wrong
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Answer : 5. "x = y or no relation can be established between x & y."

Q:

Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 12x² + 11x + 2 = 0
(ii) 12y²+ 7y + 1 = 0

219 0

  • 1
    x ≥ y
    Correct
    Wrong
  • 2
    x > y
    Correct
    Wrong
  • 3
    x < y
    Correct
    Wrong
  • 4
    x ≤ y
    Correct
    Wrong
  • 5
    x = y or no relation can be established between x & y.
    Correct
    Wrong
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Answer : 5. "x = y or no relation can be established between x & y."

Q:

Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 3x² + 11x + 10 = 0
 (ii) 2y² + 11y + 14 = 0

211 0

  • 1
    x ≥ y
    Correct
    Wrong
  • 2
    x ≤ y
    Correct
    Wrong
  • 3
    x > y
    Correct
    Wrong
  • 4
    x < y
    Correct
    Wrong
  • 5
    x = y or no relation can be established between x & y.
    Correct
    Wrong
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Answer : 1. "x ≥ y"

Q:

Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 6x² – 11x + 4 = 0
 (ii) 3y² – 5y + 2 = 0

186 0

  • 1
    x ≤ y
    Correct
    Wrong
  • 2
    x < y
    Correct
    Wrong
  • 3
    x ≥ y
    Correct
    Wrong
  • 4
    x > y
    Correct
    Wrong
  • 5
    x = y or no relation can be established between x & y.
    Correct
    Wrong
  • Show AnswerHide Answer
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Answer : 5. "x = y or no relation can be established between x & y."

Q:

Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 2x³ = $$ \sqrt {256}$$
 (ii) 2y² – 9y + 10 = 0

200 0

  • 1
    x > y
    Correct
    Wrong
  • 2
    x < y
    Correct
    Wrong
  • 3
    x ≤ y
    Correct
    Wrong
  • 4
    x ≥ y
    Correct
    Wrong
  • 5
    x = y or no relation can be established between x & y.
    Correct
    Wrong
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Answer : 3. "x ≤ y"

Q:

Directions: In each of these questions, two equations (i) and (ii) are given, you have to solve both the equations and give answer accordingly.

(i) 2x² + 9x + 9 = 0
 (ii) 15y² + 16y + 4 = 0

183 0

  • 1
    x > y
    Correct
    Wrong
  • 2
    x < y
    Correct
    Wrong
  • 3
    x ≥ y
    Correct
    Wrong
  • 4
    x ≤ y
    Correct
    Wrong
  • 5
    x = y or no relation can be established between x & y.
    Correct
    Wrong
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Answer : 2. "x < y "

Q:

If x2+4y2=17 and xy=2, where x>0,y>0, then what is the value of x3+8y3?

263 0

  • 1
    95
    Correct
    Wrong
  • 2
    85
    Correct
    Wrong
  • 3
    65
    Correct
    Wrong
  • 4
    76
    Correct
    Wrong
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Answer : 3. "65"

Q:

if a+b+c=7 and a3+b3+c3-3abc=175, then what is the value of (ab+bc+ca)?

260 0

  • 1
    8
    Correct
    Wrong
  • 2
    9
    Correct
    Wrong
  • 3
    7
    Correct
    Wrong
  • 4
    6
    Correct
    Wrong
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Answer : 1. "8"

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