Aptitude Questions Practice Question and Answer
6Q: 270 metre long train running at 10 km/hrs crosses another train running at 80 km/hrs. in 20 seconds Trains are running in opposite direction. Length of seconds train? 2009 05d15e01044a3a75f13296b30
5d15e01044a3a75f13296b30- 1240 metrefalse
- 2320 metrefalse
- 3260 metrefalse
- 4230 metretrue
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Answer : 4. "230 metre"
Q: Find value of log27 +log 8 +log1000log 120 1964 15b5cc7d0e4d2b4197775120e
5b5cc7d0e4d2b4197775120e- 11/2false
- 23/2true
- 32false
- 42/3false
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Answer : 2. "3/2"
Explanation :
Answer: B) 3/2 Explanation: = log 33 + log 23+ log 103log10×3×22 =log33 12+log 23+log 10312log(10×3×22) =12log 33+3 log 2+12 log103log10+log3+log22 =32log 3 + 2 log 2 + log 10log 3 + 2 log 2 + log 10 = 32
Q: A sum of money becomes $${7\over6}$$ of itself in 3 years at a certain rate of simple interest. The rate of interest per annum is: 1954 15cfdf50598d53c6bd3f9d354
5cfdf50598d53c6bd3f9d354- 1$$5{5\over9}\%$$true
- 2$$6{5\over9}\%$$false
- 318%false
- 425%false
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Answer : 1. "$$5{5\over9}\%$$"
Q: The Value of logtan10+logtan20+⋯⋯+logtan890 is 1831 15b5cc7d0e4d2b41977751204
5b5cc7d0e4d2b41977751204- 1-1false
- 20true
- 31/2false
- 41false
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Answer : 2. "0"
Explanation :
Answer: B) 0 Explanation: = log tan10+log tan890 + log tan20+ log tan880+⋯⋯+log tan450 = log [tan10 × tan890] + log [tan20 × tan880 ] +⋯⋯+log1 ∵ tan(90-θ)=cotθ and tan 450=1 = log 1 + log 1 +.....+log 1 = 0.
Q: A 400-metre-long train is running at the speed of 60 km/hour. A man is running in the opposite direction of train at the speed of 12 km/hour. In how much time the train will cross this man? 1810 15d15fbab44a3a75f13296b82
5d15fbab44a3a75f13296b82- 150 secondfalse
- 230 secondfalse
- 320 secondtrue
- 440 secondfalse
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Answer : 3. "20 second"
Q: A flagstaff 17.5 m high casts a shadow of length 40.25 m. What will be the height of a building, which casts a shadow of length 28.75 m under similar conditions ? 1689 15b5cc6f4e4d2b4197774f013
5b5cc6f4e4d2b4197774f013- 114 cmfalse
- 213.5 cmfalse
- 312.5 cmtrue
- 411.4 cmfalse
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Answer : 3. "12.5 cm"
Explanation :
Answer: C) 12.5 cm Explanation: Let the required height of the building be x meter More shadow length, More height(direct proportion) Hence we can write as (shadow length) 40.25 : 28.75 :: 17.5 : x⇒ 40.25 × x = 28.75 × 17.5⇒ x = 28.75 × 17.5/40.25= 2875 × 175/40250= 2875 × 7/1610= 2875/230= 575/46= 12.5 cm