CAT Practice Question and Answer
8Q: GNLF stands for 2625 05b5cc69ee4d2b4197774c990
5b5cc69ee4d2b4197774c990- 1Gorkha National Liberation Fronttrue
- 2Gross National Liberation Formfalse
- 3Both option A and Bfalse
- 4None of the abovefalse
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Answer : 1. "Gorkha National Liberation Front"
Explanation :
Answer: A) Gorkha National Liberation Front Explanation: GNLF stands for Gorkha National Liberation Front. Gorkha National Liberation Front (GNLF) is a political party in the Darjeeling District of West Bengal, India. It was formed in 1980 by Subhash Ghisingh with the objective of demanding a Gorkhaland state within India.
Q: How many meaningful English words can be formed with the letters A, L, W using each letter only once in each word ? 2623 05b5cc6cbe4d2b4197774e0db
5b5cc6cbe4d2b4197774e0db- 11true
- 22false
- 33false
- 44false
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Answer : 1. "1"
Explanation :
Answer: A) 1 Explanation: Using the letters A, L, W only one meaningful English word can be formed i.e, LAW No other words can be formed.
Q: Find the Odd One Out? 4, 6, 12, 30, 81, 315. 2621 05b5cc6aae4d2b4197774cf56
5b5cc6aae4d2b4197774cf56- 16false
- 212false
- 381true
- 4315false
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Answer : 3. "81"
Explanation :
Answer: C) 81 Explanation: Given the number series is 4, 6, 12, 30, 81, 315. Here it follows a pattern that 4 4 x 1.5 = 6 6 x 2 = 12 12 x 2.5 = 30 30 x 3 = 90 not equals to 81 90 x 3.5 = 315 Hence the odd one in the series is 81.
Q: Malleability and Ductility of metals can be accounted due to 2621 05b5cc670e4d2b4197774c052
5b5cc670e4d2b4197774c052- 1the crystalline structure in metalfalse
- 2the interaction of electrons with metal ions in the latticefalse
- 3the presence of electrostatic forcefalse
- 4the capacity of layers of metal ions to slide over the othertrue
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Answer : 4. "the capacity of layers of metal ions to slide over the other"
Explanation :
Answer: D) the capacity of layers of metal ions to slide over the other Explanation:
Q: Karthik read 613 th of a book in 1st week and 59 th of the remaining book in 2nd week. If there were 100 pages unread after 2nd week, how many pages were there in the book ? 2619 05b5cc76fe4d2b4197774ff76
5b5cc76fe4d2b4197774ff76- 1404false
- 2415false
- 3418true
- 4420false
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Answer : 3. "418"
Explanation :
Answer: C) 418 Explanation: Let the total book be 1 Then, in the 1st week 613th of book is read i.e remaining pages = 1-613=713 in 2nd week he read 59th of it i.e 59×713=35117Remaining pages after 2nd week = 713-35117=28117 But given remaining pages after 2nd week = 100 28x117=100 --> x = 418 The total pages in the book are 418
Q: A F Z U G L T _ Find the next letter in the above given letter series? 2617 05b5cc64de4d2b4197774bc5c
5b5cc64de4d2b4197774bc5c- 1Kfalse
- 2Mfalse
- 3Otrue
- 4Qfalse
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Answer : 3. "O"
Explanation :
Answer: C) O Explanation: Given series is A F Z U G L T _ Starts with A A + 5 letters = F go to end of alphabet= Z Z - 5 letters = U from F go one more to G + 5 letters = L from U go one back to U, T - 5 letters = O Second Method :: Change the letters to their corresponding number. A=1 B=2 C=3 ... Z=26 A F Z U G L T _ 1 6 26 21 7 12 20 ? Look at the pattern: the 1st and 3rd numbers = 27, 1+26 the 2nd and 4th numbers = 27, 6+21 the 5th and 7th numbers = 27, so the 6 and 8th would also equal 27. 27 - 12 = 15, so the letter is O.
Q: Statements :- All kids are God. No God is a Human. Some Human are Son. All Son are Men. Conclusions :- (a) Some Son are not God. (b) Some Men are Human. 2617 05b5cc6c8e4d2b4197774defb
5b5cc6c8e4d2b4197774defb- 1Only A followsfalse
- 2Only B followsfalse
- 3Both (A) and (B) followstrue
- 4A) and (B) follows D)false
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Answer : 3. "Both (A) and (B) follows"
Explanation :
Answer: C) Both (A) and (B) follows Explanation:
Q: A man could buy a certain number of notebooks for Rs.300. If each notebook cost is Rs.5 more, he could have bought 10 notebooks less for the same amount. Find the price of each notebook ? 2616 05b5cc6dde4d2b4197774ea28
5b5cc6dde4d2b4197774ea28- 115false
- 220false
- 310true
- 48false
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Answer : 3. "10"
Explanation :
Answer: C) 10 Explanation: Let the price of each note book be Rs.x. Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y. Hence xy = 300 => y = 300/x (x + 5)(y - 10) = 300 => xy + 5y - 10x - 50 = xy =>5(300/x) - 10x - 50 = 0 => -150+x2+5x multiplying both sides by -1/10x => x2+15x-10x-150=0 => x(x + 15) - 10(x + 15) = 0 => x = 10 or -15 As x>0, x = 10.

