CAT Practice Question and Answer
8Q: If a Siren sounds for every 5 seconds, how many times will it sound in ¾ of an hour? 2839 05b5cc76ae4d2b4197774fea3
5b5cc76ae4d2b4197774fea3- 1541 timestrue
- 2540 timesfalse
- 3450 timesfalse
- 4275 timesfalse
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Answer : 1. "541 times"
Explanation :
Answer: A) 541 times Explanation: There are 60 minutes in an hour. In ¾ of an hour there are (60 × ¾) minutes = 45 minutes. In ¾ of an hour there are (60 × 45) seconds = 2700 seconds. Siren sounds for every 5 seconds. In 2700 seconds = 2700/5 = 540 times. The count start after the first sound, the Siren will sound 541 times in ¾ of an hour.
Q: Find the odd one out? 6, 3, 3, 4.5, 10 2837 05b5cc698e4d2b4197774c670
5b5cc698e4d2b4197774c670- 13false
- 24.5false
- 36false
- 410true
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Answer : 4. "10"
Explanation :
Answer: D) 10 Explanation: Here the given number series is 6, 3, 3, 4.5, 10 The odd one in the given series is 10 The pattern it follows is 6 6 x 0.5 = 3 3 x 1 = 3 3 x 1.5 = 4.5 4.5 x 2 = 9 Hence, the odd number is 10.
Q: Rushi and Arun are two business partners. They invest their capital in the ratio 7 : 9. After 6 months, a third person Ram joins them with a capital of two third of that of Arun. After a year, profit share of Rushi was Rs. 5600, then find total profit? 2835 05b5cc619e4d2b4197774b70f
5b5cc619e4d2b4197774b70f- 126,250false
- 219,200false
- 318,650,false
- 415,200true
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Answer : 4. "15,200"
Explanation :
Answer: D) 15,200 Explanation: Ratio of investment of all the three members = (7 x 12) : (9 x 12) : (2/3 x 9 x 6) = 7 : 9 : 3 Given Rushi's one year profit = Rs. 5600 => Let the total profit = Rs. P Then, P x 7/19 = 5600 Total profit P = 19 x 5600/7 = Rs. 15,200.
Q: In how many ways word of 'GLACIOUS' can be arranged such that 'C' always comes at end? 2834 05b5cc626e4d2b4197774b825
5b5cc626e4d2b4197774b825- 13360false
- 25040true
- 3720false
- 41080false
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Answer : 2. "5040"
Explanation :
Answer: B) 5040 Explanation: Given word is GLACIOUS has 8 letters. => C is fixed in one of the 8 places Then, the remaining 7 letters can be arranged in 7! ways = 5040.
Q: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 2833 05b5cc6bfe4d2b4197774da0a
5b5cc6bfe4d2b4197774da0a- 11/3false
- 22/3false
- 31/6true
- 45/6false
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Answer : 3. "1/6"
Explanation :
Answer: C) 1/6 Explanation: Given X can do in 10 days => 1 day work of X = 1/10 Y can do in 15 days => 1 day work of Y = 1/15 1day work of (X + Y) = 1/10 + 1/15 = 1/6 Given they are hired for 5 days => 5 days work of (X + Y) = 5 x 1/6 = 5/6 Therefore, Unfinished work = 1 - 5/6 = 1/6
Q: An intelligent boy is doing a jigsaw with 275 pieces. Each day that he fits pieces together there are fewer pieces left, and it is reasonable to assume that he fits more pieces each day because the number left to sort out diminishes progressively. Hence he is able to fit an extra piece as each day goes by. On the first day he fits 20 pieces. How many days does it take for him to complete the puzzle ? 2833 05b5cc71ee4d2b4197774f59a
5b5cc71ee4d2b4197774f59a- 111 daystrue
- 215 daysfalse
- 313 daysfalse
- 416 daysfalse
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Answer : 1. "11 days"
Explanation :
Answer: A) 11 days Explanation: Let 'n' number of days it take to complete. we know that sum of n number= n/2[2a+(n-1)d]where a=20,d=1;n/2[2x20+(n-1)1]=275n[n+39]=550n2 + 39n - 550 = 0 n2+ 50n - 11n - 550 = 0(n-11) (n-50) = 0n-11 = 0;n = 11(Days).
Q: 12 year old Manish is three times as old as his brother Rajeev. How old will Manish be when he is twice as old as Rajeev ? 2832 05b5cc720e4d2b4197774f5f4
5b5cc720e4d2b4197774f5f4- 112 yrsfalse
- 214 yrsfalse
- 316 yrstrue
- 418 yrsfalse
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Answer : 3. "16 yrs"
Explanation :
Answer: C) 16 yrs Explanation: 12 year old Manish is three times as old as his brother Rajeev who must be 4 years old.Diff in ages = 8 years.when Rajeev will become 8 years old, Manish will be 16 yrs old and he will be twice as old as Rajeev.
Q: A box contains 5 green, 4 yellow and 5 white pearls. Four pearls are drawn at random. What is the probability that they are not of the same colour ? 2831 05b5cc774e4d2b4197775001b
5b5cc774e4d2b4197775001b- 111/91false
- 24/11false
- 31/11false
- 490/91true
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Answer : 4. "90/91"
Explanation :
Answer: D) Option D Explanation: Let S be the sample space. Then,n(s) = number of ways of drawing 4 pearls out of 14 = C414 ways = 14×13×12×114×3×2×1= 1001 Let E be the event of drawing 4 pearls of the same colour.Then, E = event of drawing (4 pearls out of 5) or (4 pearls out of 4) or (4 pearls out of 5) ⇒C15+ C44+ C15 = 5+1+5 =11 P(E) = n(E)n(S)=111001=191 Required probability = 1-191=9091