Answer: C) Mumbai Explanation: The National Basketball Association (NBA) announced the launch of NBA Basketball School, a network of tuition-based basketball development programs around the world open to international male and female players ages 6-18 in Mumbai.

Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt.   Maximum number of unsuccessful attempts = 216 - 1 = 215.

Answer: B) 20 min Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.

Answer: C) 50 l Explanation: Let the tin contain 5x litres of liquids 5x - 45 x 455x - 45 x 15 + 45 = 25 => 5(4x - 36) = 2(x + 36) => 20x - 180 = 2x + 72 => x = 14 litres Hence, the initial quantity of mixture = 70l Quantity of liquid B = 70 - 45 x 15 + 45  = 50 litres.

Answer: A) B.K. Dutt Explanation: Bhagat Singh and B.K. Dutt threw bombs in the Legislative Assembly as a protest against "Passage of public Safety bill".

Answer: D) 3-Bromo-1-chlorocyclohex-1-ene Explanation: In chemical nomenclature, the IUPAC nomenclature of organic chemistry is a systematic method of naming organic chemical compounds as recommended by the International Union of Pure and Applied Chemistry (IUPAC).

From the assumption and trial and error method, last three digits sum must leave the same digit as the answer. It is possible only if the answer must be units digit number leaving tens digit as carry. And the possible 3rd digit is 5. Since 5 + 5 + 5 = 15  Now, 2nd step is  1 + x + x + x = 5 => 3x = 4 It is possible with x = 8. 8 + 8 + 8 + 1 = 25 leaving 2 as carry.  Now, 3rd step is 2 + x + x + x = 5 => x = 1   Hence, the three dgits are 1, 8, 5. 185 + 185 + 185 = 555.

Answer: B) Rs. 1,44,000 Explanation: Value of Maruti Van, V1 = Rs. 1,96,000Rate of depreciation, r = 14(2/7)% = 100/7%; Time, t = 2 yearsLet V2 is the value after depreciation. V2 = V11 - r100tV2 = 196001 - 10071002 V2 = 196000(6/7)(6/7) V2 = (196000x36)/49 = Rs. 1,44,000.