Answer: A) Air Explanation: Light travels fastest in Vacuum. The fastest thing in the whole universe is the speed of light in a vacuum like outer space. It is about 2.99 x 108 m/s.

Answer: C) Option C Explanation: Raghu can complete the work in (12 x 9)hrs = 108 hrs.    Arun can complete the work in (8 x 11)hrs = 88 hrs.   Raghu's 1 hrs work = 1/108 and Arun's 1 hrs work = 1/88   (Raghu + Arun)'s 1 hrs work = 1108+188=492376  So, both Raghu and Arun will finish the work in 237649 hrs Number of days of 12 hours each=237649×112 = 19849=4349 days

Answer: A) Aurora australis Explanation: Polar lights (aurora polaris) are a natural phenomenon found in both the northern and southern hemispheres that can be truly awe inspiring. Northern lights are also called by their scientific name, aurora borealis, and Southern lights are called aurora australis.

Answer: B) 138 Explanation: The gram formula mass of a compound is nothing but the molar mass. The molar mass of K2CO3 (Potassium Carbonate) is given by Atomic weights of individual elements are   K (Potassium) = 39 g C (Carbon) = 12 g O (Oxygen) = 16 g   Hence, that of K2CO3 = 39(2) + 12 + 16(3) = 78 + 12 + 48 = 138.

Answer: D) 120 Explanation: In given word OLIVER there are 3 vowels E, I & O. These can be arranged in only one way as dictionary order E, I & O.   There are 6 letters in thegiven word.   First arrange 3 vowels.   This can be done in 6C3 ways and that too in only one way.(dictionary order E, I & O)   Remaining 3 letters can be placed in 3 places = 3! ways   Total number of possible ways of arranging letters of OLIVER = 3! x C36 ways = 6x5x4 = 120 ways.

Answer: B) Rs. 6540 Explanation: Given C.I = 5984, R = 20% , T = 2yrs  C.I = P1+201002-1   5984 =    => P = (5995x25)/11   P = Rs. 13625   Now S.I = PTR/100   SI = (13625 x 8 x 6)/100 = Rs. 6540

Answer: B) Brother Explanation: Brother Justification: Daughter of uncle's father -- Uncle's sister -- Mother; Mother's son -- Brother.

Answer: A) 1, 5 – hexadiene Explanation: 3 – Hexanol: There is no alcohol stretch present in the spectrum. Therefore, the above structure is not suitable for the given spectrum.   Trans – 4 – octene: There is no vinyl bending present in the spectrum. Therefore, the above structure is not suitable for the given spectrum. 1, 5 – hexadiene: The vinyl bending and other stretches were matched with the above structure.     Hence, the c = c stretch, vinyl bending and stretch were matched with the above structure. Therefore, the given spectrum belongs to 1, 5 – hexadiene.