CAT Practice Question and Answer
8Q: Which Indian airport has become the busiest single-runway airport in the world with 1 flight in 65 seconds ? 1559 05b5cc6dfe4d2b4197774eb07
5b5cc6dfe4d2b4197774eb07- 1Chennai International Airportfalse
- 2Chhatrapati Shivaji International Airporttrue
- 3Indira Gandhi International Airportfalse
- 4Kempegowda International Airportfalse
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Answer : 2. "Chhatrapati Shivaji International Airport"
Explanation :
Answer: B) Chhatrapati Shivaji International Airport Explanation: The GVK group-run Mumbai airport has become the world’s busiest amongst the single-runway facilities by handling 837 flights a day or one in 65 seconds on an average in fiscal 2017.
Q: What is the sum of all 3 digits number that can be formed using digits 0,1,2,3,4,5 with no repitition ? 1559 05b5cc709e4d2b4197774f2a3
5b5cc709e4d2b4197774f2a3- 128450false
- 226340false
- 332640true
- 436450false
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Answer : 3. "32640"
Explanation :
Answer: C) 32640 Explanation: We know that zero can't be in hundreds place. But let's assume that our number could start with zero. The formula to find sum of all numbers in a permutation is 111 x no of ways numbers can be formed for a number at given position x sum of all given digits No of 1 s depends on number of digits So,the answer us 111 x 20 x (0+1+2+3+4+5) = 33300 We got 20 as follows. If we have 0 in units place we can form a number in 4*5 ways. This is for all numbers. So we have substituted 20 in formula. Now, this is not the final answer because we have included 0 in hundreds place. so we have to remove the sum of all numbers that starts with 0. This is nothing but the sum of all 2 digits numbers formed by 1 2 3 4 5. Because 0 at first place makes it a 2 digit number. So the sum for this is 11 x 4 x (1+2+3+4+5). =660 Hope u understood why we use 4. Each number can be formed in 4x1 ways So, the final answer is 33300-660 = 32640
Q: Find the sum to 200 terms of the series 2 + 5 + 7 + 6 + 12 + 7 + .... 1559 05b5cc754e4d2b4197774fb9f
5b5cc754e4d2b4197774fb9f- 130,400true
- 230,200false
- 334,600false
- 438,400false
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Answer : 1. "30,400"
Explanation :
Answer: A) 30,400 Explanation: we can treat every two consecutive terms as one.So, we will have a total of 100 terms of the nature:(2 + 5) + (7 + 6) + (12 + 7).... => 7, 13, 19,.... We know the sum of n terms nn+12 Now, a= 7, d=6 and n=100Hence the sum of the given series is S= 100/2 x[2 x 7 + 99 x 6]=> 50[608]=> 30,400.
Q: The basic unit of the nervous system is the 1557 05b5cc6a6e4d2b4197774cdbb
5b5cc6a6e4d2b4197774cdbb- 1Lymphsfalse
- 2Nephronsfalse
- 3Nervesfalse
- 4Neuronstrue
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Answer : 4. "Neurons"
Explanation :
Answer: D) Neurons Explanation: The basic unit of the nervous system is the Neurons. The neuron is a single nerve cell, and you have billions of them. There are three basic types of neurons:: 1. Association, 2. Afferent and 3. Efferent. The association neurons comprise the central nervous system (CNS) that is the brain and spinal cord. The afferent neurons are also known as the sensory neurons, they bring the stimuli from the sensors (e.g., skin, eyes, ears) to the CNS. The efferent neurons are also known as motor neurons, they bring the responses from the brain to the muscles and the glands.
Q: What organelle allows some protists to detect light? 1557 05b5cc68be4d2b4197774c37a
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Answer :
Explanation :
An organelle called Eyespot allows some protists to detect light. It allows the cells to sense light direction and intensity and respond to it by swimming either towards the light (positive phototaxis) or away from the light (negative phototaxis). Eyespot is a photoreceptive organelle found in the flagellate or (motile) cells of green algae and other unicellular photosynthetic organisms such as euglenids. Eyespot-mediated light perception helps the cells in finding an environment with optimal light conditions for photosynthesis. Eyespots are the simplest and most common "eyes" found in nature, composed of photoreceptors and areas of bright orange-red pigment granules.
Q: A rectangular lawn of dimensions 80 m x 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m ? 1557 05b5cc6eee4d2b4197774ef1b
5b5cc6eee4d2b4197774ef1b- 1Rs. 3600false
- 2Rs. 3800false
- 3Rs. 3900true
- 4Rs. 3700false
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Answer : 3. "Rs. 3900"
Explanation :
Answer: C) Rs. 3900 Explanation: Area = (l + b – d) d = (80 + 60 – 10)10 => 1300 sq.mts => 1300 x 3 = Rs.3900
Q: When all the students in a school are made to stand in rows of 54, 30 such rows are formed. If the students are made to stand in rows of 45, how many such rows will be formed ? 1557 05b5cc736e4d2b4197774f88d
5b5cc736e4d2b4197774f88d- 122false
- 236true
- 332false
- 426false
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Answer : 2. "36"
Explanation :
Answer: B) 36 Explanation: Total number of students = 54 x 30When arranged in rows of 45, number of rows formed are, 54x3045 = 36.
Q: Every year before the festive season, a brand store increases the price of the product by 42% and then introduce two successive discount of 10% and 11% respectively. What is percentage loss and percentage gain ? 1557 05b5cc745e4d2b4197774f9f9
5b5cc745e4d2b4197774f9f9- 13.25% lossfalse
- 213.742% lossfalse
- 33.25% gainfalse
- 413.742% gaintrue
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Answer : 4. "13.742% gain"
Explanation :
Answer: D) 13.742% gain Explanation: Let CP = 100,42 % increase => SP = 14210 % discount in SP => ((142 x 10)/100) = 14.2So 1st SP = (142 - 14.2) = 127.8, again 12 % discount in 1st SP ((127.8 x 11)/100) = 14.0582nd SP = (127.8 - 14.058) = 113.742, So finally CP = 100, SP = 113.742, => gain = 13.742%.

