CAT Practice Question and Answer
8Q: A low trough is indicative of 1482 05b5cc61ee4d2b4197774b788
5b5cc61ee4d2b4197774b788- 1the start of a depressionfalse
- 2the end of a recessionfalse
- 3a serious depressionfalse
- 4a growing recessiontrue
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 4. "a growing recession"
Explanation :
Answer: D) a growing recession Explanation: A low trough is indicative of "a growing recession" since a trough indicates a general change in the business cycle, which can have varying degrees of importance. A recession could be an important decline in economic activity that goes on for quite many months.
Q: Value of vehicle at end of each year depreciates at the rate of 3/5th of value at the beginning. If Initial value is 10,000Rs then at the end of three years its value is ? 1481 05b5cc715e4d2b4197774f472
5b5cc715e4d2b4197774f472- 1Rs. 6000false
- 2Rs. 3600false
- 3Rs. 2160true
- 4Rs. 415false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 3. "Rs. 2160"
Explanation :
Answer: C) Rs. 2160 Explanation: End of first year : 10000 x (3/5) = Rs. 6000End of second year : 6000 x (3/5) = Rs. 3600End of third year : 3600 x (3/5) = Rs. 2160
Q: A,B,C,D,E,F,G and H are sitting around a circular table facing the centre but not necessarily in the same order. G sits third to the right of C. E is second to the right of G and 4th to the right of H. B is fourth to the right of C. D is not an immediate neighbour of E. A and C are immediate neighbours. Which of the following is/are correct ? 1481 05b5cc6c5e4d2b4197774dd46
5b5cc6c5e4d2b4197774dd46- 1F is third to the left of Bfalse
- 2F is second to the right of Btrue
- 3B is an immediate neighbour of Dfalse
- 4All of the abovefalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "F is second to the right of B"
Explanation :
Answer: B) F is second to the right of B Explanation: From the given information, the circular arrangement is Here F is second to the right of B and the remaning all are wrong.
Q: When should you stop at green and go at red? 1481 05b5cc672e4d2b4197774c07c
5b5cc672e4d2b4197774c07c- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer :
Explanation :
While eating a watermelon, we all go along the red and stops at green.
Q: What kind of apple isn't an apple? 1481 05b5cc6a5e4d2b4197774cccb
5b5cc6a5e4d2b4197774cccb- 1Pineappletrue
- 2Akero applefalse
- 3Adanac applefalse
- 4Aceymac applefalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "Pineapple"
Explanation :
Answer: A) Pineapple Explanation: Except pineapple remaining all three are types of apples. Pineapple is what kind of apple isn't an apple.
Q: What was a major contribution of John Muir? 1480 05b5cc62ce4d2b4197774b91c
5b5cc62ce4d2b4197774b91c- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer :
Explanation :
John Muir encouraged the establishment of various parks in the United States' National Park System, including the Yosemite and Sequoia National Parks.
Q: A duster is of dimension 5x5x7 all in cms, is sinked into a cylindrical vessel of radius 5 cm and height 10 cm. After insertion the level of the water is inccresed by 2.14 cm. Then by what percentage the part of the duster is above the layer ? 1480 05b5cc705e4d2b4197774f216
5b5cc705e4d2b4197774f216- 196 %false
- 24 %true
- 397 %false
- 43 %false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "4 %"
Explanation :
Answer: B) 4 % Explanation: Imension of the duster is assumed as 5x5x7 cm3 Volume of the duster below the water layer= volume of water increased= πxrxrxh = 3.14×52×2.14 ≈ 168 cm3 Total volume of the duster = 5×5×7 = 175 cm3 Percentage of the duster part below the layer = 168×100/175 = 96% Percentage of the duster part above the layer = 4%
Q: What is the bond order of O2? 1480 05b5cc65ee4d2b4197774be02
5b5cc65ee4d2b4197774be02- 11.5false
- 22true
- 32.5false
- 41false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: The number of bonds between a pair of atoms is called the bond order. Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two. When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5 the average of an S-O single bond in one Lewis structure and an S=O double bond in the other. In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O2 molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.

