CAT Practice Question and Answer

Q: Find the missing number in the given series ? 15, 51, 216, 1100, ?, 46452 4342 0

  • 1
    5660
    Correct
    Wrong
  • 2
    6560
    Correct
    Wrong
  • 3
    6750
    Correct
    Wrong
  • 4
    6630
    Correct
    Wrong
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Answer : 4. "6630"
Explanation :

Answer: D) 6630 Explanation: Let first no. be "k" and multiple be "l"...start value of y with 3then,[(k x y) + {l x (l-1)}]Thus, we get 15 x 3 + 3 x 2 = 5151 x 4 + 4 x 3 = 216216 x 5 + 5 x 4 = 11001100 x 6 + 6 x 5 = 66306630 x 7 + 7 x 6 = 46452 Therefore, the missing number is 6630.

Q: In an objective competitive exam, a correct answer score 4 marks and on a wrong answer 2 marks are negatively added. A student scores 420 marks from 150 question. How many answers were correct ? 4335 0

  • 1
    145
    Correct
    Wrong
  • 2
    138
    Correct
    Wrong
  • 3
    125
    Correct
    Wrong
  • 4
    120
    Correct
    Wrong
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Answer : 4. "120"
Explanation :

Answer: D) 120 Explanation: let x be the correct answer and y be the wrong answerso the total number of questions is (x + y) = 150.....(1)=> 4x - 2y = 420.....(2)By solving (1) & (2), we get => 6x = 720hence x = 120Therefore, number of correct answers are 120.

Q: "Good Samaritan Policy" has been launched by which state / union territory government? 4332 0

  • 1
    Delhi
    Correct
    Wrong
  • 2
    Karnataka
    Correct
    Wrong
  • 3
    Telangana
    Correct
    Wrong
  • 4
    Gujarath
    Correct
    Wrong
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Answer : 1. "Delhi"
Explanation :

Answer: A) Delhi Explanation: The Delhi government has recently approved 'Good Samaritan Policy' under which monetary incentive of Rs 2,000 and appreciation certificate will be given to people who help road accident victims in the national capital. The scheme is intended to encourage people to take accident victims in emergency situation to hospitals so that someone’s life could be saved.

Q: Find the missing number in the given number series? 2676, 445, ?, 21,6, 2, 1 4331 0

  • 1
    88
    Correct
    Wrong
  • 2
    92
    Correct
    Wrong
  • 3
    96
    Correct
    Wrong
  • 4
    102
    Correct
    Wrong
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Answer : 1. "88"
Explanation :

Answer: A) 88 Explanation: The given number series 2676, 445, ?, 21,6, 2, 1 follows a pattern that, From right side, 1 1 x 1 + 1 = 2 2 x 2 + 2 = 6 6 x 3 + 3 = 21 21 x 4 + 4 = 88 88 x 5 + 5 = 445 445 x 6 + 6 = 2676   Hence the missing number in the given number series is 88.

Q: There are three rooms in a Hotel: one single, one double and one for four persons. How many ways are there to house seven persons in these rooms ? 4325 0

  • 1
    105
    Correct
    Wrong
  • 2
    7! x 6!
    Correct
    Wrong
  • 3
    7!/5!
    Correct
    Wrong
  • 4
    420
    Correct
    Wrong
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Answer : 1. "105"
Explanation :

Answer: A) 105 Explanation: Choose 1 person for the single room & from the remaining choose 2 for the double room & from the remaining choose 4 people for the four person room,   Then, 7C1 x 6C2 x 4C4  = 7 x 15 x 1 = 105

Q: P is faster than Q. P and Q each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then, P's speed is equal to ? 4323 0

  • 1
    3 km/hr
    Correct
    Wrong
  • 2
    4 km/hr
    Correct
    Wrong
  • 3
    5 km/hr
    Correct
    Wrong
  • 4
    6 km/hr
    Correct
    Wrong
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Answer : 2. "4 km/hr"
Explanation :

Answer: B) 4 km/hr Explanation: Let P's speed = x km/hr. Then, Q's speed = (7 - x) km/ hr.   So, 24/x + 24/(7 - x) = 14   x2 - 98x + 168 = 0   (x - 3)(x - 4) = 0 => x = 3 or 4.   Since, P is faster than Q,   so P's speed = 4 km/hr and Q's speed = 3 km/hr.

Q: There are 100 students in 3 sections A, B and C of a class. The average marks of all the three sections was 84. The average of B and C was 87.5 and the average marks of students in A section was : 4310 0

  • 1
    20
    Correct
    Wrong
  • 2
    35
    Correct
    Wrong
  • 3
    54
    Correct
    Wrong
  • 4
    40
    Correct
    Wrong
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Answer : 1. "20"
Explanation :

Answer: A) 20 Explanation: Numbers of students in section A = x ∴ Numbers of students in section B and C = (100 – x) ∴ x 70 + (100 – x) 87.5 = 84 100 => 70x + 87.5 100 – 87.5x = 8400 => 8750 – 17.5x = 8400 => 17.5x = 8750 – 8400 => x = 20.

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