CAT Practice Question and Answer
8Q: Fumble is to Finesse as Malign is to 3530 05b5cc6a2e4d2b4197774cba8
5b5cc6a2e4d2b4197774cba8- 1Slanderfalse
- 2Extoltrue
- 3Criticizefalse
- 4Assurancefalse
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Answer : 2. "Extol"
Explanation :
Answer: B) Extol Explanation: Fumble means grope, mishandle, drop, mistake, blunder, bungle. Finesse means skill, grace, elegance, assurance, diplomacy, discretion. So, they are opposites. Similarly, Malign means slander or criticize. Extol means being kind or good-natured. A person without finesse often fumbles. A person without extol in his heart often maligns. Extol means praise or exalt, benevolence
Q: A thief steals half the total number of loaves of bread plus 1/2 loaf from a bakery. A second thief steals half the remaining number of loaves plus 1/2 loaf and so on. After the 5th thief has stolen there are no more loaves left in the bakery. What was the total number of loaves did the bakery have at the beginning ? 3525 05b5cc70ee4d2b4197774f33c
5b5cc70ee4d2b4197774f33c- 121false
- 211false
- 317false
- 431true
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Answer : 4. "31"
Explanation :
Answer: D) 31 Explanation: Let y be the total number of loavesa be the remaining loaves after 1st thiefb be the remaining loaves after 2nd thiefand c, d..so on after 3 and 4 the = 0 be the remaining loaves after 5th thief a = y - (y/2 + 1/2)= y/2 - 1/2 b = a - (a/2 + 1/2)= a/2 - 1/2 c = b - (b/2 + 1/2)= b/2 - 1/2 d = c - (c/2 + 1/2)= c/2 - 1/2 e = d - (d/2 + 1/2)= d/2 - 1/2we know that, e = 0,thus by substitution, we getd = 1c = 3b = 7a = 15y = 31Therefore total number of bread loaves in bakery was 31.
Q: If 6 engines consume 24 metric tonnes of coal, when each is working 8 hours day, how much coal will be required for 9 engines, each running 13hours a day, it being given that 2 engines of former type consume as much as 3 engines of latter type ? 3523 05b5cc723e4d2b4197774f672
5b5cc723e4d2b4197774f672- 145 metric tonnestrue
- 247 metric tonnesfalse
- 355 metric tonnesfalse
- 434 metric tonnesfalse
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Answer : 1. "45 metric tonnes"
Explanation :
Answer: A) 45 metric tonnes Explanation: 2 engines of former type for one hour consumes (2 x 24)/(6 x8) = 1 metric ton i.e. 3 engines of latter type consumes 1 ton for one hour Hence 9 engines consumes 3 tons for one hour For 15 hours it is 15 x 3 = 45 metric tonnes.
Q: Find the odd one out of the following options. 3506 05b5cc6d6e4d2b4197774e679
5b5cc6d6e4d2b4197774e679- 1Sapphirefalse
- 2Rubyfalse
- 3Topazfalse
- 4Granitetrue
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Answer : 4. "Granite"
Explanation :
Answer: D) Granite Explanation: Except Granite all other options belong to the group of precious stones.
Q: In a queue, Amrita is 10th from the front while Mukul is 25th from behind and Mamta is just in the middle of the two. If there be 50 persons in the queue. What position does Mamta occupy from the front ? 3501 05b5cc6f8e4d2b4197774f068
5b5cc6f8e4d2b4197774f068- 114thfalse
- 216thfalse
- 318thtrue
- 420thfalse
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Answer : 3. "18th"
Explanation :
Answer: C) 18th Explanation: Number of persons between Amrita and Mukul = 50 - (10 + 25) = 15. Since Mamta lies in middle of these 15 persons, so Mamta`s position is 8th from Amrita i.e. 18th from the front.
Q: What is the value of P in the following Equation ? 192.5 × 19p = 197 3494 15b5cc6bee4d2b4197774d9a6
5b5cc6bee4d2b4197774d9a6- 13.9false
- 24.1false
- 33.7false
- 44.5true
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Answer : 4. "4.5"
Explanation :
Answer: D) 4.5 Explanation: Given equation is 192.5 ×19p = 197 Here it is in the form of am × an = am+n Here m = 2.5 , n = p, m+n = 7 => 2.5 + p = 7 => p = 7 - 2.5 => p = 4.5
Q: Each consonant in the word TIRADES is replaced by the previous letter in the English alphabet and each vowel is replaced by the next letter in the English alphabet and the new letters are arranged alphabetically. Which of the following will be the fourth from the right end ? 3493 05b5cc736e4d2b4197774f888
5b5cc736e4d2b4197774f888- 1Sfalse
- 2Qfalse
- 3Jtrue
- 4Ufalse
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Answer : 3. "J"
Explanation :
Answer: C) J Explanation: Given word is TIRADESNow the consonants T, R, D, S are replaced by S, Q, C, RAnd Vowels are I, A, E are replaced by J, B and FThey are arranged alphabeticallyNew word is BCFJQRS The fourth letter from the right end is J.
Q: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3491 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
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Answer : 1. "127.5 m"
Explanation :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.