1. Answer : 2 Explanation : Productivity = Total production/area of Agr.land  Productivity of UP = [ (35000+30000+25000) / (30/100) ] = 300000   Productivity of MP = [ (30000+37500+27500) / (25/100) ] = 380000   Productivity of Bihar = [ (22500+27500+25000) / (20/100) ] = 375000  Productivity of Odisha = [ (22500+15000+10000) / (5/100) ]= 950000   Productivity of Haryana = [ (30000+25000+35000) / (8/100) ] = 1125000   Productivity of Punjab = [ (40000+35000+30000) / (12/100) ] = 875000  The Productivity of Haryana is the maximum.       2. Answer : 5   Explanation : Production of Punjab is maximum = 105000 tonnes      3. Answer : 3  Explanation : Production of Wheat in Punjab = 40000 tones Production of Maize in Odisha = 10000 tones Required % = (40000 - 10000)/100 = 300%      4. Answer : 4  Explanation : The ratio of prodution of Rice in Bihar to the production of Wheat in Haryana = 25000 tonnes : 25000 tonnes = 1 : 1       5. Answer : 1   Explanation : Income of MP from export of 40% of Rice at the rate of Rs.30 per kg = Rs.39crore Income of UP from export of 30% of Rice at the rate of Rs.32 per kg = Rs.28.8 crore  Required ratio = 39 : 28.8 = 390 : 288 = 65 : 48

Answer: A) decreases Explanation: When water freezes its density decreases. Water at ordinary temperatures contracts and increases in density as it is cooled, like most substances. But at about 4°C it reaches a maximum density and then decreases in density as it approaches the freezing point.

Answer: D) FDBGECA Explanation:

Answer: C) 175 Explanation: Given that,  working days = 5  working hours = 8  A man get rupess per hour is Rs.2.40  So in one day the man get total rupees is 2.40 x 8 = 19.2  So in 5 days week the man get total rupees is 19.2 x 5 = 96  So in 4 week the man get total rupees is 96 x 4 = 384  So the man worked for = 160hours in 4 weeks    But given that the man earned Rs.432    Hence remaning money is (432-384 = 48)which is earn by doing overtime work   Overtime hours  = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.

Answer: B) 554 Explanation: The given number series follows a pattern that 5 x 5 – 1 = 24 24 x 4 – 2 = 94 94 x 3 – 3 = 279 279 x 2 – 4 = 554

Answer: B) 15/39 Explanation: P( selecting atleast one couple) = 1 - P(selecting none of the couples for the prize)     = 1-16C1× 14C1×12C1×10C116C4=1539

Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.

Answer: D) 35 Explanation: Given S = 17 yrs A = 16 yrs B = 12 yrs Average = 17 + 16 + 12/3 = 15 yrs Given if Aslam added to them, their average increases by 5 => Average of 4 members = 20 Let the age of Aslam be 'x' Then,  17 + 16 + 12 + x /4 = 20 => x = 80 - 45 => x = 35.    Hence, the age of Aslam is 35 yrs.