CAT Practice Question and Answer

Q: A 300m race is held between two players running 3m/s and 5m/s in swimming pool of 50m long. how many times the two player meet in opposite direction till the faster one completes the race ? 3784 0

  • 1
    3 times
    Correct
    Wrong
  • 2
    4 times
    Correct
    Wrong
  • 3
    5 times
    Correct
    Wrong
  • 4
    2 times
    Correct
    Wrong
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Answer : 1. "3 times"
Explanation :

Answer: A) 3 times Explanation: Let us assume A is the faster and B is slower, A takes 10s to finish a lap of 50 m, B takes 17s(approx) to finish a lap of 50 m.So at 11th sec A starts his 2nd lap by the time B will be in between so that is the first time they will meet each other, at 21st sec A starts his 3rd lap by the time B will be coming back to finish his 2nd lap. So that is the second time they meet in opposite. Then at 31st sec A will start his 4th lap by the time B would not even finish 2nd lap as he take 34(2*17) sec to finish 2 laps. So at 35th sec B will start his 3rd lap by the time A will be coming back to finish his 4th lap in the half way so they will meet 3rd time. At 41st sec A will start its fifth lap by the time B will be going to finish 3rd lap in same direction. At 50th second both will complete A's 5th lap and B's 3rd lap. So they will start next lap(A's 6th and B's 4th) from the same point in same direction. And A will finish the race after completing 300m(6*50) total distance and then they wont meet opposite to each other. So totally they met 3 times in opposite direction.

Q: The study of Heavenly bodies is called 3784 0

  • 1
    Astronomy
    Correct
    Wrong
  • 2
    Astrology
    Correct
    Wrong
  • 3
    Astrophysics
    Correct
    Wrong
  • 4
    Astronautics
    Correct
    Wrong
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Answer : 1. "Astronomy"
Explanation :

Answer: A) Astronomy Explanation: Astronomy is the study of planets and heavenly bodies. Historically, astronomy has focused on observations of heavenly bodies. It is a close cousin to astrophysics. Succinctly put, astrophysics involves the study of the physics of astronomy and concentrates on the behavior, properties and motion of objects out there.

Q: _ tu _ rt _ s _ _ usrtu _ 3783 0

  • 1
    rsutrr
    Correct
    Wrong
  • 2
    rsurtr
    Correct
    Wrong
  • 3
    rsurts
    Correct
    Wrong
  • 4
    rtusru
    Correct
    Wrong
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Answer : 3. "rsurts"
Explanation :

Answer: C) rsurts Explanation: The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.

Q: A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ? 3775 0

  • 1
    Rs. 404.80
    Correct
    Wrong
  • 2
    Rs. 536.80
    Correct
    Wrong
  • 3
    Rs.440
    Correct
    Wrong
  • 4
    Rs. 160
    Correct
    Wrong
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Answer : 1. "Rs. 404.80"
Explanation :

Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.

Q: P and Q can complete a job in 24 days working together. P alone can complete it in 32 days. Both of them worked together for 8 days and then P left. The number of days Q will take to complete the remaining work is ? 3751 0

  • 1
    56 days
    Correct
    Wrong
  • 2
    54 days
    Correct
    Wrong
  • 3
    60 days
    Correct
    Wrong
  • 4
    64 days
    Correct
    Wrong
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Answer : 4. "64 days"
Explanation :

Answer: D) 64 days Explanation: (P+Q)'s 1 day work = 1/24 P's 1 day work = 1/32 => Q's 1 day work = 1/24 - 1/32 = 1/96 Work done by (P+Q) in 8 days = 8/24 = 1/3 Remainining work = 1 - 1/3 = 2/3 Time taken by Q to complete the remaining work = 2/3 x 96 = 64 days.

Q: Find the odd one out of the following number series? 9 5 6 14 56 488 3748 0

  • 1
    56
    Correct
    Wrong
  • 2
    6
    Correct
    Wrong
  • 3
    14
    Correct
    Wrong
  • 4
    5
    Correct
    Wrong
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Answer : 1. "56"
Explanation :

Answer: A) 56 Explanation: The given number series follows a pattern that, 9 9 x 0.5 + 0.5 = 5 5 x 1 + 1 = 6 6 x 2 + 2 = 14 14 x 4 + 4 = 60 (not equals to 56) 60 x 8 + 8 = 488.   Hence, the odd one in the given number series is 56.

Q: Paw : Cat :: Hoof : ? 3747 0

  • 1
    Donkey
    Correct
    Wrong
  • 2
    Lion
    Correct
    Wrong
  • 3
    Elephant
    Correct
    Wrong
  • 4
    Horse
    Correct
    Wrong
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Answer : 4. "Horse"
Explanation :

Answer: D) Horse Explanation: The cat's foot is called a paw. The horse's foot is called a hoof.

Q: 3125  256  ?  4  1 Which number replaces the "?" in the question? 3747 0

  • 1
    27
    Correct
    Wrong
  • 2
    128
    Correct
    Wrong
  • 3
    32
    Correct
    Wrong
  • 4
    64
    Correct
    Wrong
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Answer : 1. "27"
Explanation :

Answer: A) 27 Explanation: In the given series numbers are arranged following the rule, 55,44, 33, 22, 11  Therefore, the missing number is 27.

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