CAT Practice Question and Answer
8Q: Find the odd one out of the following number series? 9 5 6 14 56 488 2884 05b5cc66de4d2b4197774bfb0
5b5cc66de4d2b4197774bfb0- 156true
- 26false
- 314false
- 45false
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Answer : 1. "56"
Explanation :
Answer: A) 56 Explanation: The given number series follows a pattern that, 9 9 x 0.5 + 0.5 = 5 5 x 1 + 1 = 6 6 x 2 + 2 = 14 14 x 4 + 4 = 60 (not equals to 56) 60 x 8 + 8 = 488. Hence, the odd one in the given number series is 56.
Q: Sum of the ages of Rajesh, Suresh, Mahesh and Dinesh is 76 years. 7 years hence, their age ratio is 7:6:5:8. Find Mahesh’s present age ? 2883 05b5cc6c2e4d2b4197774dba5
5b5cc6c2e4d2b4197774dba5- 117 yearsfalse
- 213 yearstrue
- 314 yearsfalse
- 416 yearsfalse
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Answer : 2. "13 years"
Explanation :
Answer: B) 13 years Explanation: Given R + S + M + D = 76 => R+7 : S+7 : M+7 : D+7 = 7:6:5:8 => Let the ratio = x => M+7 = 5x => M = 5x-7 => R = 7x-7 => S = 6x-7 => D = 8x-7 => R + S + M + D = 76 => 7x-7 + 6x-7 + 5x-7 + 8x-7 = 76 => 26x - 28 = 76 => 26x = 104 => x = 4 => Mahesh's present age = 5x-7 = 20 - 7 = 13 years.
Q: Ratio of the ages of Mahesh and Nilesh is 5 : x. Mahesh is 18 years younger to Ramesh. After nine years Ramesh will be 47 years old. If the difference between the ages of Mahesh and Nilesh is same as the age of Ramesh, what is the value of x ? 2874 05b5cc6dce4d2b4197774e9bf
5b5cc6dce4d2b4197774e9bf- 111.8false
- 212.9false
- 313.7false
- 414.5true
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Answer : 4. "14.5"
Explanation :
Answer: D) 14.5 Explanation: Let the present ages of Mahesh, Nilesh and Ramesh be k, l and m respectively.k/l = 5/x ------ (1)k = m - 18 ------ (2)m + 9 = 47 ------ (3)k - l = m ----- (4)(3) => m = 47 - 9 = 38 years(2) => k = 38 -18 = 20 years(1) => 20/l = 5/x => l = 4x(4) => 4x - 20 = 38=> 4x = 58 => x = 14.5
Q: A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ? 2872 05b5cc720e4d2b4197774f613
5b5cc720e4d2b4197774f613- 145false
- 224false
- 342false
- 454true
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Answer : 4. "54"
Explanation :
Answer: D) 54 Explanation: By trial and error method from the given options, as 54 - 45 = (1/11) x (45+54) = 99/11 = 9 Hence this satisfies the given conditions. Then the woman's husband age is 54.
Q: Find the odd man out in the following number series? 5, 4, 9, 32, 273 2865 05b5cc695e4d2b4197774c500
5b5cc695e4d2b4197774c500- 14false
- 29false
- 332true
- 4273false
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Answer : 3. "32"
Explanation :
Answer: C) 32 Explanation: The given number series follows 5, 4, 9, 32, 308 pattern that 5 5 x 1 - 1 = 4 4 x 3 - 3 = 9 9 x 5 - 5 = 40 (not equals to 32) 40 x 7 - 7 = 273 Hence, the odd man in the given number series is 32.
Q: Programs stored in ROM are called 2863 15b5cc6a9e4d2b4197774ceef
5b5cc6a9e4d2b4197774ceef- 1Hardwarefalse
- 2Firmwaretrue
- 3Freewarefalse
- 4Softwarefalse
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Answer : 2. "Firmware"
Explanation :
Answer: B) Firmware Explanation: The programs which are as permanent as hardware and stored in ROM are known as Firmware. Data stored in ROM can only be modified slowly, with difficulty, or not at all, so it is mainly used to store firmware (software that is closely tied to specific hardware, and unlikely to need frequent updates) or application software in plug-in cartridges.
Q: The number of permutations of the letters of the word 'MESMERISE' is ? 2861 05b5cc6ebe4d2b4197774ee5f
5b5cc6ebe4d2b4197774ee5f- 19!/(2!)^{2}x3!true
- 29! x 2! x 3!false
- 30false
- 4Nonefalse
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Answer : 1. "9!/(2!)^{2}x3!"
Explanation :
Answer: A) 9!/(2!)^{2}x3! Explanation: n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.The letter pattern 'MESMERISE' consists of 10 letters of which there are 2M's, 3E's, 2S's and 1I and 1R.Number of arrangements = 9!(2!)2×3!
Q: A vessel contains 20 liters of a mixture of milk and water in the ratio 3:2. 10 liters of the mixture are removed and replaced with an equal quantity of pure milk. If the process is repeated once more, find the ratio of milk and water in the final mixture obtained ? 2860 05b5cc6dce4d2b4197774e960
5b5cc6dce4d2b4197774e960- 15:3false
- 21:4false
- 34:1false
- 49:1true
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Answer : 4. "9:1"
Explanation :
Answer: D) 9:1 Explanation: Milk = 3/5 x 20 = 12 liters, water = 8 liters If 10 liters of mixture are removed, amount of milk removed = 6 liters and amount of water removed = 4 liters. Remaining milk = 12 - 6 = 6 liters Remaining water = 8 - 4 = 4 liters 10 liters of pure milk are added, therefore total milk = (6 + 10) = 16 liters. The ratio of milk and water in the new mixture = 16:4 = 4:1 If the process is repeated one more time and 10 liters of the mixture are removed, then amount of milk removed = 4/5 x 10 = 8 liters. Amount of water removed = 2 liters. Remaining milk = (16 - 8) = 8 liters. Remaining water = (4 -2) = 2 liters. Now 10 lts milk is added => total milk = 18 lts The required ratio of milk and water in the final mixture obtained = (8 + 10):2 = 18:2 = 9:1.