Answer: C) 40 triangles, 7 Squares Explanation: The figure may be labelled as shown      Triangles :   The Simplest triangles are BGM, GHM, HAM, ABM, GIN, IJN, JHN, HGN, IKO, KLO, LJO, JIO, KDP, DEP, ELP, LKP, BCD and AFE i.e 18 in number   The triangles composed of two components each are ABG, BGH, GHA, HAB, HGI, GIJ, IJH, JHG, JIK, IKL, KLJ,LJI, LKD, KDE, DEL and ELK i.e 16 in number.   The triangles composed of four components each are BHI, GJK, ILD, AGJ, HIL and JKE i.e 6 in number.   Total number of triangles in the figure = 18 + 16 + 6 =40.   Squares :   The Squares composed of two components each are MGNH, NIOJ, and OKPL i.e 3 in number   The Squares composed of four components each are BGHA, GIJH, IKJL and KDEL i.e 4 in number   Total number of squares in the figure = 3 + 4 =7

Answer: D) U Explanation: If all the A's are dropped from the above arrangement, we get   C U B E D E D B E B U C D B C D B D U B C C B E D.    Here the eleventh from the left end of the above arrangement is U

Answer: A) बड़ी संख्या में सेल स्पष्टीकरण: कंप्यूटिंग में, मेमोरी कंप्यूटर हार्डवेयर एकीकृत सर्किट को संदर्भित करता है जो कंप्यूटर में तत्काल उपयोग के लिए जानकारी संग्रहीत करता है। अधिकांश सेमीकंडक्टर मेमोरी को मेमोरी सेल या बिस्टेबल फ्लिप-फ्लॉप में व्यवस्थित किया जाता है, प्रत्येक एक बिट (0 या 1) को स्टोर करता है।

Answer: B) 5 Explanation: There are total 5 ways.we have only one kg of weight so,2kg = 1kg + 1kg4kg = 1 + 2 + 18kg = 1 + 2 + 4 + 116kg = 1 + 2 + 4 + 8 + 131kg = 1 + 2 + 4 + 8 + 16So 5 weights are needed.

Answer: D) Data is not sufficient Explanation: Let the sum be Rs. p, rate be R% p.a. and time be T years. Then,  P×T×(R+2)100-P×T×R100=108  ⇒2PT= 10800  ...... (1)  And,   P×R×(T+2)100-P×R×T100=180   ⇒2PR = 18000 ......(2) Clearly, from (1) and (2), we cannot find the value of pSo, the data is not sufficient.

Answer: D) All the above Explanation: The basic operations performed by a computer are Arithmetic operation, Logical operation and Storage and relative.

Answer: A) Rs. 620 Explanation: Let the C.P of one item is Rs. P and that of other is Rs. (7500 - P) According to the data given C.P = S.P => Px(116/100) + (7500-P)x(86/100) = 7500 => 30P = 105000 => P = 3500 Required difference between selling prices = Rs. [(3500/100) x 116] - [(4000/100) x 86] = 4060-3440 = Rs. 620

Answer: C) 81 Explanation: 729 = 9 x 9 x 9 => Cube root of 729 = 9   Now, required square of 9 = 9 x 9 = 81.