CAT Practice Question and Answer
8Q: At a dinner party every two guests used a bowl of rice between them, every three guests used a bowl of dal between them and every four used a bowl of meat between them. There were altogether 65 dishes. How many guests were present at the party ? 3055 05b5cc720e4d2b4197774f636
5b5cc720e4d2b4197774f636- 160true
- 274false
- 382false
- 458false
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Answer : 1. "60"
Explanation :
Answer: A) 60 Explanation: Let, no. of rice bowl = xno. of dal bowl = yno. of meat bowl = z Then, x + y + z = 65 ....(1) Also given that, 2x = 3y = 4z substituting value of y & z in terms of x i.e. y = 2x/3 and z = x/2 in eq (1),We get x = 30. As 1 rice bowl is shared between 2 guests, Therefore, there are 60 guests.
Q: C U B A E D E D A B E B A U C D B C A D B D U B C A C B E D A If all the A's are dropped from the above arrangement, which of the following will be eleventh from the left end of the above arrangement? 3052 05b5cc7d2e4d2b419777512e0
5b5cc7d2e4d2b419777512e0- 1Efalse
- 2Cfalse
- 3Dfalse
- 4Utrue
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Answer : 4. "U"
Explanation :
Answer: D) U Explanation: If all the A's are dropped from the above arrangement, we get C U B E D E D B E B U C D B C D B D U B C C B E D. Here the eleventh from the left end of the above arrangement is U
Q: A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2490 ? 3050 05b5cc6e1e4d2b4197774ebb1
5b5cc6e1e4d2b4197774ebb1- 1Rs. 820false
- 2Rs. 830true
- 3Rs. 840false
- 4Rs. 850false
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Answer : 2. "Rs. 830"
Explanation :
Answer: B) Rs. 830 Explanation: Let the total amount in the partnership be 'x'.Then A's share = x/3B's share = x/4C's share = x/5D's share = x - (x/3 + x/4 +x/5) = 13x/60 A : B : C : D = x/3 : x/4 : x/5 : 13x/60 = 20 : 15 : 12 : 13 A's share in the profit of Rs. 2490 = 20 (2490/60) = Rs. 830.
Q: Choose the antonym of the word given from the following options ? MUNDANE 3049 05b5cc75ce4d2b4197774fc52
5b5cc75ce4d2b4197774fc52- 1Extraordinarytrue
- 2Regularfalse
- 3Visionaryfalse
- 4Routinefalse
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Answer : 1. "Extraordinary"
Explanation :
Answer: A) Extraordinary Explanation:
Q: The number of permutations of the letters of the word 'MESMERISE' is ? 3049 05b5cc6ebe4d2b4197774ee5f
5b5cc6ebe4d2b4197774ee5f- 19!/(2!)^{2}x3!true
- 29! x 2! x 3!false
- 30false
- 4Nonefalse
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Answer : 1. "9!/(2!)^{2}x3!"
Explanation :
Answer: A) 9!/(2!)^{2}x3! Explanation: n items of which p are alike of one kind, q alike of the other, r alike of another kind and the remaining are distinct can be arranged in a row in n!/p!q!r! ways.The letter pattern 'MESMERISE' consists of 10 letters of which there are 2M's, 3E's, 2S's and 1I and 1R.Number of arrangements = 9!(2!)2×3!
Q: In a queue, Shankar is ninth from the rear end. Althaf's place is eighth from the front. Nitu is standing between the two. What could be the minimum numbers of boys standing in the queue ? 3048 05b5cc74ae4d2b4197774fa9a
5b5cc74ae4d2b4197774fa9a- 118false
- 214true
- 322false
- 424false
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Answer : 2. "14"
Explanation :
Answer: B) 14 Explanation: 1 2 3 4 5 6(Shankar) 7(Nitu) 8(Althaf) 9 10 11 12 13 14Here, Althaf is 8th from front, Shankar is 9th from rear end and Nitu is between themSo minimum no. of boys standing in the queue = 14
Q: Sponge is to Porous as Rubber is to 3040 05b5cc6abe4d2b4197774d006
5b5cc6abe4d2b4197774d006- 1Inflexiblefalse
- 2Elastictrue
- 3Solidfalse
- 4Massivefalse
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Answer : 2. "Elastic"
Explanation :
Answer: B) Elastic Explanation: A sponge is a porous material. Rubber is an elastic material. Since Rubber is not a Massive or solid and not an inflexible thing, it is elastic.
Q: A merchant buys two items for Rs. 7500. One item he sells at a profit of 16% and the other item at 14% loss. In the deal, the merchant makes neither any profit nor any loss. What is the difference between the selling price of both the items? 3038 05b5cc69de4d2b4197774c88d
5b5cc69de4d2b4197774c88d- 1Rs. 620true
- 2Rs. 654false
- 3Rs. 725false
- 4Rs. 747false
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Answer : 1. "Rs. 620"
Explanation :
Answer: A) Rs. 620 Explanation: Let the C.P of one item is Rs. P and that of other is Rs. (7500 - P) According to the data given C.P = S.P => Px(116/100) + (7500-P)x(86/100) = 7500 => 30P = 105000 => P = 3500 Required difference between selling prices = Rs. [(3500/100) x 116] - [(4000/100) x 86] = 4060-3440 = Rs. 620

