CAT Practice Question and Answer
8Q: The amount of water (in ml) that should be added to reduce 9 ml lotion, containing 50% alcohol, to a lotion containing 30% alcohol is ? 3163 05b5cc74fe4d2b4197774fae5
5b5cc74fe4d2b4197774fae5- 16 mltrue
- 211 mlfalse
- 315 mlfalse
- 49 mlfalse
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Answer : 1. "6 ml"
Explanation :
Answer: A) 6 ml Explanation: Let us assume that the lotion has 50% alcohol and 50% water.ratio = 1:1As the total solution is 9mlalcohol = water = 4.5mlNow if we want the quantity of alcohol = 30%The quantity of water = 70%The new ratio = 3:7Let x ml of water be addedWe get,4.54.5+x = 37=> x=6Hence 6ml of water is added.
Q: Which 'Water Body' separates Andaman and Nicobar Islands ? 3162 05b5cc6dbe4d2b4197774e8e6
5b5cc6dbe4d2b4197774e8e6- 1Eleventh Degree Channelfalse
- 2Andaman Seafalse
- 3Bay of Bengalfalse
- 4Ten Degree Channeltrue
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Answer : 4. "Ten Degree Channel"
Explanation :
Answer: D) Ten Degree Channel Explanation:
Q: System Study involves 3155 05b5cc69be4d2b4197774c7d9
5b5cc69be4d2b4197774c7d9- 1documenting the existing systemfalse
- 2identifying current deficiencies and establishing new goalsfalse
- 3study of an existing systemfalse
- 4All the abovetrue
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Answer : 4. "All the above"
Explanation :
Answer: D) All the above Explanation:
Q: What animal has the shortest gestation period? 3153 05b5cc6a1e4d2b4197774cab3
5b5cc6a1e4d2b4197774cab3- 1Elephantfalse
- 2Meadowsfalse
- 3Mousefalse
- 4Opossumtrue
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Answer : 4. "Opossum"
Explanation :
Answer: D) Opossum Explanation: The shortest gestation period known is 12 to 13 days, shared by three marsupials: the American or Virginian opossum (Didelphis marsupialis); the rare water opossum, or yapok (Chironectes minimus) of central and northern South America; and the eastern native cat (Dasyurus viverrinus) of Australia. Gestation is the period of time between fertilization and birth in oviparous animals. The elephant has the longest gestation period of about 23 months of any land animal.
Q: Which of the following pairs is mismatched? 3153 05b5cc6a8e4d2b4197774ce8b
5b5cc6a8e4d2b4197774ce8b- 1Pila globosa - pearltrue
- 2Kenia lacca - lacfalse
- 3Apis indica - honeyfalse
- 4Bombyx mori - silkfalse
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Answer : 1. "Pila globosa - pearl"
Explanation :
Answer: A) Pila globosa - pearl Explanation: Pinctada vulgaris is a bivalve from which pearl is obtained.
Q: Sony is one-fifth the age of her mother 15 years ago and Sony’s brother is three-fifth the age of his mother 10 years ago. If the sum of Sony and her brother’s ages is 31 then how old is Sony's mother ? 3149 05b5cc745e4d2b4197774fa04
5b5cc745e4d2b4197774fa04- 140false
- 250true
- 360false
- 470false
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Answer : 2. "50"
Explanation :
Answer: B) 50 Explanation: Sony and her brother's age sum is 31Let Sony's mother's age be 'x'.Now the conditions given for both of their ages related to their mom is1/5(x-15) + 3/5(x-10) = 31x-15 + 3x-30 = 1554x-45 = 1554x = 200x = 50So, Mother's age = 50. Cross verification : 15 years ago age = 35 => Sony age = 710 years ago age = 40 => bro age = 24 Sum = 24 + 7 = 31.
Q: Total number of students in 3 classes of a school is 333 . The number of students in class 1 and 2 are in 3:5 ratio and 2 and 3 class are 7:11 ratio . What is the strength of class that has highest number of students ? 3147 05b5cc72ce4d2b4197774f7a6
5b5cc72ce4d2b4197774f7a6- 1125false
- 2155false
- 3135false
- 4165true
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Answer : 4. "165"
Explanation :
Answer: D) 165 Explanation: Ratio C1:C2 = 3:5 and C2:C3 = 7:11So C1:C2:C3 = 21 : 35 : 55Let the strength of three classes are 21x, 35x and 55x respectively, then Given that 21x + 35x + 55x = 333=> 111x = 333 or x=3So strength of the class with highest number of students =55x = 55x3 = 165.
Q: 5 men and 3 boys can together cultivate a 23 acre field in 4 days and 3 men and 2 boys together can cultivate a 7 acre field in 2 days. How many boys will be needed together with 7 men, if they cultivate 45 acre of field in 6 days. 3147 05b5cc69de4d2b4197774c8ad
5b5cc69de4d2b4197774c8ad- 16false
- 24false
- 32true
- 43false
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Answer : 3. "2"
Explanation :
Answer: C) 2 Explanation: Let work done by 1 man in i day be m and Let work done by 1 boy in 1 day be b From the given data, 4(5m + 3b) = 23 20m + 12b = 23....(1) 2(3m + 2b) = 7 6m + 4b = 7 ....(2) By solving (1) & (2), we get m = 1, b = 1/4 Let the number of required boys = n 6(7 1 + n x 1/4) = 45 => n = 2.

