Answer: D) 80 Explanation: There should be 90 instead of 80so we can have a series5, 5x3, 15x2, 30x3, 90x2, 180x3, 540x2 and 1080x3 and so on...

Answer: B) 20 minutes Explanation: First send 17 and 7. After 7 minutes, 7 is at finish and 17 needs 10 more minutes to complete his travel. now send 13. After 10 minutes 17 reaches finish and 13 needs 3 more minutes to complete. now send 3. both 3 and 13 reach destination at the same time after 3 minutes. hence the time taken is 7+10+3=20 minutes.

Answer: D) 36 Explanation: Given there are 9 flavours of ice creams.   Each child takes the combination of two flavours and no two children will have the same combination   This can be done by  ways i.e children.   Number of children=C29  = 9 x 8 / 1x 2 = 36.

Answer: A) Bill Gates Explanation:

Answer: B) Cheteshwar Pujara Explanation: India's most consistent middle-order batsman Cheteshwar Pujara stormed his way into record books after playing a marathon innings against Australia on fourth day of the third Test match surpassing Rahul Dravid previous best of 495 balls.

Answer: D) Forests and energy Explanation:

Answer: D) 8 Explanation: Suppose there are 9 balls   Let us give name to each ball B1 B2 B3 B4 B5 B6 B7 B8 B9   Now we will divide all the balls into 3 groups.   Group1 - B1 B2 B3   Group2 - B4 B5 B6   Group3 - B7 B8 B9   Step1 - Now weigh any two groups. Let's assume we choose Group1 on left side of the scale and Group2 on the right side.   So now when we weigh these two groups we can get 3 outcomes.   Weighing scale tilts on left - Group1 has a heavy ball.Weighing scale tilts on right - Group2 has a heavy ball.Weighing scale remains balanced - Group3 has a heavy ball.Lets assume we got the outcome as 3. i.e Group 3 has a heavy ball.   Step2 - Now weigh any two balls from Group3. Lets assume we keep B7 on left side of the scale and B8 on right side.   So now when we weigh these two balls we can get 3 outcomes.   Weighing scale tilts on left - B7 is the heavy ball.Weighing scale tilts on right - B8 is the heavy ball.Weighing scale remains balanced - B9 is the heavy ball.The conclusion we get from this Problem is that each time weigh. We element 2/3 of the balls.   As we came to conclusion that Group3 has the heavy ball from Step1, we remove 6 balls from the equation i.e (2/3) of 9.   Simillarly we do the ame thing for the Step2.   Now going with this conclusion. We have 6561 balls.   Step - 1   Divided into 3 groups   Group1 - 2187Balls   Group2 - 2187Balls   Group3 - 2187Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 2   Divided into 3 groups   Group1 - 729Balls   Group2 - 729Balls   Group3 - 729Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 3   Divided into 3 groups   Group1 - 243Balls   Group2 - 243Balls   Group3 - 243Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 4   Divided into 3 groups   Group1 - 81Balls   Group2 - 81Balls   Group3 - 81Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 5   Divided into 3 groups   Group1 - 27Balls   Group2 - 27Balls   Group3 - 27Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 6   Divided into 3 groups   Group1 - 9Balls   Group2 - 9Balls   Group3 - 9Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 7   Divided into 3 groups   Group1 - 3Balls   Group2 - 3Balls   Group3 - 3Balls   Taking the similar steps as we did in the above example, we come to the conclusion that Group1 has the heavy ball.   Step - 8   So now when we weigh 2 balls out of 3 we can get 3 outcomes.   Weighing scale tilts on left - left side placed is the heavy ball.Weighing scale tilts on right - right side placed is the heavy ball.Weighing scale remains balanced - remaining ball is the heavy ball.So the general answer to this question is, it is always multiple of 3 steps.   For 9 balls  32= 9. therefore 2 steps   For 6561 balls 38 = 6561 therefore 8 steps

Answer: A) 25 Explanation: (A+B+C) do 1 work in 10 days. So (A+B+C)'s 1 day work=1/10 and as they work together for 4 days so workdone by them in 4 days=4/10=2/5 Remaining work=1-2/5=3/5   (B+C) take 10 more days to complete 3/5 work. So( B+C)'s 1 day work=3/50 Now A'S 1 day work=(A+B+C)'s 1 day work - (B+C)'s 1 day work=1/10-3/50=1/25 A does 1/25 work in in 1 day Therefore 1 work in 25 days.