Answer: D) Data is not sufficient Explanation: From the given data,how many goals scored = 5397....(1)many more matches = 982.....(2)he scored five = 163.....(3)from (1)&(2), many = 9 ....(4)from (1)&(3), scored = 3 ....(5)Using (4)&(5)in(1), we get goals = 5 or 7.

Answer: B) 2/3 Explanation: Total coins 30 In that, 1 rupee coins 20 50 paise coins 10Probability of total 1 rupee coins =  20C11 Probability that 11 coins are picked = 30C11 Required probability of a coin now picked from the box is 1 rupee = 20C11/30C11 = 2/3.

Answer: B) 217.50 Explanation: Given expression = (45 x 750/100) - (25 x 480/100) = (337.50 - 120) = 217.50

Answer: D) 70 Explanation: Here the given series is 1, 3, 6, 11, 20, 37, ??, and the logic behind the series is 1 x 2 + 1 = 3 3 x 2 + 0 = 6 6 x 2 + (-1) = 11 11 x 2 + (-2) = 20 20 x 2 + (-3) = 37 37 x 2 + (-4) = 70   Hence, the next number in the given series is 70.

Answer: D) April, July Explanation: If the period between the two months is divisible by 7, then that two months will have the same calender . Now,(a). October + November = 31 + 30 = 61 (not divisible by 7) (b). Apr. + May + June + July + Aug. + Sep. + Oct. = 30 + 31 + 30 + 31 + 31 +30 + 31 = 213 (not divisible by 7) (c). June + July + Aug. + Sep. = 30 + 31 + 31 + 30 = 122 (not divisible by 7) (d). Apr. + May + June = 30 + 31 + 30 = 91 (divisible by 7)   Hence, April and July months will have the same calendar.

Answer: D) 5/21 Explanation: Number of ways of (selecting at least two couples among five people selected) = (⁵C₂ x ⁶C₁) As remaining person can be any one among three couples left. Required probability = (⁵C₂ x ⁶C₁)/¹⁰C₅= (10 x 6)/252 = 5/21

Answer: D) 10 Explanation: Given nuber series is 15, 30, ? , 40, 8, 48  Here the number series follows a pattern that 15 15 x 2 = 30 30 ÷ 3 = 10 10 x 4 = 40 40 ÷ 5 = 8 8 x 6 = 48 Hence, the missing number in the series is 10.

Answer: D) Can't be determined Explanation: We cannot find out the answer because the number of days of the current month is not given.