GATE Practice Question and Answer
8Q: P, Q and R start simultaneously from A to B. P reaches B, turns back and meet Q at a distance of 11 km from B. Q reached B, turns back and meet R at a distance of 9 km from B. If the ratio of the speeds of P and R is 3:2, what is the distance between A and B ? 2192 05b5cc6c7e4d2b4197774de73
5b5cc6c7e4d2b4197774de73- 199true
- 2100false
- 389false
- 41false
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Answer : 1. "99"
Explanation :
Answer: A) 99 Explanation: Let, Distance between A and B = d Distance travelled by P while it meets Q = d + 11 Distance travelled by Q while it meets P = d – 11 Distance travelled by Q while it meets R = d + 9 Distance travelled by R while it meets Q = d – 9 Here the ratio of speeds of P & Q => SP : SQ = d + 11 : d – 11 The ratio of speeds of Q & R => SQ : SR = d + 9 : d – 9 But given Ratio of speeds of P & R => P : R = 3 : 2 SPSR = SPSQxSQSR = d+11d+9d-11d-9 => d+11d+9d-11d-9 = 3/2 => d = 1, 99 => d = 99 satisfies. Therefore, Distance between A and B = 99
Q: Maneela, Raghu and Aravind have some jems with each of them. Five times the number of jems with Raghu equals seven times the number of jems with Maneela while five times the number of jems with Maneela equals seven times the number of jems with Aravind. What is the minimum number of jems that can be there with all three of them put together ? 1996 05b5cc6c7e4d2b4197774de6e
5b5cc6c7e4d2b4197774de6e- 1108false
- 2107false
- 3109true
- 4110false
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Answer : 3. "109"
Explanation :
Answer: C) 109 Explanation: From given data, R : M = 5 : 7 M : A = 5 : 7 R : M : A = 25 : 35 : 49 25 + 35 + 49 = 109
Q: In what ratio must a merchant mix two varieties of oils worth Rs. 60/kg and Rs. 65/kg, so that by selling the mixture at Rs. 68.20/kg, he may gain 10% ? 1391 05b5cc6c6e4d2b4197774de5e
5b5cc6c6e4d2b4197774de5e- 12:3false
- 24:3false
- 33:4false
- 43:2true
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Answer : 4. "3:2"
Explanation :
Answer: D) 3:2 Explanation: Let he mixes the oils in the ratio = x : y Then, the cost price of the oils = 60x + 65y Given selling price = Rs. 68.20 => Selling price = 68.20(x+y) Given profit = 10% = SP - CP => 10/100 (60x + 65y) = 68.20(x+y)-(60x + 65y) => 6x + 6.5y = 8.20x + 3.20y =>2.2x = 3.3y => x : y = 3 : 2
Q: The average age of a couple and their son was 40 years, the son got married and a child was born just two years after their marriage. When child turned to 10 years, then the average age of the family becomes 38 years. What was the age of the daughter in law at the time of marriage ? 2920 05b5cc6c6e4d2b4197774de59
5b5cc6c6e4d2b4197774de59- 112 yearstrue
- 210 yearsfalse
- 314 yearsfalse
- 413 yearsfalse
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Answer : 1. "12 years"
Explanation :
Answer: A) 12 years Explanation: Given the average age of couple and their son = 40 => Sum of age (H +W +S) = 40×3 Let the age of daughter in law at the time of marriage = D years Now after 10 years, (H + S +W) + 3×12 + D +12 + 10 = 38×5 178 + D = 190 D = 190 -178 = 12 years
Q: If two line pa + b = 2 and 3a + b = 4 are parallel to each other, then what is the value of p ? 1393 05b5cc6c6e4d2b4197774de54
5b5cc6c6e4d2b4197774de54- 11false
- 22false
- 33true
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Answer : 3. "3"
Explanation :
Answer: C) 3 Explanation: Given two lines are parallel pa+b=2 b=-pa+2..........(1) 3a+b=4 b=-3a+4 ...........(2) m1 = -p m2= -3 The condition for the two lines to be parallel is m1=m2 p = 3
Q: In a row of boys, Haran is eleventh from the left and manoj is seventeenth form the right. When they exchange their places than Haran will be thirteenth from the left. Which of the following will be the new position of Manoj from the right ? 3707 05b5cc6c6e4d2b4197774de4f
5b5cc6c6e4d2b4197774de4f- 111false
- 219true
- 313false
- 417false
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Answer : 2. "19"
Explanation :
Answer: B) 19 Explanation: Here total number of boys in the row = 11 + 19 = 13 + 17 = 30 Here after exchanging the places of Haran & Manoj => Manoj replaces Harans place of 11th from left But in the question he asked Manoj's place from right = 30 - 11 = 19th place.
Q: If E = 5 and READ is coded as 7, then what is the code of 'DEAR' ? 12400 05b5cc6c6e4d2b4197774de4a
5b5cc6c6e4d2b4197774de4a- 16false
- 27true
- 38false
- 49false
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Answer : 2. "7"
Explanation :
Answer: B) 7 Explanation: Here E = 5 = 5/1 = 5 => READ = 18 + 5 + 1 + 4 = 28/4 = 7 => DEAR = 4 + 5 + 1 + 18 = 28/4 = 7
Q: The probability that a bowler bowled a ball from a point will hit by the batsman is ¼. Three such balls are bowled simultaneously towards the batsman from that very point. What is the probability that the batsman will hit the ball ? 2057 05b5cc6c6e4d2b4197774de31
5b5cc6c6e4d2b4197774de31- 137/64true
- 227/56false
- 311/13false
- 49/8false
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Answer : 1. "37/64"
Explanation :
Answer: A) 37/64 Explanation: Probability of not hitting the ball = 1- 1/4 =Then, the probability that the batsman will hit the ball =