GATE Practice Question and Answer

Q: 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 = ? 2397 0

  • 1
    0
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    12
    Correct
    Wrong
  • 4
    10
    Correct
    Wrong
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Answer : 3. "12"
Explanation :

Answer: C) 12 Explanation: Given  1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 Using BODMAS Rule, As multiplication precedes addition, 1 x 0 = 0,  Now, 10 + 0 + 1 + 1 = 10 + 2 = 12.   Hence, 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 x 0 + 1 + 1 = 12.

Q: What will come in place of the question mark (?) in the following number series? 312      231      295      ?      282      257 2397 0

  • 1
    210
    Correct
    Wrong
  • 2
    25
    Correct
    Wrong
  • 3
    246
    Correct
    Wrong
  • 4
    279
    Correct
    Wrong
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Answer : 3. "246"
Explanation :

Answer: C) 246 Explanation: The series follows a pattern that, -92, +82, -72, +62, -52

Q: H.C.F of 4 x 27 x 3125, 8 x 9 x 25 x 7 and 16 x 81 x 5 x 11 x 49 is : 2396 0

  • 1
    360
    Correct
    Wrong
  • 2
    180
    Correct
    Wrong
  • 3
    90
    Correct
    Wrong
  • 4
    120
    Correct
    Wrong
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Answer : 2. "180"
Explanation :

Answer: B) 180 Explanation: 4 x 27 x 3125 = 22 × 33 × 55 ;   8 x 9 x 25 x 7 = 23 × 32 × 52 × 7   16 x 81 x 5 x 11 x 49 = 24 × 34 × 5 × 11 × 72   H.C.F = 22 × 32 × 5 = 180.

Q: A letter lock consists of three rings each marked with six different letters. The number of distinct unsuccessful attempts to open the lock is at the most  ? 2396 0

  • 1
    215
    Correct
    Wrong
  • 2
    268
    Correct
    Wrong
  • 3
    254
    Correct
    Wrong
  • 4
    216
    Correct
    Wrong
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Answer : 1. "215"
Explanation :

Answer: A) 215 Explanation: Since each ring consists of six different letters, the total number of attempts possible with the three rings is = 6 x 6 x 6 = 216. Of these attempts, one of them is a successful attempt.   Maximum number of unsuccessful attempts = 216 - 1 = 215.

Q: Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour ? 2394 0

  • 1
    2 hrs
    Correct
    Wrong
  • 2
    20 min
    Correct
    Wrong
  • 3
    40 min
    Correct
    Wrong
  • 4
    30 min
    Correct
    Wrong
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Answer : 2. "20 min"
Explanation :

Answer: B) 20 min Explanation: In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.

Q: In a certain Business, the profit is 220% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit ? 2394 0

  • 1
    61%
    Correct
    Wrong
  • 2
    75%
    Correct
    Wrong
  • 3
    55%
    Correct
    Wrong
  • 4
    81%
    Correct
    Wrong
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Answer : 1. "61%"
Explanation :

Answer: A) 61% Explanation: Let C.P.= Rs. 100. Then, Profit = Rs.220,  S.P. = Rs.320.   New C.P. = 125% of Rs. 100 = Rs. 125  New S.P. = Rs.320. Profit = Rs. (320 - 125) = Rs. 195   Required percentage = 195320×100== 60.9 =~ 61%

Q: One fathom is equal to how many meters ? 2392 0

  • 1
    1.7699
    Correct
    Wrong
  • 2
    2.0210
    Correct
    Wrong
  • 3
    1.8288
    Correct
    Wrong
  • 4
    2.1212
    Correct
    Wrong
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Answer : 3. "1.8288"
Explanation :

Answer: C) 1.8288 Explanation: One fathom = 1.8288 meters = 6 feet A fathom is a unit of length used especially for measuring the depth of water.

Q: There are 41 students in a class, number of girls is one more than number of guys. we need to form a team of four students. all four in the team cannot be from same gender. number of girls and guys in the team should NOT be equal. How many ways can such a team be made ? 2392 0

  • 1
    49450
    Correct
    Wrong
  • 2
    50540
    Correct
    Wrong
  • 3
    46587
    Correct
    Wrong
  • 4
    52487
    Correct
    Wrong
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Answer : 2. "50540"
Explanation :

Answer: B) 50540 Explanation: Given G + B= 41 and B = G-1 Hence, G = 21 and B = 20Now we have 2 options, 1G and 3M (or) 3G and 1M(2G and 2M or 0G and 4M or 4G and oM are not allowed),   Total : C121×C320+C321×C120= 50540 ways.

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