Answer: C) Only b follows Explanation: Clearly, reducing the number of aspirants for admission to colleges or sending the students of well-to-do families to foreign countries for higher studies, is no proper solution. So, both I and III do not follow. The right solution is to increase the number of colleges so as t accommodate the increasing number of admission-seekers. So, only II follows.

Answer: B) 1/6 Explanation: Total work is given by L.C.M of 72, 48, 36 Total work = 144 units Efficieny of A = 144/72 = 2 units/day Efficieny of B = 144/48 = 3 units/day Efficieny of C = 144/36 = 4 units/day   According to the given data, 2 x p/2 + 3 x p/2 + 2 x (p+6)/3 + 3 x (p+6)/3 + 4 x (p+6)/3 = 144 x (100 - 125/3) x 1/100 3p + 4.5p + 2p + 3p + 4p = 84 x 3 - 54 p = 198/16.5 p = 12 days.   Now, efficency of D = (144 x 125/3 x 1/100)/10 = 6 unit/day (C+D) in p days = (4 + 6) x 12 = 120 unit Remained part of work = (144-120)/144 = 1/6.

Answer: C) 5% Explanation: Let 'R%' be the rate of interest From the given data, 25202400 = 1 + R10041 + R1003⇒1 + R100 = 6360⇒R = 5   Hence, the rate of interest R = 5% per annum.

Resistivity : Resistivity is a measure of the resistance to the flow of electrons.  Conductivity : Conductivity is just the inverse of resistivity, σ = 1/ρ, where σ is conductivity and ρ is resistivity.   Example: Think of a pipe and water, the bigger the pipe, the easier water can flow and thus the lower the resistance.

Answer: A) 54 Explanation: In given Series, all the numbers except 54 are multiples of 5.

Answer: A) 70 kms Explanation: Let the time taken by train be 't' hrs. Then, 40t = 35t + 1560 40t = 35t + 35/4 t = 7/4 hrs Therefore, Required length of the total journey d = s x t = 40 x 7/4 = 70 kms.

Answer: D) Data is not sufficient Explanation: a. P's investment = (80000 x 6 + 60000 x 6) = 840000 for 1 month. b & c. Q's investment = 80% of Rs. 60000 for 8 months. = Rs.(48000 x 8) for 1 month = 384000 for 1 month P : Q = 840000 : 384000 = 35 : 16. But, the total profit is not given, so data is inadequate.

1. How to find Speed(s) if distance(d) & time(t) is given:    Speed (S) = Distance (D)Time (T)     Ex: Find speed if a person travels 4 kms in 2 hrs? Speed = D/T = 4/2 = 2 kmph.   2.  Similarly, we can find distance (d)  if speed (s) & time (t) is given by   Distance (D) = Speed (S) x Time (T)   Ex : Find distance if a person with a speed of 2 kmph in 2 hrs? Distance D = S X T = 2 x 2 = 4 kms.    3.  Similarly, we can find time (t) if speed (s) &  distance (d) is given by   Time (T) = Distance (D)Speed (S)   Ex : Find in what time a person travels 4 kms with a speed of 2 kmph? Time T = D/S = 4/2 = 2 hrs.   4. How to convert  km/hr into m/sec :   P km/hr = P x 518 m/sec   Ex : Convert 36 kmph into m/sec? 36 kmph = 36 x 5/18 = 10 m/sec    5. How to convert  m/sec into km/hr :   P m/sec = P x 185 kmph.   Ex : Convert 10 m/sec into km/hr? 10 m/sec = 10 x 18/5 = 36 kmph.   6.  If the ratio of the speeds of A and B is a:b, then the ratio of the times taken by them to cover the same distance is b : a.   7.  Suppose a man covers a certain distance at x km/ hr and an equal distance at y km/hr . Then, the average speed during the whole journey is 2xyx+y km/hr.