Answer: B) 25000 Explanation: We know that,   One square meter is equal to 10,00,000 sq mm.Given, each mesh is 8mm length and 5mm wideTherefore for each mesh : 8 x 5 = 40 sq mm.So, number of meshes = 100000040 = 25000.

Answer: D) 1000(p - q) + qr Explanation: We need to find the total cost to send r messsages, r > 1000. The first 1000 messsages will cost Rs.p each (Or)  The total cost of first 1000 messsages = Rs.1000p The remaining (r - 1000) messsages will cost Rs.q each (Or) The cost of the (r - 1000) = Rs.(r - 1000)y   Therefore, total cost = 1000p + rq - 1000q = 1000(p - q) + qr

Answer: B) 18.75 % Explanation: Prashanth sold a album for $ 735 and made a profit of 22.5% .CP = 735 x 100/122.5 = Rs. 600New CP = 600 + 120 = Rs. 720New SP = 735 + 120 = Rs. 855. Profit = Rs. 135. profit % = 100 x 135/720 = 18.75%.

Answer: D) Leader Explanation: Here the second one follows the first one. That is a nurse follows a doctor and similarly, a follower follows a leader.   Hence, Doctor : Nurse :: Leader : Follower.

Answer: B) 6 days Explanation: L's 10 days work = 115×10=23   Remaining work = 1-23=13   Now,  work is done by K in one day = 1/18   1/3 work is done by K in  18×13 = 6 days

Answer: C) Only b follows Explanation: Clearly, reducing the number of aspirants for admission to colleges or sending the students of well-to-do families to foreign countries for higher studies, is no proper solution. So, both I and III do not follow. The right solution is to increase the number of colleges so as t accommodate the increasing number of admission-seekers. So, only II follows.

A Temper.

Answer: B) 37.33 sec Explanation: Speed = 108 km/hrenter a tunnel,, means that the train covers a distance equal to its own lengthso (108 x 5/18) = x/4 where x= length of trainhence x = 120 mtrsto pass completely train has to travel a distance = (x + tunnel length) that is 1120 mtrs.so (1120/t) = (108x5/18)t = 37.33 sec