GATE Practice Question and Answer
8Q: Light travels fastest in 1906 05b5cc672e4d2b4197774c09b
5b5cc672e4d2b4197774c09b- 1Airtrue
- 2Waterfalse
- 3Glassfalse
- 4Diamondfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "Air"
Explanation :
Answer: A) Air Explanation: Light travels fastest in Vacuum. The fastest thing in the whole universe is the speed of light in a vacuum like outer space. It is about 2.99 x 108 m/s.
Q: 5 years ago, the mother's age was 3 times of her son's age. 5 years hence, the ratio between the ages of mother and the son becomes 11:5. Find the mother's present age? 1906 05b5cc611e4d2b4197774b67b
5b5cc611e4d2b4197774b67b- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer :
Explanation :
Let the present age's of mother be 'M' and that of her son be 'S'. According to the given data in the question, M - 5 = 3(S - 5) F - 3S = -10 ...............(1) Then given , M + 5 : S + 5 = 11 : 5 => 5M - 11S = 30 ..............(2) From (1) & (2), we get S = 20 Then by substituting S = 20 in (1) or (2), we get M = 50. Hence, the present age of mother is M = 50 years.
Q: Two persons K and L can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days ? 1906 05b5cc6d8e4d2b4197774e7aa
5b5cc6d8e4d2b4197774e7aa- 11/6true
- 21/3false
- 32/3false
- 41/18false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "1/6"
Explanation :
Answer: A) 1/6 Explanation: K's one day's work = 1/30 L's one day's work = 1/45 (K + L)'s one day's work = 1/30 + 1/45 = 1/18 The part of the work completed in 3 days = 3 (1/18) = 1/6.
Q: Compound interest on a certain sum of money at 20% per annum for 2 years is Rs.5995. What is the SI on the same money at 8% per annum for 6 years ? 1905 05b5cc6cae4d2b4197774e0a9
5b5cc6cae4d2b4197774e0a9- 1Rs. 5989false
- 2Rs. 6540true
- 3Rs. 7844false
- 4Rs. 6789false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Rs. 6540"
Explanation :
Answer: B) Rs. 6540 Explanation: Given C.I = 5984, R = 20% , T = 2yrs C.I = P1+201002-1 5984 = => P = (5995x25)/11 P = Rs. 13625 Now S.I = PTR/100 SI = (13625 x 8 x 6)/100 = Rs. 6540
Q: Conditions: I is brother of J K is father of I L is brother of M M is daughter of J , then Who is I to L? 1903 05b5cc777e4d2b419777500bb
5b5cc777e4d2b419777500bb- 1Grand fatherfalse
- 2Uncletrue
- 3Sonfalse
- 4Brotherfalse
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Uncle"
Explanation :
Answer: B) Uncle Explanation:
Q: If the C.I. on a sum for 2 years at 12 1/2 % per annum is Rs. 510, the S.I. on the same sum at the same rate for the same period of time is ? 1903 05b5cc6e0e4d2b4197774eb2a
5b5cc6e0e4d2b4197774eb2a- 1Rs. 580false
- 2Rs. 480true
- 3Rs. 550false
- 4Rs. 470false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "Rs. 480"
Explanation :
Answer: B) Rs. 480 Explanation: Let the sum be Rs. P. Then, P1+252x1002-P= 510 P[982- 1] = 510. Sum = Rs. 1920 So, S.I. = (1920 x 25 x 2) / (2 x 100) = Rs. 480
Q: What is the gram formula mass of K2CO3? 1903 05b5cc632e4d2b4197774b9b8
5b5cc632e4d2b4197774b9b8- 1147false
- 2138true
- 3129false
- 4116false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 2. "138"
Explanation :
Answer: B) 138 Explanation: The gram formula mass of a compound is nothing but the molar mass. The molar mass of K2CO3 (Potassium Carbonate) is given by Atomic weights of individual elements are K (Potassium) = 39 g C (Carbon) = 12 g O (Oxygen) = 16 g Hence, that of K2CO3 = 39(2) + 12 + 16(3) = 78 + 12 + 48 = 138.
Q: Find the next number in the given number series? 2, 19, 0, 21, –2, ? 1902 05b5cc69de4d2b4197774c8f5
5b5cc69de4d2b4197774c8f5- 123true
- 225false
- 327false
- 429false
- Show AnswerHide Answer
- Workspace
- SingleChoice
Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: The given number series 2, 19, 0, 21, –2, ? follows a pattern, 2 2 + 17 = 19 19 - 19 = 0 0 + 21 = 21 21 - 23 = -2 -2 + 25 = 23 Hence, the next number in the series is 23.