GATE Practice Question and Answer
8Q: Translator program used in assembly language 1869 05b5cc64de4d2b4197774bc75
5b5cc64de4d2b4197774bc75- 1Assemblertrue
- 2Interpreterfalse
- 3Compilerfalse
- 4Operating systemfalse
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Answer : 1. "Assembler"
Explanation :
Answer: A) Assembler Explanation: Assemblers are used to translate a program written in a low-level assembly language into a machine code (object code) file so it can be used and executed by the computer. Hence, Assembler is the translator program used in assembly language.
Q: A Bus is running at 9/10 of its own speed reached a place in 22 hours. How much time could be saved if the bus would run at its own speed ? 1868 05b5cc6dde4d2b4197774ea00
5b5cc6dde4d2b4197774ea00- 11.5 hrsfalse
- 21.7 hrsfalse
- 32.2 hrstrue
- 43.5 hrsfalse
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Answer : 3. "2.2 hrs"
Explanation :
Answer: C) 2.2 hrs Explanation: Let the original Speed be "s" kmphAnd the usual time be "t" hrsGiven that if the bus is running at 9s/10 kmph the time is 22 hrs=> [9s/10] x 22 = t x s=> 99/5 = t => t = 19.8 hrs Hence, if bus runs at its own speed, the time saved = 22 - 19.8 = 2.2 hrs.
Q: Rajitha invested 25% more than Santhosh. Santhosh invested 30% less than Raju, who invested Rs. 6,000. What is the ratio of the amount that Rajitha invested to the total amount invested by all of them together ? 1868 05b5cc736e4d2b4197774f850
5b5cc736e4d2b4197774f850- 125 : 114false
- 235 : 103true
- 315 : 108false
- 441 : 94false
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Answer : 2. "35 : 103"
Explanation :
Answer: B) 35 : 103 Explanation: Santhosh's investment = 6000 x 70/100 = Rs.4200Rajitha's investment = 4200 x 5/4 = Rs.5250Therefore, total amount invested = 6000 + 4200 + 5250 = Rs.15450.Required ratio = 5250 : 15450 = 35 : 103.
Q: A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is 1867 05b5cc6d9e4d2b4197774e816
5b5cc6d9e4d2b4197774e816- 130false
- 236false
- 340true
- 442false
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Answer : 3. "40"
Explanation :
Answer: C) 40 Explanation: Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)On dividing (i) by (ii), we get: x = 40 km.
Q: Nine different letters of alphabet are given, words with 5 letters are formed from these given letters. Then, how many such words can be formed which have at least one letter repeated ? 1867 05b5cc6c6e4d2b4197774de0e
5b5cc6c6e4d2b4197774de0e- 143929true
- 259049false
- 315120false
- 40false
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Answer : 1. "43929"
Explanation :
Answer: A) 43929 Explanation: Number of words with 5 letters from given 9 alphabets formed = 95 Number of words with 5 letters from given 9 alphabets formed such that no letter is repeated is = 9P5 Number of words can be formed which have at least one letter repeated = 95 - 9P5 = 59049 - 15120 = 43929
Q: The length, breadth and height of a room are in the ratio 7:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased ? 1867 05b5cc6c6e4d2b4197774de18
5b5cc6c6e4d2b4197774de18- 190%true
- 288%false
- 385%false
- 484%false
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Answer : 1. "90%"
Explanation :
Answer: A) 90% Explanation: Let length, breadth and height of the room be 7, 3, 1 unit respectively. Area of walls = 2(l+b)xh = 2(7+3)x1 = 20 sq. unit. Now, length, breadth and height of room will become 3.5, 6 and 2 respectively. Area of walls = 2(l+b)xh = 2(3.5+6)x2 = 38 sq. unit. % Increase in the area of walls = (38-20)x100/20 = 90%.
Q: 50 men can build a tank in 40days, but though they begin the work together, 5 men quit every ten days. The time needed to build the tank is ? 1867 05b5cc76fe4d2b4197774ff71
5b5cc76fe4d2b4197774ff71- 150 daystrue
- 248 daysfalse
- 347.5 daysfalse
- 449 daysfalse
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Answer : 1. "50 days"
Explanation :
Answer: A) 50 days Explanation: 50 men can build a tank in 40 days Assume 1 man does 1 unit of work in 1 day Then the total work is 50×40 = 2000 units 50 men work in the first 10 days and completes 50×10 = 500 units of work 45 men work in the next 10 days and completes 45×10 = 450 units of work 40 men work in the next 10 days and completes 40×10 = 400 units of work 35 men work in the next 10 days and completes 35×10 = 350 units of work So far 500 + 450 + 400 + 350 = 1700 units of work is completed and Remaining work is 2000 - 1700 = 300 units 30 men work in the next 10 days. In each day, they does 30 units of work. Therefore, additional days required = 300/30 =10 Thus, total 10+10+10+10+10 = 50 days required.
Q: How many squares with sides 1/2 inch long are needed to cover a rectangle that is 4 ft long and 4 ft wide ? 1866 05b5cc74fe4d2b4197774fb49
5b5cc74fe4d2b4197774fb49- 19216true
- 210246false
- 312345false
- 47527false
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Answer : 1. "9216"
Explanation :
Answer: A) 9216 Explanation: It takes four of those little squares -- each one 1/2 inch on a side -- to cover one square inch. That's because each one is 1/2 x 1/2, or 1/4 of a square inch. In a rectangle that is 48 inches by 48 inches, there are 2304 square inches.(1 ft = 12 inches) Since it takes 4 little squares to cover 1 sq inch, then it would need 2304 x 4 squares (1/2 inch on a side each) to cover a rectangle 4 feet by 4 feet. That is 9,216 of those squares.

