GATE Practice Question and Answer

Q: Value of vehicle at end of each year depreciates at the rate of 3/5th of value at the beginning. If Initial value is 10,000Rs then at the end of three years its value is ? 1405 0

  • 1
    Rs. 6000
    Correct
    Wrong
  • 2
    Rs. 3600
    Correct
    Wrong
  • 3
    Rs. 2160
    Correct
    Wrong
  • 4
    Rs. 415
    Correct
    Wrong
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Answer : 3. "Rs. 2160"
Explanation :

Answer: C) Rs. 2160 Explanation: End of first year     :  10000 x (3/5) = Rs. 6000End of second year :  6000 x (3/5) = Rs. 3600End of third year    :  3600 x (3/5) = Rs. 2160

Q: Find the Missing number in the given Series ?   2, 3, 6, 15, ? , 157.5 1405 0

  • 1
    87
    Correct
    Wrong
  • 2
    78.5
    Correct
    Wrong
  • 3
    56.5
    Correct
    Wrong
  • 4
    45
    Correct
    Wrong
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Answer : 4. "45"
Explanation :

Answer: D) 45 Explanation: Here given  2, 3, 6, 15, ? , 157.5 2 x 1.5 = 3 3 x 2  = 6 6 x 2.5 = 15 15 x 3 = 45 45 x 3.5 = 157.5 Therefore, the missing number is 45

Q: Rangaswamy Cup is associated with 1404 0

  • 1
    Football
    Correct
    Wrong
  • 2
    Badminton
    Correct
    Wrong
  • 3
    Cricket
    Correct
    Wrong
  • 4
    Hockey
    Correct
    Wrong
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Answer : 4. "Hockey"
Explanation :

Answer: D) Hockey Explanation:

Q: What is the bond order of O2? 1404 0

  • 1
    1.5
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    2.5
    Correct
    Wrong
  • 4
    1
    Correct
    Wrong
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Answer : 2. "2"
Explanation :

Answer: B) 2 Explanation: The number of bonds between a pair of atoms is called the bond order. Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two. When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5  the average of an S-O single bond in one Lewis structure and an S=O double bond in the other. In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O2 molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.

Q: Which of the following vitamins are water soluble? 1402 0

  • 1
    Vitamins B & C
    Correct
    Wrong
  • 2
    Vitamins K, D & C
    Correct
    Wrong
  • 3
    Vitamins A, D & K
    Correct
    Wrong
  • 4
    Vitamins A, K, B, C & D
    Correct
    Wrong
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Answer : 1. "Vitamins B & C"
Explanation :

Answer: A) Vitamins B & C Explanation: Vitamins are essential nutrients found in foods. They perform specific and vital functions in a variety of body systems, and are crucial for maintaining optimal health.   The two different types of vitamins are fat-soluble vitamins and water-soluble vitamins.   Fat-soluble vitamins :  Vitamins A, D, E and K — dissolve in fat before they are absorbed in the bloodstream to carry out their functions. Excesses of these vitamins are stored in the liver, and are not needed every day in the diet.   Water-soluble vitamins : Vitamins dissolve in water and are not stored by the body. Since they are eliminated in urine, we require a continuous daily supply in our diet. The water-soluble vitamins include the vitamin B-complex group and vitamin C.   Water-soluble vitamins are easily destroyed or washed out during food storage or preparation.

Q: There are two numbers such that the sum of twice the first number and thrice the second number is 100 and sum of thrice the first number and twice the second number is 120. Which is the larger number ? 1401 0

  • 1
    32
    Correct
    Wrong
  • 2
    24
    Correct
    Wrong
  • 3
    26
    Correct
    Wrong
  • 4
    38
    Correct
    Wrong
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Answer : 1. "32"
Explanation :

Answer: A) 32 Explanation: Let the first number be K and second number be LThen, 2K + 3L = 100.....(1)3K + 2L = 120.......(2)solving (1)&(2), we getK = 32 and L = 12 Hence the largest number is 32.

Q: The breadth of a rectangular field is 75% of its length. If perimeter of the field is 1050 m, what will be th area of field ? 1398 0

  • 1
    65700 sq.m
    Correct
    Wrong
  • 2
    54500 sq.m
    Correct
    Wrong
  • 3
    78700 sq.m
    Correct
    Wrong
  • 4
    67500 sq.m
    Correct
    Wrong
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Answer : 4. "67500 sq.m"
Explanation :

Answer: D) 67500 sq.m Explanation: Let the length be 'l' and breadth be 'b'. b = l × 3/4__________(a) 2(l+b) = 1050 l+b = 525___________(b) From equations (a) and (b), l = 300m, b = 225 m Area = l × b = 300 × 225 = 67500 sq.m.

Q: Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ? 1397 0

  • 1
    23
    Correct
    Wrong
  • 2
    24
    Correct
    Wrong
  • 3
    25
    Correct
    Wrong
  • 4
    26
    Correct
    Wrong
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Answer : 4. "26"
Explanation :

Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.

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