GATE Practice Question and Answer
8Q: Value of vehicle at end of each year depreciates at the rate of 3/5th of value at the beginning. If Initial value is 10,000Rs then at the end of three years its value is ? 1405 05b5cc715e4d2b4197774f472
5b5cc715e4d2b4197774f472- 1Rs. 6000false
- 2Rs. 3600false
- 3Rs. 2160true
- 4Rs. 415false
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Answer : 3. "Rs. 2160"
Explanation :
Answer: C) Rs. 2160 Explanation: End of first year : 10000 x (3/5) = Rs. 6000End of second year : 6000 x (3/5) = Rs. 3600End of third year : 3600 x (3/5) = Rs. 2160
Q: Find the Missing number in the given Series ? 2, 3, 6, 15, ? , 157.5 1405 05b5cc6bce4d2b4197774d8ac
5b5cc6bce4d2b4197774d8ac- 187false
- 278.5false
- 356.5false
- 445true
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Answer : 4. "45"
Explanation :
Answer: D) 45 Explanation: Here given 2, 3, 6, 15, ? , 157.5 2 x 1.5 = 3 3 x 2 = 6 6 x 2.5 = 15 15 x 3 = 45 45 x 3.5 = 157.5 Therefore, the missing number is 45
Q: Rangaswamy Cup is associated with 1404 05b5cc6a5e4d2b4197774ccd1
5b5cc6a5e4d2b4197774ccd1- 1Footballfalse
- 2Badmintonfalse
- 3Cricketfalse
- 4Hockeytrue
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Answer : 4. "Hockey"
Explanation :
Answer: D) Hockey Explanation:
Q: What is the bond order of O2? 1404 05b5cc65ee4d2b4197774be02
5b5cc65ee4d2b4197774be02- 11.5false
- 22true
- 32.5false
- 41false
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Answer : 2. "2"
Explanation :
Answer: B) 2 Explanation: The number of bonds between a pair of atoms is called the bond order. Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two. When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5 the average of an S-O single bond in one Lewis structure and an S=O double bond in the other. In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O2 molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.
Q: Which of the following vitamins are water soluble? 1402 05b5cc66de4d2b4197774bf91
5b5cc66de4d2b4197774bf91- 1Vitamins B & Ctrue
- 2Vitamins K, D & Cfalse
- 3Vitamins A, D & Kfalse
- 4Vitamins A, K, B, C & Dfalse
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Answer : 1. "Vitamins B & C"
Explanation :
Answer: A) Vitamins B & C Explanation: Vitamins are essential nutrients found in foods. They perform specific and vital functions in a variety of body systems, and are crucial for maintaining optimal health. The two different types of vitamins are fat-soluble vitamins and water-soluble vitamins. Fat-soluble vitamins : Vitamins A, D, E and K — dissolve in fat before they are absorbed in the bloodstream to carry out their functions. Excesses of these vitamins are stored in the liver, and are not needed every day in the diet. Water-soluble vitamins : Vitamins dissolve in water and are not stored by the body. Since they are eliminated in urine, we require a continuous daily supply in our diet. The water-soluble vitamins include the vitamin B-complex group and vitamin C. Water-soluble vitamins are easily destroyed or washed out during food storage or preparation.
Q: There are two numbers such that the sum of twice the first number and thrice the second number is 100 and sum of thrice the first number and twice the second number is 120. Which is the larger number ? 1401 05b5cc736e4d2b4197774f892
5b5cc736e4d2b4197774f892- 132true
- 224false
- 326false
- 438false
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Answer : 1. "32"
Explanation :
Answer: A) 32 Explanation: Let the first number be K and second number be LThen, 2K + 3L = 100.....(1)3K + 2L = 120.......(2)solving (1)&(2), we getK = 32 and L = 12 Hence the largest number is 32.
Q: The breadth of a rectangular field is 75% of its length. If perimeter of the field is 1050 m, what will be th area of field ? 1398 05b5cc6c8e4d2b4197774df0a
5b5cc6c8e4d2b4197774df0a- 165700 sq.mfalse
- 254500 sq.mfalse
- 378700 sq.mfalse
- 467500 sq.mtrue
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Answer : 4. "67500 sq.m"
Explanation :
Answer: D) 67500 sq.m Explanation: Let the length be 'l' and breadth be 'b'. b = l × 3/4__________(a) 2(l+b) = 1050 l+b = 525___________(b) From equations (a) and (b), l = 300m, b = 225 m Area = l × b = 300 × 225 = 67500 sq.m.
Q: Hemavathi gets 3 marks for each right sum and loses 2 marks for each wrong sum. He attempts 35 sums and obtains 60 marks. The number of sums attempted correctly is ? 1397 05b5cc73de4d2b4197774f90c
5b5cc73de4d2b4197774f90c- 123false
- 224false
- 325false
- 426true
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Answer : 4. "26"
Explanation :
Answer: D) 26 Explanation: Let, Hema attempted 'k' sum correctly, then k x 3 -2 x(35-k) = 605k = 130k = 26 so 26 correct sums.

