Answer: C) 415 Explanation: Given numbers are 585 546 514 404 206 369Then interchanging the 1st and 3rd digits of the given numbers, we get585 645 415 404 602 963Now, arranging them in ascending order963 645 602 585 415 404Then the last second number is 415.

A number of possible explanations for why manhole covers are round include :   1. A round manhole cover cannot fall through its circular opening, whereas a square, rectangular, or oval manhole cover could fall in if it were inserted diagonally in the hole. 2. Circular covers don’t need to be rotated or precisely aligned when placing them on the opening. 3. A round manhole cover is easily moved and rolled. 4. Human beings have a roughly circular cross-section. 5. Round tubes are the strongest shape against the compression of the earth around them, so the cover of the tube would naturally be round as well. 6. It’s easier to dig a circular hole.

Answer: B) 2 Explanation: The number of bonds between a pair of atoms is called the bond order. Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two. When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5  the average of an S-O single bond in one Lewis structure and an S=O double bond in the other. In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O2 molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.

Answer: A) Rs. 2000 Explanation: Given, Compound rate, R = 10% per annumTime = 2 yearsC.I = Rs. 420Let P be the required principal.A = (P+C.I)Amount, A = P1 + r100n (P+C.I) = P1 + 101002 (P+420) = P[11/10][11/10] P-1.21P = -420 0.21P = 420 Hence, P = 420/0.21 = Rs. 2000

Answer: C) 20 Explanation: We know that  40% = 40100 = 25⇒25 x 244 x ? = 48? = 48 x 5 x 42 x 24 = 20

Answer: D) All of these Explanation:    K    |    J -- L    |    I -- D -- B Here I is female J, K, L & D , B are males Then from the above conditions, All of the given statements are true.

Answer: D) 17 Explanation: Any two digit number can be written as (10P + Q), where P is the digit in the tens place and Q is the digit in the units place.P + Q = 8 ----- (1)(10Q + P) - (10P + Q) = 549(Q - P) = 54(Q - P) = 6 ----- (2)Solve (1) and (2) P = 1 and Q = 7The required number is = 17

Answer: C) Rs. 2160 Explanation: End of first year     :  10000 x (3/5) = Rs. 6000End of second year :  6000 x (3/5) = Rs. 3600End of third year    :  3600 x (3/5) = Rs. 2160