Answer: B) 15.69 cm Explanation: Draw the two chords as shown in the figure. Let O be the center of the circle. Draw OC perpendicular to both chords. That divides the two chords in half.So CD = 10 and AB = 14. Draw radii OA and OD, both equal to radius r.We are given that BC = 5, the distance between the two chords. LetOB = x. We use the Pythagorean theorem on right triangle ABO AO² = AB² + OB² r² = 14² + x² We use the Pythagorean theorem on right triangle DCO DO² = CD² + OC² We see that OC = OB+BC = x+5, so r² = 10² + (x+5)² So we have a system of two equations: r² = 14² + x² r² = 10² + (x+5)² Since both left sides equal r², set the right sidesequal to each other. 14² + x² = 10² + (x+5)² 196 + x² = 100 + x² + 10x + 25 196 = 125 + 10x 71 = 10x 7.1 = x r² = 14² + x² r² = 196 + (7.1)² r² = 196 + 50.41 r² = 246.41 r = √246.41 r = 15.69745202 cm

Answer: C) Neither A nor B follows Explanation: There is no indication that Indian scientists are incapable of developing enzymes. There could be any number of reasons why Indian scientists used Russian enzymes. So conclusion A does not follow. In addition, cost is not discussed in the passage at all. There is no mention of a correlation between cost and extraction of proteins. Thus, conclusion B does not follow either.

Answer: C) 20 Explanation: We know that  40% = 40100 = 25⇒25 x 244 x ? = 48? = 48 x 5 x 42 x 24 = 20

Answer: B) 2 Explanation: The number of bonds between a pair of atoms is called the bond order. Bond orders can be calculated from Lewis structures, which are the heart of the valence-bond model. Oxygen, for example, has a bond order of two. When there is more than one Lewis structure for a molecule, the bond order is an average of these structures. The bond order in sulfur dioxide, for example, is 1.5  the average of an S-O single bond in one Lewis structure and an S=O double bond in the other. In molecular orbital theory, we calculate bond orders by assuming that two electrons in a bonding molecular orbital contribute one net bond and that two electrons in an antibonding molecular orbital cancel the effect of one bond. We can calculate the bond order in the O2 molecule by noting that there are eight valence electrons in bonding molecular orbitals and four valence electrons in antibonding molecular orbitals in the electron configuration of this molecule. Thus, the bond order is two.

Answer: A) Ribosomes Explanation: Ribosomes are present in prokaryotic cells. These are organelles which consist of two subunits. They are present in both Eukaryotic and Prokaryotic cells. They are made up of RNA and proteins and present in the cytoplasm and on the membranes and are involved in protein synthesis.

Answer: A) Vitamins B & C Explanation: Vitamins are essential nutrients found in foods. They perform specific and vital functions in a variety of body systems, and are crucial for maintaining optimal health.   The two different types of vitamins are fat-soluble vitamins and water-soluble vitamins.   Fat-soluble vitamins :  Vitamins A, D, E and K — dissolve in fat before they are absorbed in the bloodstream to carry out their functions. Excesses of these vitamins are stored in the liver, and are not needed every day in the diet.   Water-soluble vitamins : Vitamins dissolve in water and are not stored by the body. Since they are eliminated in urine, we require a continuous daily supply in our diet. The water-soluble vitamins include the vitamin B-complex group and vitamin C.   Water-soluble vitamins are easily destroyed or washed out during food storage or preparation.

Answer: C) Half work Explanation: A can do the work = 18 daysB can do the work = 18/2 = 9 days(A + B)'s 1 day work = 1/18 + 1/9 = 1/6=> In 3 days = 3x1/6 = 1/2 work is completed.

Answer: B) 24 kmph Explanation: Average speed=total distance/total timeLet distance to store be  Kthen, total time =(K/20)+(K/30)=K/12and, total time =(2K)so average speed= 2K / (K/12) = 24kmph.