Answer: B) 2160 Explanation: Let the number be 3p and 5p ATQ, 8p = 2 x 48 p = 96/8 p = 12   The numbers are 36 and 60.   Hence, the product of the numbers = 36 x 60 = 2160.

Answer: A) 66 sec Explanation: For ticking 6 times, there are 5 intervals. Each interval has time duration of 30/5 = 6 secs At 12 o'clock, there are 11 intervals,so total time for 11 intervals = 11 x 6 = 66 secs.

Answer: C) 16/25 Explanation: If there are total 100 candidates, 40 candidates are really capable and 60 candidates are incapable.Of the candidates who are really capable = 80% 40*(80/100)=32 pass the test andof the incapable= 30%60*(30/100)=18 pass the test.Total candidates who passed the test = 32+18 = 50The proportion of the really capable students who can pass the test to the total students who can pass = 32/50 = 16/25.

Answer: A) Stillness Explanation: Given Transition is to Change, and we know that Transition and change are Synonyms. Similarly, Immobility means not moving and synonym of immobility are motionlessness, stillness,...   Hence, Transition is to change as immobility is to stillness.

Answer: C) 7556 Explanation: Let ratio of the incomes of Pavan and Amar be 4x and 3x and Ratio of their expenditures be 3y and 2y 4x - 3y = 1889 ......... I and 3x - 2y = 1889 ...........II I and II y = 1889 and x = 1889 Pavan's income = 7556

Answer: A) 12 & 7 Explanation: x – y = 5 4x – 6y = 6 x = 12 y = 7

Answer: D) 4 3/8 km Explanation: Relative Speed = 5 ¾ - 4 ½ = 1 ¼ Time = 3 ½ h. Distance = 5/4 x 7/2 = 35/8 = 4 3/8 km.

Answer: B) J, L Explanation: This question concerns a committee’s decision about which five of eight areas of expenditure to reduce. The question requires you to suppose that K and N are among the areas that are to be reduced, and then to determine which pair of areas could not also be among the five areas that are reduced. The fourth condition given in the passage on which this question is based requires that exactly two of K, N, and J are reduced. Since the question asks us to suppose that both K and N are reduced, we know that J must not be reduced: Reduced         ::      K, NNot reduced   ::      J The second condition requires that if L is reduced, neither N nor O is reduced. So L and N cannot both be reduced. Here, since N is reduced, we know that L cannot be. Thus, adding this to what we’ve determined so far, we know that J and L are a pair of areas that cannot both be reduced if both K and N are reduced: Reduced        ::      K, NNot reduced  ::      J, L Answer choice (B) is therefore the correct answer.