GATE Practice Question and Answer
8Q: A man spend Rs. 810 in buying trouser at Rs. 70 each and shirt at Rs. 30 each. What will be the ratio of trouser and shirt when the maximum number of trouser is purchased ? 3431 05b5cc731e4d2b4197774f7b5
5b5cc731e4d2b4197774f7b5- 11:3false
- 22:1false
- 33:2true
- 42:3false
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Answer : 3. "3:2"
Explanation :
Answer: C) 3:2 Explanation: Let us assume S as number of shirts and T as number of trousersGiven that each trouser cost = Rs.70 and that of shirt = Rs.30Therefore, 70 T + 30 S = 810=> 7T + 3S = 81......(1)T = ( 81 - 3S )/7 We need to find the least value of S which will make (81 - 3S) divisible by 7 to get maximum value of TSimplifying by taking 3 as common factor i.e, 3(27-S) / 7In the above equation least value of S as 6 so that 27- 3S becomes divisible by 7 Hence T = (81-3xS)/7 = (81-3x6)/7 = 63/7 = 9 Hence for S, put T in eq(1), we getS = 81-7(9)/3 = 81-63 / 3 = 18/3 = 6.The ratio of T:S = 9:6 = 3:2.
Q: In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 600 m ? 3427 05b5cc6e5e4d2b4197774ed42
5b5cc6e5e4d2b4197774ed42- 1127.5 mtrue
- 2254 mfalse
- 3184 mfalse
- 4212 mfalse
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Answer : 1. "127.5 m"
Explanation :
Answer: A) 127.5 m Explanation: When A runs 1000 m, B runs 900 m and when B runs 800 m, C runs 700 m. When B runs 900 m, distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 m. In a race of 1000 m, A beats C by (1000 - 787.5) = 212.5 m to C. In a race of 600 m, the number of meters by which A beats C = (600 x 212.5)/1000 = 127.5 m.
Q: Solve the Riddle :: Three men were on a boat that was stuck one mile from the shore. One was afraid of Sharks. The other couldn't Swim. And the last one didn't have a life jacket. However, they reached the shore without any problems. How did they do it? 3426 05b5cc69fe4d2b4197774c9dc
5b5cc69fe4d2b4197774c9dc- Show AnswerHide Answer
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Answer :
Explanation :
They walked and did this. It was never specified that the boat was at sea. Since this logic is observed by them to tackle situation.
Q: Which statement best describes an O3 molecule? 3412 05b5cc6b3e4d2b4197774d432
5b5cc6b3e4d2b4197774d432- 1The double bond in ozone switches back and forth between the two outer oxygen atomsfalse
- 2An ozone molecule contains one single bond and one double bondtrue
- 3Each atom in ozone is connected to another atom by 1.5 bonds.false
- 4Nonefalse
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Answer : 2. "An ozone molecule contains one single bond and one double bond"
Explanation :
Answer: B) An ozone molecule contains one single bond and one double bond Explanation: Ozone molecule has one single bond and one double bond.
Q: A batsman in his 17th innings makes a score of 85 and their by increasing his average by 3. What is his average after the 17th innings ? 3399 05b5cc6e9e4d2b4197774ee01
5b5cc6e9e4d2b4197774ee01- 134false
- 236false
- 335false
- 437true
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Answer : 4. "37"
Explanation :
Answer: D) 37 Explanation: 16x + 85 = 17(x + 3) x = 34 + 3 = 37
Q: If NAMO = 172 and OM = 56 then, SHIVAY = ? 3388 05b5cc6cee4d2b4197774e237
5b5cc6cee4d2b4197774e237- 1606false
- 2415false
- 3504true
- 4404false
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Answer : 3. "504"
Explanation :
Answer: C) 504 Explanation: (COUNTING OF LETTERS) NAMO = 14 + 1 + 13 + 15 = 43 x 4 = 172, OM = 15 + 13 = 28 x 2 = 56, SHIVAY = 19 + 8 + 9 + 22 + 1 + 25 = 84 x 6 = 504
Q: The wildcard in a WHERE clause is useful when 3383 05b5cc65ee4d2b4197774be3b
5b5cc65ee4d2b4197774be3b- 1An exact match is not possible in a SELECT statement.true
- 2An exact match is necessary in a CREATE statement.false
- 3An exact match is not possible in a CREATE statement.false
- 4An exact match is necessary in a SELECT statement.false
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Answer : 1. "An exact match is not possible in a SELECT statement."
Explanation :
Answer: A) An exact match is not possible in a SELECT statement. Explanation:
Q: In a regular week, there are 5 working days and for each day, the working hours are 8. A man gets Rs. 2.40 per hour for regular work and Rs. 3.20 per hours for overtime. If he earns Rs. 432 in 4 weeks, then how many hours does he work for ? 3380 05b5cc74fe4d2b4197774fb35
5b5cc74fe4d2b4197774fb35- 1145false
- 2165false
- 3175true
- 4135false
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Answer : 3. "175"
Explanation :
Answer: C) 175 Explanation: Given that, working days = 5 working hours = 8 A man get rupess per hour is Rs.2.40 So in one day the man get total rupees is 2.40 x 8 = 19.2 So in 5 days week the man get total rupees is 19.2 x 5 = 96 So in 4 week the man get total rupees is 96 x 4 = 384 So the man worked for = 160hours in 4 weeks But given that the man earned Rs.432 Hence remaning money is (432-384 = 48)which is earn by doing overtime work Overtime hours = 48/3.20 = 15 So total worked hours is = 15 + 160 = 175.