GATE Practice Question and Answer
8Q: A person sold two cows each for Rs.9900. If he gained 10% on one and lost 20% on the other, then which of the following is true ? 3142 05b5cc6dde4d2b4197774e9e2
5b5cc6dde4d2b4197774e9e2- 1He lost Rs. 200false
- 2He gained Rs. 200false
- 3Neither he gained nor lostfalse
- 4None of the abovetrue
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Answer : 4. "None of the above"
Explanation :
Answer: D) None of the above Explanation: In first he got Rs. 990 But in second he lost Rs. 1980 So he lost Rs. 990.
Q: Happiness is to 517768399 as senipah is to 3140 05b5cc64de4d2b4197774bc57
5b5cc64de4d2b4197774bc57- 19836715false
- 29386615false
- 39386715true
- 49386517false
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Answer : 3. "9386715"
Explanation :
Answer: C) 9386715 Explanation: If each consecutive letter in "happiness" relates to the consecutive numbers in 517768399, then H=5, A=1, P=7, I=6, N=8, E=3 and S=9. Using the numbers that relate to the letters in 'senipah', you will arrive at SENIPAH = 9386715. Hence, Happiness is to 517768399 as senipah is to 9386715.
Q: Which pair of atoms has the highest electronegativity difference? (Calcium's electronegativity is 1.0 Fluorine's electronegativity is 4.0 Hydrogen's electronegativity is 2.2 Sodium's electronegativity is 0.93) 3138 05b5cc669e4d2b4197774bf7c
5b5cc669e4d2b4197774bf7c- 1F-Ffalse
- 2Ca-Ffalse
- 3H-Ffalse
- 4Na-Ftrue
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Answer : 4. "Na-F"
Explanation :
Answer: D) Na-F Explanation: F-F = 4 - 4 = 0 Ca-F = 4 - 1 = 3.0 H-F = 4 - 2.2 = 1.8 Na-F = 4 - 0.93 = 3.07 Hence, the highest electronegativity difference is in Na-F.
Q: In a class 60% of the students pass in English and 45% pass in Hindi. If 25% of them pass in both subjects, what percentage of the students fail in both the subjects? 3136 15b5cc601e4d2b4197774b440
5b5cc601e4d2b4197774b440- 120%true
- 225%false
- 330%false
- 415%false
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Answer : 1. "20%"
Explanation :
Answer: A) 20% Explanation: Percentage of students passed in English = 60% Percentage of students passed in Hindi = 45% Percentage of students passed in both subjects = 25% ATQ, Percentage of students passed in only English = 60 - 25 = 35% Percentage of students passed in only Hindi = 45 - 25 = 20% Therefore, Percentage of students failed = 100 - (35 + 25 + 20) = 100 - 80 = 20%.
Q: A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ? 3136 05b5cc71be4d2b4197774f4fe
5b5cc71be4d2b4197774f4fe- 1Rs. 404.80true
- 2Rs. 536.80false
- 3Rs.440false
- 4Rs. 160false
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Answer : 1. "Rs. 404.80"
Explanation :
Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
Q: Equal quantities of three mixtures of milk and water are mixed in the ratio 1:2, 2:3 and 3:4. The ratio of water and milk in the mixture is ? 3133 05b5cc73ae4d2b4197774f8c9
5b5cc73ae4d2b4197774f8c9- 1193 : 122true
- 297 : 102false
- 3115 : 201false
- 4147 : 185false
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Answer : 1. "193 : 122"
Explanation :
Answer: A) 193 : 122 Explanation: Given the three mixtures ratio as (1:2),(2:3),(3:4) (1+2),(2+3),(3+4) Total content = 3,5,7 Given equal quantities of the three mixtures are mixed, then LCM of 3, 5, 7 = 105 105/3 = 35 , 105/5 = 21 , 105/7 = 15 Now, the individual equal quantity ratios are (35x1, 35x2), (21x2, 21x3), (15x3, 15x4) i.e (35,70), (42,63), (45,60) So overall mixture ratio of milk and water is 35+42+45 : 70+63+60 122:193 But in the question asked the ratio of water to milk = 193 : 122
Q: P and Q were assigned to do a work for an amount of 1200. P alone can do it in 15 days while Q can do it in 12 days. With the help of R they finish the work in 6 days. Find the share of R ? 3133 05b5cc731e4d2b4197774f814
5b5cc731e4d2b4197774f814- 1120true
- 2240false
- 3360false
- 4180false
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Answer : 1. "120"
Explanation :
Answer: A) 120 Explanation: 1/15 + 1/12 + 1/R = 1/6, we got R = 60 (it means R will take 60 days to complete the work alone) so ratio of work done by P:Q:R = 1/15 : 1/12 : 1/60 = 5 : 4 : 1 so R share = (1/10) x 1200 = 120.
Q: A does half as much work as Band C does half as much work as A and B together. If C alone can finish the work in 40 days, then together ,all will finish the work in ? 3131 05b5cc728e4d2b4197774f714
5b5cc728e4d2b4197774f714- 117 + 4/7 daysfalse
- 213 + 1/3 daystrue
- 315 + 3/2 daysfalse
- 416 daysfalse
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Answer : 2. "13 + 1/3 days"
Explanation :
Answer: B) 13 + 1/3 days Explanation: C alone can finish the work in 40 days.As given C does half as much work as A and B together => (A + B) can do it in 20 days(A + B)s 1 days wok = 1/20.A's 1 days work : B's 1 days Work = 1/2 : 1 = 1:2(given)A's 1 day’s work = (1/20) x (1/3) = (1/60) [Divide 1/20 in the raio 1:2]B's 1 days work = (1/20) x (2/3) = 1/30(A+B+C)'s 1 day's work = (1/60) + (1/30) + (1/40) = 9/120 = 3/40 All the three together will finish it in 40/3 = 13 and 1/3 days.