GATE Practice Question and Answer
8Q: Which pair of atoms has the highest electronegativity difference? (Calcium's electronegativity is 1.0 Fluorine's electronegativity is 4.0 Hydrogen's electronegativity is 2.2 Sodium's electronegativity is 0.93) 3728 05b5cc669e4d2b4197774bf7c
5b5cc669e4d2b4197774bf7c- 1F-Ffalse
- 2Ca-Ffalse
- 3H-Ffalse
- 4Na-Ftrue
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Answer : 4. "Na-F"
Explanation :
Answer: D) Na-F Explanation: F-F = 4 - 4 = 0 Ca-F = 4 - 1 = 3.0 H-F = 4 - 2.2 = 1.8 Na-F = 4 - 0.93 = 3.07 Hence, the highest electronegativity difference is in Na-F.
Q: Select the correct statement about cellular respiration? 3728 05b5cc6a3e4d2b4197774cc34
5b5cc6a3e4d2b4197774cc34- 1All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide moleculetrue
- 2All the carbon atoms in glucose ultimately incorporated during cellular respiration into NADH moleculefalse
- 3All the carbon atoms in glucose ultimately incorporated during cellular respiration into ATP moleculefalse
- 4All the carbon atoms in glucose ultimately incorporated during cellular respiration into water moleculefalse
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Answer : 1. "All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule"
Explanation :
Answer: A) All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecule Explanation: All the carbon atoms in glucose ultimately incorporated during cellular respiration into carbon dioxide molecules.
Q: The study of Heavenly bodies is called 3722 05b5cc6a2e4d2b4197774cbc7
5b5cc6a2e4d2b4197774cbc7- 1Astronomytrue
- 2Astrologyfalse
- 3Astrophysicsfalse
- 4Astronauticsfalse
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Answer : 1. "Astronomy"
Explanation :
Answer: A) Astronomy Explanation: Astronomy is the study of planets and heavenly bodies. Historically, astronomy has focused on observations of heavenly bodies. It is a close cousin to astrophysics. Succinctly put, astrophysics involves the study of the physics of astronomy and concentrates on the behavior, properties and motion of objects out there.
Q: In an election between two candidates K and L, the number of valid votes received by K exceeds those received by L by 15% of the total number of votes polled. If 20% of the votes polled were invalid and a total of 8720 votes were polled, then how many valid votes did L get ? 3722 05b5cc6d7e4d2b4197774e6fb
5b5cc6d7e4d2b4197774e6fb- 13241false
- 22457false
- 32642false
- 42834true
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Answer : 4. "2834"
Explanation :
Answer: D) 2834 Explanation: Let the total number of votes polled in the election be 100k.Number of valid votes = 100k - 20% (100k) = 80kLet the number of votes polled in favour of K and L be a and b respectively.a - b = 15% (100k) => a = b + 15k=> a + b = b + 15k + bNow, 2b + 15k = 80k and hence b = 32.5kIt is given that 100k = 872032.5k = 32.5k/100k x 8720 = 2834 The number of valid votes polled in favour of L is 2834.
Q: A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss ? 3712 05b5cc71be4d2b4197774f4fe
5b5cc71be4d2b4197774f4fe- 1Rs. 404.80true
- 2Rs. 536.80false
- 3Rs.440false
- 4Rs. 160false
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Answer : 1. "Rs. 404.80"
Explanation :
Answer: A) Rs. 404.80 Explanation: Let C1 be the cost price of the first article and C2 be the cost price of the second article.Let the first article be sold at a profit of 22%, while the second one be sold at a loss of 8%. We know, C1 + C2 = 600.The first article was sold at a profit of 22%. Therefore, the selling price of the first article = C1 + (22/100)C1 = 1.22C1The second article was sold at a loss of 8%. Therefore, the selling price of the second article = C2 - (8/100)C2 = 0.92C2. The total selling price of the first and second article = 1.22C1 + 0.92C2. As the merchant did not make any profit or loss in the entire transaction, his combined selling price of article 1 and 2 is the same as the cost price of article 1 and 2. Therefore, 1.22C1 + 0.92C2 = C1+C2 = 600As C1 + C2 = 600, C2 = 600 - C1. Substituting this in 1.22C1 + 0.92C2 = 600, we get1.22C1 + 0.92(600 - C1) = 600or 1.22C1 - 0.92C1 = 600 - 0.92*600or 0.3C1 = 0.08*600 = 48or C1 = 48/(0.3) = 160.If C1 = 160, then C2 = 600 - 160 = 440.The item that is sold at loss is article 2. The selling price of article 2 = 0.92*C2 = 0.92*440 = 404.80.
Q: _ tu _ rt _ s _ _ usrtu _ 3704 05b5cc6d9e4d2b4197774e843
5b5cc6d9e4d2b4197774e843- 1rsutrrfalse
- 2rsurtrfalse
- 3rsurtstrue
- 4rtusrufalse
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Answer : 3. "rsurts"
Explanation :
Answer: C) rsurts Explanation: The series rtus/rtus/rtus/rtus. Thus, the pattern 'rtus' is repeated.
Q: A 300m race is held between two players running 3m/s and 5m/s in swimming pool of 50m long. how many times the two player meet in opposite direction till the faster one completes the race ? 3697 05b5cc754e4d2b4197774fb77
5b5cc754e4d2b4197774fb77- 13 timestrue
- 24 timesfalse
- 35 timesfalse
- 42 timesfalse
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Answer : 1. "3 times"
Explanation :
Answer: A) 3 times Explanation: Let us assume A is the faster and B is slower, A takes 10s to finish a lap of 50 m, B takes 17s(approx) to finish a lap of 50 m.So at 11th sec A starts his 2nd lap by the time B will be in between so that is the first time they will meet each other, at 21st sec A starts his 3rd lap by the time B will be coming back to finish his 2nd lap. So that is the second time they meet in opposite. Then at 31st sec A will start his 4th lap by the time B would not even finish 2nd lap as he take 34(2*17) sec to finish 2 laps. So at 35th sec B will start his 3rd lap by the time A will be coming back to finish his 4th lap in the half way so they will meet 3rd time. At 41st sec A will start its fifth lap by the time B will be going to finish 3rd lap in same direction. At 50th second both will complete A's 5th lap and B's 3rd lap. So they will start next lap(A's 6th and B's 4th) from the same point in same direction. And A will finish the race after completing 300m(6*50) total distance and then they wont meet opposite to each other. So totally they met 3 times in opposite direction.
Q: First Bank to introduce Credit Card in India 3688 05b5cc6b9e4d2b4197774d743
5b5cc6b9e4d2b4197774d743- 1HSBC Bankfalse
- 2ICICI Bankfalse
- 3State Bank of Indiafalse
- 4Central Bank of Indiatrue
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Answer : 4. "Central Bank of India"
Explanation :
Answer: D) Central Bank of India Explanation: First Bank to introduce Credit Card in India - Central Bank of India First Bank to introduce ATM - HSBC, 1987 First Bank to introduce Internet Banking - ICICI Bank First Bank to introduce Mutual Funds - State Bank of India

