GATE Practice Question and Answer

Q: If the rate increases by 2%, the simple interest received on a sum of money increases by Rs. 108. If the time period is increased by 2 years, the simple interest on the same sum increases by Rs.180. The sum is ? 3504 0

  • 1
    Rs. 540
    Correct
    Wrong
  • 2
    Rs. 415
    Correct
    Wrong
  • 3
    Rs. 404
    Correct
    Wrong
  • 4
    Data is not sufficient
    Correct
    Wrong
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Answer : 4. "Data is not sufficient"
Explanation :

Answer: D) Data is not sufficient Explanation: Let the sum be Rs. p, rate be R% p.a. and time be T years. Then,  P×T×(R+2)100-P×T×R100=108  ⇒2PT= 10800  ...... (1)  And,   P×R×(T+2)100-P×R×T100=180   ⇒2PR = 18000 ......(2) Clearly, from (1) and (2), we cannot find the value of pSo, the data is not sufficient.

Q: Cube root of 729 then square it 3504 0

  • 1
    9
    Correct
    Wrong
  • 2
    36
    Correct
    Wrong
  • 3
    81
    Correct
    Wrong
  • 4
    144
    Correct
    Wrong
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Answer : 3. "81"
Explanation :

Answer: C) 81 Explanation: 729 = 9 x 9 x 9 => Cube root of 729 = 9   Now, required square of 9 = 9 x 9 = 81.

Q: Eight years ago, Ajay's age was 4/3 times that of Vijay. Eight years hence, Ajay's age will be 6/5 times that of Vijay. What is the present age of Ajay ? 3502 0

  • 1
    41 yrs
    Correct
    Wrong
  • 2
    40 yrs
    Correct
    Wrong
  • 3
    37 yrs
    Correct
    Wrong
  • 4
    33 yrs
    Correct
    Wrong
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Answer : 2. "40 yrs"
Explanation :

Answer: B) 40 yrs Explanation: Let the present ages of Ajay and Vijay be 'A' and 'V' years respectively. => A - 8 = 4/3 (V - 8) and A + 8 = 6/5 (V + 8) => 3/4(A - 8) = V - 8 and 5/6(A + 8) = V + 8 V = 3/4 (A - 8) + 8 = 5/6 (A + 8) - 8 => 3/4 A - 6 + 8 = 5/6 A + 20/3 - 8 => 10 - 20/3 = 10/12 A - 9/12 A => 10/3 = A/12 => A = 40.

Q: Sponge is to Porous as Rubber is to 3499 0

  • 1
    Inflexible
    Correct
    Wrong
  • 2
    Elastic
    Correct
    Wrong
  • 3
    Solid
    Correct
    Wrong
  • 4
    Massive
    Correct
    Wrong
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Answer : 2. "Elastic"
Explanation :

Answer: B) Elastic Explanation: A sponge is a porous material. Rubber is an elastic material.  Since Rubber is not a Massive or solid and not an inflexible thing, it is elastic.

Q: A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ? 3493 0

  • 1
    22/7 x 24/35
    Correct
    Wrong
  • 2
    22/7 x 36 x 4
    Correct
    Wrong
  • 3
    22/7 x 36/5
    Correct
    Wrong
  • 4
    22/7 x 37/21
    Correct
    Wrong
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Answer : 1. "22/7 x 24/35"
Explanation :

Answer: A) 22/7 x 24/35 Explanation: Since level of water increased in cylinder by height 4.  This is because of the rectangular block .   Therefore , area of rectangular block immersed in water is  = 227×6×6×4   Thats why portion of block immersed in water is  = (22/7 * 36 * 4) / total vol. of rectangle  = (22/7 * 36 * 4)/ (7*5*6)  = (22/7 * 24)/ 35.

Q: The calendar for the year 2018 will be the same for the year 3491 0

  • 1
    2023
    Correct
    Wrong
  • 2
    2027
    Correct
    Wrong
  • 3
    2029
    Correct
    Wrong
  • 4
    2022
    Correct
    Wrong
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Answer : 3. "2029"
Explanation :

Answer: C) 2029 Explanation: How to find the years which have the same Calendars :   Leap year calendar repeats every 28 years. Here 28 is distributed as 6 + 11 + 11.   Rules: a) If given year is at 1st position after Leap year then next repeated calendar year is Givenyear+6. b) If given year is at 2nd position after Leap year then next repeated calendar year is Givenyear+11. c) If given year is at 3rd position after Leap year then next repeated calendar year is Givenyear+11.   Now, the given year is 2018 We know that 2016 is a Leap year. 2016    2017    2018    2019  2020 Lp Y      1st     2nd      3rd     Lp Y   Here 2018 is at 2 nd position after the Leap year. According to rule b) the calendar of 2018 is repeated for the year is 2018 + 11 = 2029.

Q: Three men, four women and six children can complete a work in 9 days. A women does  double the work a man does and a child does half the work a man does. How many women alone can complete this work in 9 days? 3487 0

  • 1
    7
    Correct
    Wrong
  • 2
    8
    Correct
    Wrong
  • 3
    9
    Correct
    Wrong
  • 4
    6
    Correct
    Wrong
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Answer : 1. "7"
Explanation :

Answer: A) 7 Explanation: Given (3 Men + 4 Women + 6 Children) -----> 9 days But W = 2M and C = M/2 Now, convert Men and Children into Women by 3W2 + 4W + 6W4=> 32 + 4 + 32 = 7 Women  Therefore, 7 women alone can complete this work in 9 days.

Q: Find the odd one out of the floowing number series? 270, 261, 279, 252, 289, 243 3475 0

  • 1
    270
    Correct
    Wrong
  • 2
    279
    Correct
    Wrong
  • 3
    289
    Correct
    Wrong
  • 4
    243
    Correct
    Wrong
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Answer : 3. "289"
Explanation :

Answer: C) 289 Explanation: Here the given number series is 270, 261, 279, 252, 289, 243 270 - 9 = 261 261 + 18 = 279 279 - 27 = 252 252 + 36 = 288 (not equals to 289) 288 - 45 = 243   Hence, the odd number in the given number series is 289.

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