Answer: C) PYTOOJ Explanation: FRIEND : FPIBNZ Follows a pattern that, F - F R- second letter to left of R i.e, P I - I E - Third letter to left of E i.e, B N - N D - Fourth letter to left of D i.e, Z Similarly, for PATRON  P - P A -  second letter to left of A i.e, Y T - T R - Third letter to left of R i.e, O O - O N - Fourth letter to left of N i.e, J PATRON : PYTOOJ   Therefore, FRIEND : FPIBNZ :: PATRON : PYTOOJ

Answer: A) Rs. 316 Explanation: S.I. for 2 years = (514 - 415) = Rs. 99S.I. for 1 year = 99/2 Principal = (415 - 99) = Rs. 316.

Answer: C) 12th element Explanation: If we consider the third term to be ‘x”The 15th term will be (x + 12d)6th term will be (x + 3d)11th term will be (x + 8d) and 13th term will be (x + 10d).Thus, as per the given condition, 2x + 12d = 3x + 21d.Or x + 9d = 0.x + 9d will be the 12th term. Thus, 12th term of the A.P will be zero.

Answer: B) (1+2m)/2 Explanation: log4928 = 12log77×4   = 12+122log72= 12+log72= 12 + m= 1+2m2.

Answer: B) 338 Explanation: We know that 40% = 25   40% of 265 + 35% of 180 = 50% ?   25 x 265 + 35% of 180 = 50% ?   We know that (35% of 180 = 180% of 35) & 180% = 95   25 x 265 + 95 x 35 = 50% ?   106 + 63 = 50% ?   ?= 2 x 169 = 338.

Answer: D) 2311 cub. cm Explanation: Given Circumference of a circular base of a cylinder = 44 cm We know that Circumference of a circle = 2πr = 44⇒r = 22π Now given the height of a cylinder h = 15 cm Volume of a cylinder V = πr2h = π22π215 = 22 x 22 x 153.14 = 2311 cm3.

Answer: A) Incorrigible Explanation: The One-word substitute for That which cannot be corrected is Incorrigible.

Answer: A) Wednesday Explanation: The year 2006 is an ordinary year. So, it has 1 odd day.So, the day on 24th Nov, 2007 will be 1 day beyond the day on 24th Nov, 2006.But, 24th Nov, 2007 is Thursday. 24 - 10 = 14 days. Therefore, 2 weeks ago it is same day. Thus, 10th Nov, 2006 is one day before 10th Nov, 2007 i.e. it is Wednesday.