GATE Practice Question and Answer

Q: What is an error in a program called 2855 0

  • 1
    Power fail
    Correct
    Wrong
  • 2
    Crash
    Correct
    Wrong
  • 3
    Virus
    Correct
    Wrong
  • 4
    Bug
    Correct
    Wrong
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Answer : 4. "Bug"
Explanation :

Answer: D) Bug Explanation: In computer technology, a coding error in a computer program is called a bug.

Q: A sum of money at simple interest amounts to Rs. 415 in 2 years and to Rs. 514 in 4 years. The sum is ? 2848 0

  • 1
    Rs. 316
    Correct
    Wrong
  • 2
    Rs. 251
    Correct
    Wrong
  • 3
    Rs. 154
    Correct
    Wrong
  • 4
    Rs. 294
    Correct
    Wrong
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Answer : 1. "Rs. 316"
Explanation :

Answer: A) Rs. 316 Explanation: S.I. for 2 years = (514 - 415) = Rs. 99S.I. for 1 year = 99/2 Principal = (415 - 99) = Rs. 316.

Q: Name a common greenhouse gas containing only hydrogen and oxygen? 2846 0

  • 1
    CH4
    Correct
    Wrong
  • 2
    O3
    Correct
    Wrong
  • 3
    H2O
    Correct
    Wrong
  • 4
    NO
    Correct
    Wrong
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Answer : 3. "H2O"
Explanation :

Answer: C) H2O Explanation: The common greenhouse gas containing only hydrogen and oxygen is H2O, this is water vapor. The common greenhouse gases are water vapor, carbon dioxide, methane, nitrous oxide, and ozone. The composition (chemical formula) of those gases are: Water vapor: H2OCarbon dioxide: CO2Methane: CH4Nitrous oxide: NOOzone: O3. As you see the only one of those that contains only hydrogen and oxygen is H2O, water vapor.

Q: Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it?  ___ utt ___ tt ___ ttu ___ 2843 0

  • 1
    t t u t
    Correct
    Wrong
  • 2
    t u t t
    Correct
    Wrong
  • 3
    t u u t
    Correct
    Wrong
  • 4
    t t t u
    Correct
    Wrong
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Answer : 3. "t u u t"
Explanation :

Answer: C) t u u t Explanation: t, u, u and t. The sequence is : tut tut tut tut.

Q: Sushma joins a job at 20 yrs. First 3 years salary is 10,000 p.a. Afterwards every year increment of 2,000 per year for 10 years. Then salary becomes constant till retirement. At retirement average salary is 25,000. (throughout career). At what age Sushma retires ? 2840 0

  • 1
    50 yrs
    Correct
    Wrong
  • 2
    47 yrs
    Correct
    Wrong
  • 3
    45 yrs
    Correct
    Wrong
  • 4
    42 yrs
    Correct
    Wrong
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Answer : 1. "50 yrs"
Explanation :

Answer: A) 50 yrs Explanation: Let age of retirement = Sso according to the given condition 25000(x-20)=10000 x 3 + 12000 + 14000 + 16000 + 18000 + 20000 + 22000 + 24000 + 26000 + 28000 + 30000 + 30000(S-33)= 30000 + 210000 + 30000S-990000= 30000S - 750000or 25000S - 500000 = 30000x - 750000or 5000x = 250000or S = 50 yrs.

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Answer :
Explanation :

One grandfather, One father and One son makes two fathers and two sons.

Q: The cost of 7 tables and 12 chairs is Rs 48,250. What is the cost of 21 tables and 36 chairs ? 2833 0

  • 1
    Rs. 1,44,750
    Correct
    Wrong
  • 2
    Rs. 2,35,745
    Correct
    Wrong
  • 3
    Rs. 89,489
    Correct
    Wrong
  • 4
    Rs.74,256
    Correct
    Wrong
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Answer : 1. "Rs. 1,44,750"
Explanation :

Answer: A) Rs. 1,44,750 Explanation: 3T+12C = 48,250----(1) 21T+36C = ? multiply eq (1) with 3i.e,, 3(7T+12C) = 48,250*321T+36C = 1,44,750/-

Q: A man covers a distance of 1200 km in 70 days resting 9 hours a day, if he rests 10 hours a day and walks with speed 1½ times of the previous in how many days will he cover 840 km ? 2832 0

  • 1
    39 days
    Correct
    Wrong
  • 2
    37 days
    Correct
    Wrong
  • 3
    35 days
    Correct
    Wrong
  • 4
    33 days
    Correct
    Wrong
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Answer : 3. "35 days"
Explanation :

Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.

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