Answer: C) 35 days Explanation: Distance d = 1200kmlet S be the speed he walks 15 hours a day(i.e 24 - 9)so totally he walks for 70 x 15 = 1050hrs. S = 1200/1050 => 120/105 = 24/21 => 8/7kmph given 1 1/2 of previous speedso 3/2 * 8/7= 24/14 = 12/7 New speed = 12/7kmph Now he rests 10 hrs a day that means he walks 14 hrs a day. time = 840 x 7 /12 => 490 hrs=> 490/14 = 35 days So he will take 35 days to cover 840 km.

Answer: A) 11 days Explanation: Let 'n' number of days it take to complete.   we know that sum of n number= n/2[2a+(n-1)d]where a=20,d=1;n/2[2x20+(n-1)1]=275n[n+39]=550n2 + 39n - 550 = 0 n2+ 50n - 11n - 550 = 0(n-11) (n-50) = 0n-11 = 0;n = 11(Days).

Answer: B) 264 km Explanation: Let the distance travelled by Tilak in first case or second case = d kms Now, from the given data, d/20 = d/22 + 36 min => d/20 = d/22 + 3/5 hrs => d = 132 km.   Hence, the total distance travelled by him = d + d = 132 + 132 = 264 kms.

Answer: D) Trajectory Explanation: The path traced by planet is called Orbit. Similarly, the path traced by projectile is called Trajectory.   Hence, Planet : Orbit : : Projectile : Trajectory.

Answer: C) is used to temporarily store, items that has been cut or copied Explanation: A clipboard is a temporary storage area for items that the user wants to cut or copy from one place to another.   For example, in a word processor application, the user might want to cut text from one part of a document and paste it in another part of the document or somewhere else, it is temporarily stored in clipboard.

Answer: C) 16 yrs Explanation: 12 year old Manish is three times as old as his brother Rajeev who must be 4 years old.Diff in ages = 8 years.when Rajeev will become 8 years old, Manish will be 16 yrs old and he will be twice as old as Rajeev.

Answer: D) 10 Explanation: Here the given number series is 6, 3, 3, 4.5, 10 The odd one in the given series is 10 The pattern it follows is 6 6 x 0.5 = 3 3 x  1  = 3 3 x 1.5 = 4.5 4.5 x 2 = 9   Hence, the odd number is 10.

Answer: C) 1/6 Explanation: Given X can do in 10 days  => 1 day work of X = 1/10   Y can do in 15 days  => 1 day work of Y = 1/15   1day work of (X + Y) = 1/10 + 1/15 = 1/6   Given they are hired for 5 days  => 5 days work of (X + Y) = 5 x 1/6 = 5/6  Therefore, Unfinished work = 1 - 5/6 = 1/6