GATE Practice Question and Answer
8Q: When Ionic bonds are formed metallic atoms tend to 2542 05b5cc697e4d2b4197774c5a5
5b5cc697e4d2b4197774c5a5- 1share electronsfalse
- 2gain electronsfalse
- 3lose electronstrue
- 4None of abovefalse
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Answer : 3. "lose electrons"
Explanation :
Answer: C) lose electrons Explanation: Ionic bonding is the complete transfer of valence electron(s) between atoms. It is a type of chemical bond that generates two oppositely charged ions. In ionic bonds, the metal loses electrons to become a positively charged cation, whereas the nonmetal accepts those electrons to become a negatively charged anion. Hence, when Ionic bonds are formed metallic atoms tend to lose electrons and become positive ions
Q: 25% of 25% Is Equal To 2538 05b5cc6bae4d2b4197774d78a
5b5cc6bae4d2b4197774d78a- 10.0625true
- 20.0210false
- 30.03145false
- 40.3210false
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Answer : 1. "0.0625"
Explanation :
Answer: A) 0.0625 Explanation: 25% of 25% means 25/100 of 25/100 i.e, 1/4 of 1/4 or in other words 1/4 x 1/4=1/16 Hence, the answer is 1/16 = 0.0625.
Q: A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately? 2536 05b5cc6bfe4d2b4197774da97
5b5cc6bfe4d2b4197774da97- 120true
- 219false
- 317false
- 422false
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Answer : 1. "20"
Explanation :
Answer: A) 20 Explanation: Given height of the conical tent = 3 m Diameter = 10 => Radius = D/2 = 10/2 = 5 m Now, as the tent is in the conical form Volume of the conical tent = πr2h3 => (22 x 5 x 5 x 3) / (7 x 3) = 22 x 25/7 = 78.54 cu.m Given each person requires 3.92 cu.m of air => Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20
Q: When Ankith saw Sanvi, he recalled, " She is the daughter of the father of my daughter's mother." Who is Sanvi to Ankit ? 2536 05b5cc758e4d2b4197774fbef
5b5cc758e4d2b4197774fbef- 1sisterfalse
- 2daughter-in-lawfalse
- 3sister-in-lawtrue
- 4cousinfalse
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Answer : 3. "sister-in-law"
Explanation :
Answer: C) sister-in-law Explanation: Ankit's daughter's mother---Ankit's wife; Ankit's wife's father---Ankit's father-in-law;Father-in-law's daughter--- Ankit's sister-in-law. So, Sanvi is sister-in-law of Ankit.
Q: A man saves 20% of his monthly salary. If an account of dearness of things he is to increase his monthly expenses by 15%, he is only able to save Rs. 400 per month. What is his monthly salary ? 2535 05b5cc6e1e4d2b4197774ebf2
5b5cc6e1e4d2b4197774ebf2- 1Rs. 6000false
- 2Rs. 4500false
- 3Rs. 5000true
- 4Rs. 6500false
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Answer : 3. "Rs. 5000"
Explanation :
Answer: C) Rs. 5000 Explanation: Income = Rs. 100 Expenditure = Rs. 80 Savings = Rs. 20 Present Expenditure 80x(15/100) = Rs. 12 = 80 + 12 = Rs. 92 Present Savings = 100 – 92 = Rs. 8 100 ------ 8? --------- 400 => 5000 His salary = Rs. 5000
Q: A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ? 2534 05b5cc731e4d2b4197774f7e2
5b5cc731e4d2b4197774f7e2- 110.5 kgsfalse
- 212 kgsfalse
- 39.6 kgsfalse
- 411.5 kgstrue
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Answer : 4. "11.5 kgs"
Explanation :
Answer: D) 11.5 kgs Explanation: Screws weight = 90x100 = 9000gmsbolts weight = 100 x 150 = 15000gmsweight = screws + bolts => 24000 gms =>24 kgGiven entire box weight = 35.5kgempty box = entire box weight - weight => 35.5kg - 24kg => 11.5kgso the empty box is 11.5kg.
Q: Rs. 69 were divided among 115 family members so that each lady gets 50 paise less than each gentleman, and each gentleman received twice the paise as each lady received. Find the number of gentlemen in the family? 2533 05b5cc67be4d2b4197774c1f0
5b5cc67be4d2b4197774c1f0- 123true
- 292false
- 348false
- 452false
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Answer : 1. "23"
Explanation :
Answer: A) 23 Explanation: Total number of female members = 115 Let the number of males = x Number of females = y => x + y = 115 ......(1) According to the given data, x + y(0.50) = 69 ......(2) From (1) & (2), we get 0.5y = 46 => y = 46 x 2 = 92 => x = 115 - 92 = 23 Hence, required number of gentlemen in the family = x = 23.
Q: The modulus of elasticity for mild steel is approximately equal to 2532 05b5cc65ee4d2b4197774be16
5b5cc65ee4d2b4197774be16- 1210 kN/mm2true
- 2100 kN/mm2false
- 380 kN/mm2false
- 410 kN/mm2false
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Answer : 1. "210 kN/mm2"
Explanation :
Answer: A) 210 kN/mm2 Explanation: It is useful to have a property of a material that is independent of the size of the sample and can be use to compare its elastic properties with another - this is called the Modulus of Elasticity for the material. The modulus of elasticity is defined as: Modulus of elasticity = Stress / Strain There are three types of moduli. They are : (a) the Young Modulus - tensile and compression longitudinal stress (b) the shear modulus - a shearing stress (c) the bulk modulus - volume changes of the specimen.

