GATE Practice Question and Answer
8Q: X can complete the work in 10 days, Y can do the same in 15 days. If they are hired for 5 days to do the work together, what is the work that left unfinished? 2443 05b5cc6bfe4d2b4197774da0a
5b5cc6bfe4d2b4197774da0a- 11/3false
- 22/3false
- 31/6true
- 45/6false
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Answer : 3. "1/6"
Explanation :
Answer: C) 1/6 Explanation: Given X can do in 10 days => 1 day work of X = 1/10 Y can do in 15 days => 1 day work of Y = 1/15 1day work of (X + Y) = 1/10 + 1/15 = 1/6 Given they are hired for 5 days => 5 days work of (X + Y) = 5 x 1/6 = 5/6 Therefore, Unfinished work = 1 - 5/6 = 1/6
Q: A shopkeeper has a job to print certain number of documents and there are three machines P, Q and R for this job. P can complete the job in 3 days, Q can complete the job in 4 days and R can complete the job in 6 days. How many days the shopkeeper will it take to complete the job if all the machines are used simultaneously ? 2442 05b5cc758e4d2b4197774fbf4
5b5cc758e4d2b4197774fbf4- 14/3 daystrue
- 22 daysfalse
- 33/2 daysfalse
- 44 daysfalse
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Answer : 1. "4/3 days"
Explanation :
Answer: A) 4/3 days Explanation: Let the total number of documents to be printed be 12. The number of documents printed by P in 1 day = 4. The number of documents printed by Q in 1 day = 3. The number of documents printed by R in 1 day = 2. Thus, the total number of documents that can be printed by all the machines working simultaneously in a single day = 9. Therefore, the number of days taken to complete the whole work = 12/9 = 4/3 days.
Q: What number should replace the question mark? 125, 138, 164, ?, 255 2441 05b5cc6a1e4d2b4197774cabd
5b5cc6a1e4d2b4197774cabd- 1189false
- 2197false
- 3200false
- 4203true
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Answer : 4. "203"
Explanation :
Answer: D) 203 Explanation: The given number series is 125, 138, 164, ?, 255 125 125 + 13x1 = 138 138 + 13x2 = 164 164 + 13x3 = 203 203 + 13x4 = 255 Hence, the missing number in the series is 203.
Q: Which of the following statements about Woodrow Wilson is true? 2438 05b5cc60de4d2b4197774b613
5b5cc60de4d2b4197774b613- 1He wanted to place strict government controls on corporations.true
- 2He overturned discriminatory laws against African Americans.false
- 3He advocated eliminating the income tax.false
- 4He opposed reforms to the banking system.false
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Answer : 1. "He wanted to place strict government controls on corporations."
Explanation :
Answer: A) He wanted to place strict government controls on corporations. Explanation: Woodrow Wilson was one of the major "Progressives" in American government and so 'He wanted to place strict government controls on corporations.'
Q: I jump when i walk and sit when i stand, who am I? 2437 05b5cc6a0e4d2b4197774ca65
5b5cc6a0e4d2b4197774ca65- Show AnswerHide Answer
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Answer :
Explanation :
Kangaroo.
Q: The top and bottom of a tower were seen to be at angles of depression 30° and 60° from the top of a hill of height 100 m. Find the height of the tower ? 2436 15b5cc72ce4d2b4197774f79c
5b5cc72ce4d2b4197774f79c- 142.2 mtsfalse
- 233.45 mtsfalse
- 366.6 mtstrue
- 458.78 mtsfalse
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Answer : 3. "66.6 mts"
Explanation :
Answer: C) 66.6 mts Explanation: From above diagramAC represents the hill and DE represents the tower Given that AC = 100 m angleXAD = angleADB = 30° (∵ AX || BD ) angleXAE = angleAEC = 60° (∵ AX || CE) Let DE = h Then, BC = DE = h, AB = (100-h) (∵ AC=100 and BC = h), BD = CE tan 60°=AC/CE => √3 = 100/CE =>CE = 100/√3 ----- (1) tan 30° = AB/BD => 1/√3 = 100−h/BD => BD = 100−h(√3)∵ BD = CE and Substitute the value of CE from equation 1 100/√3 = 100−h(√3) => h = 66.66 mts The height of the tower = 66.66 mts.
Q: A box contains 90 screws each of 100 gms and 100 bolts each of 150 gms. If the entire box weighs 35.5 kg, then the weight of the empty box is ? 2436 05b5cc731e4d2b4197774f7e2
5b5cc731e4d2b4197774f7e2- 110.5 kgsfalse
- 212 kgsfalse
- 39.6 kgsfalse
- 411.5 kgstrue
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Answer : 4. "11.5 kgs"
Explanation :
Answer: D) 11.5 kgs Explanation: Screws weight = 90x100 = 9000gmsbolts weight = 100 x 150 = 15000gmsweight = screws + bolts => 24000 gms =>24 kgGiven entire box weight = 35.5kgempty box = entire box weight - weight => 35.5kg - 24kg => 11.5kgso the empty box is 11.5kg.
Q: A Conical tent was erected by the army at a base camp with height 3 m and base diameter 10 m. If every person requires 3.92 cu.m air, then how many persons can be seated in that tent approximately? 2434 05b5cc6bfe4d2b4197774da97
5b5cc6bfe4d2b4197774da97- 120true
- 219false
- 317false
- 422false
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Answer : 1. "20"
Explanation :
Answer: A) 20 Explanation: Given height of the conical tent = 3 m Diameter = 10 => Radius = D/2 = 10/2 = 5 m Now, as the tent is in the conical form Volume of the conical tent = πr2h3 => (22 x 5 x 5 x 3) / (7 x 3) = 22 x 25/7 = 78.54 cu.m Given each person requires 3.92 cu.m of air => Number of persons can be seated in the tent = 78.54/3.92 = 20.03 =~ 20