Answer: D) 432 Explanation: There are 600 Kabaddi players4% wear knee band on one legRemaining players = 600 x 0.96 = 576Of the remaining, 25% wear knee bands on both leg and Of the remaining, 75% do not wear knee bands .So players not wearing knee bands = 0.75 x 576 = 576 x 3/4 = 144 x 3 = 432.

Answer: D) L Explanation: Here the letters follow the rule (AxZ)+(A+Z) The number corresponding to the letters are used in the rule A=1, Z=26 => 26x1 + 1 + 26 = 26+27 = 53 =  053 (LxP)+(L+P) = (12 x16) + 12 + 16 = 192+28 = 220 Similarly (11x12) + 11 + 12 => 132 + 23 = 155

Answer: A) 4/3 days Explanation: Let the total number of documents to be printed be 12.  The number of documents printed by P in 1 day = 4.  The number of documents printed by Q in 1 day = 3.  The number of documents printed by R in 1 day = 2.  Thus, the total number of documents that can be printed by all the machines working simultaneously in a single day = 9.   Therefore, the number of days taken to complete the whole work = 12/9 = 4/3 days.

Answer: B) 60 kms Explanation: Let 'd' be the distance and 's' be the speed and 't' be the timed=sxt45 mins = 3/4 hr and 48 mins = 4/5 hrAs distance is same in both cases;s(3/4) = (s-5)(4/5)3s/4 = (4s-20)/515s = 16s-80s = 80 km.=> d = 80 x 3/4 = 60 kms.

Answer: B) 170 lit Explanation: Given A alone can fill the tank of capacity 240 lit in 16 hrs. => A can fill in 1 hr = 240/16 = 15 lit => B alone can fill the tank of capacity 240 lit in 12 hrs. => B can fill in 1 hr = 240/12 = 20 lit Now, (A + B) in 1 hr = 15 + 20 = 35 lit But they are opened for 2 hrs => 2 x 35 = 70 lit rae filled Remaining water to be filled in tank of 240 lit = 240 - 70 = 170 lit.

Answer: C) UX Explanation: Each corresponding letter moves five places forward in the alphabet.Here as BE is related to GJ then PS will relate to UX.

Answer: A) 34 Explanation: M + Tu + W + Th = 4 x 48 = 192Tu + W + Th + F = 4 x 46 = 184M = 42Tu + W + Th = 192 - 42 = 150F = 184 – 150 = 34

Answer: D) All the above Explanation: Glycolysis is the chemical process that converts glucose C₆H₁₂O₆, into Pyruvate, CH₃COCOO− + H⁺.   It represents the first stage in the chemical oxidation of glucose by a cell. The free energy released in this process is used to form the high-energy molecules ATP and NADH.