GATE Practice Question and Answer

Q: 80 litres of diesel is required to travel 800 km using a 800 cc engine. If the volume of diesel required to cover a distance varies directly as the capacity of the engine, then how many litres of diesel is required to travel 1000 kms using 1200 cc engine ? 2387 0

  • 1
    120 lit
    Correct
    Wrong
  • 2
    140 lit
    Correct
    Wrong
  • 3
    110 lit
    Correct
    Wrong
  • 4
    150 lit
    Correct
    Wrong
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Answer : 4. "150 lit"
Explanation :

Answer: D) 150 lit Explanation: To cover a distance of 800 kms using a 800 cc engine, the amount of diesel required = 80 litres. => the amount of diesel required to cover a distance of 1000 kms = 1000 x 80/800 = 100 litres However, the vehicle uses a 1200 cc engine and it is given that the amount of diesel required varies directly as the engine capacity. i.e., for instance, if the capacity of engine doubles, the diesel requirement will double too. Therefore, with a 1200 cc engine, quantity of diesel required = 1200/800 x 100 = 150 litres.

Q: 90 D in a R A 2386 0

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Answer :
Explanation :

90 D in a R A => 90 degrees in a Right Angle.  This is similar to  26 L of the A = 26 Letters of the Alphabet 12 S of the Z.

Q: Folder is to document as envelope is to 2383 0

  • 1
    Money
    Correct
    Wrong
  • 2
    Articles
    Correct
    Wrong
  • 3
    Letters
    Correct
    Wrong
  • 4
    Wires
    Correct
    Wrong
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Answer : 3. "Letters"
Explanation :

Answer: C) Letters Explanation: We know that, a folder holds documents in the same way an envelope holds letters.   Hence, Folder : Document :: Envelope : Letter.

Q: Find the Odd One Out? 3 24 186 1008 5040 20160 2381 0

  • 1
    24
    Correct
    Wrong
  • 2
    20160
    Correct
    Wrong
  • 3
    186
    Correct
    Wrong
  • 4
    5040
    Correct
    Wrong
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Answer : 3. "186"
Explanation :

Answer: C) 186 Explanation: The given number series is 3  24  186  1008  5040  20160 Here  the given series follows a pattern that, 3 3 x 8 = 24 24 x 7 = 168 not 186 168 x 6 = 1008 1008 x 5 =  5040 5040 x 4 = 20160   Hence the Odd One in the number series is 186.

Q: Ronika deposited Rs.7000 which amounted to Rs.9200 after 3 years at simple interest. Had the interest been 2% more. She would get how much ? 2377 0

  • 1
    9850
    Correct
    Wrong
  • 2
    9500
    Correct
    Wrong
  • 3
    9620
    Correct
    Wrong
  • 4
    9760
    Correct
    Wrong
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Answer : 3. "9620"
Explanation :

Answer: C) 9620 Explanation: As the interest rate increases by 2%=> (7000x3x2)/100 = 420                                   9200                                  --------                                   9620

Q: If (2a + 3b)/(5a - 3b) = 23/5 , then the value of ba is ? 2377 0

  • 1
    5
    Correct
    Wrong
  • 2
    4
    Correct
    Wrong
  • 3
    20
    Correct
    Wrong
  • 4
    28
    Correct
    Wrong
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Answer : 3. "20"
Explanation :

Answer: C) 20 Explanation: Given (2a + 3b)/(5a - 3b) = 23/5 => 10a + 15b = 115a - 69b=> 105a = 84b => 5a = 4b a/b = 4/5 => a=4 & b=5=> bxa = 5x4 = 20.

Q: If Reena’s age was twice of her present age, when subtracted from four times three years from hence, with three times the three years before her present age. What will be her age after one year ? 2375 0

  • 1
    22 yrs
    Correct
    Wrong
  • 2
    21 yrs
    Correct
    Wrong
  • 3
    20 yrs
    Correct
    Wrong
  • 4
    24 yrs
    Correct
    Wrong
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Answer : 1. "22 yrs"
Explanation :

Answer: A) 22 yrs Explanation: Let Reena’s present age be 'K' yrs.Given:{(K+3) x 4} - {(K-3) x 3)} => K = 21 yrsSo her present age is 21 yrs.Then, her age after 1 year is 22 yrs.

Q: One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture. 2369 0

  • 1
    27 %
    Correct
    Wrong
  • 2
    26 %
    Correct
    Wrong
  • 3
    29 %
    Correct
    Wrong
  • 4
    21 %
    Correct
    Wrong
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Answer : 1. "27 %"
Explanation :

Answer: A) 27 % Explanation: Let the percentage of benzene = X(30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135  X = 27 So, required percentage of benzene = 27 %

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