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Q: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4323 0

Answer : 2. "7.5 hrs"
Explanation :
Answer: B) 7.5 hrs Explanation: Let there are L men job requires LK man hours. job completed in first 4 hrs = L x 4 = 4L job completed in next 4 hrs = 4 x L/2 = 2L job completed in next 4 hrs = 4 x L/4 = L job completed in last 4 hrs = 4 x L/8 = L/2 4L + 2L + L + L/2 = KL K = 7+1/2 = 7.5 hours.

Q: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4314 0

Answer : 4. "1250"
Explanation :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

Q: Read the following information carefully and answer the question below. Seven Students – A, B, C, D, E, F and G like different Pens viz, Reynolds, Cello, Parker, Rotomac, Flair, Linc and Eilcos but not necessarily in the same order. They also study in three different standards viz. 9th, 10th and 12th. Not more than three and not less than two students study in the same class. A do not likes cello pen. Persons who like cello and Flair pens, study in the same class. G studies in 10th standard but he does not likes flair pen. B studies with only one student, who likes linc pens. B does not studies with G. E likes Rotomac but he do not study in class 9. D studies in class 9 but he does not like line pen. A does not study in class 12. F does not like linc pen. The one likes Parker pen, studies in class 10. The one, who likes Reynolds pen, studies in same class with one who likes Flair pen. D likes neither Flair pen nor cello pen. 1. Who likes Parker Pen ? (1) F (2) G (3) H (4) None 2. Three of the following four are similar in a certain way. Find the odd one ? (1) BE (2) AD (3) EG (4) DF 3. Which three student study in the same class ? (1) ADE (2) DFG (3) ADF (4) AEG 4. C likes which pen ? (1) Reynolds (2) Flair (3) Cello (4) Linc 4298 0

Answer :
Explanation :
1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.

Q: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4281 0

Answer : 3. "35 and 11 years"
Explanation :
Answer: C) 35 and 11 years Explanation: Let the age of sushma be x and the age of her son is yThen five years before x-5=5(y-5) ...(1)Five years hence x+5 = 3(y+5)-8 .....(2) By soving (1) & (2), we get5y - 15 = 3y + 7y = 11 => x = 35 Therefore, the age of Sushma = 35 and her son = 11.

Q: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 4231 0

Answer : 3. "C"
Explanation :
Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4224 0

Answer : 3. "90 min"
Explanation :
Answer: C) 90 min Explanation: Let X = Time taken for each of Type B Problems(100 Problems)And 2X = Time taken for each of Type A problems(50 problems) Total time period = 3hrs = 3 x 60min = 180 minutes 100X + 50(2X) = 180100X + 100X = 180200X = 180 min X = 180/200X = 0.90 min By convertiing into seconds, X = 0.90 x 60 secondsX = 54 sec So, time taken for Part A problems is = 54 x 2 x 50 = 5400 seconds= 5400/60sec = 90 minutes.

Q: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 4179 0

Answer : 2. "8 : 13"
Explanation :
Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13

Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 4178 0

Answer : 2. "30 years"
Explanation :
Answer: B) 30 years Explanation: Let Karan’s present age be x years and Shiva’s present age be y years.Then, according to the first condition,x - 10 = 3(y - 10) or x - 3y = - 20 ..(1) Now, Karan’s age after 10 years = (x + 10) yearsShiva’s age after 10 years = (y + 10)(x + 10) = 2 (y + 10) or x - 2y = 10 ..(2) Solving (1) and (2), we get x = 70 and y = 30Karan’s age = 70 years and Shiva’s age = 30 years.

Q: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4323 0

Q: An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ? 4314 0

Answer : 4. "1250"
Explanation :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

Answer :
Explanation :
1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.

Q: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4281 0

Q: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 4231 0

Answer : 3. "C"
Explanation :
Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4224 0

Q: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 4179 0

Answer : 2. "8 : 13"
Explanation :
Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13

Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 4178 0

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Q: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4323 05b5cc73ae4d2b4197774f8d8

Answer : 4. "1250" Explanation :Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

Answer : Explanation :1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.

Q: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4281 05b5cc73ae4d2b4197774f8d3

Q: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 4231 05b5cc70ee4d2b4197774f380

Answer : 3. "C" Explanation :Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4224 05b5cc74fe4d2b4197774fb1c

Q: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 4179 05b5cc715e4d2b4197774f463

Answer : 2. "8 : 13" Explanation :Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13

Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 4178 05b5cc75ee4d2b4197774fcca

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Q: A group of men can complete a job in K hours. After every 4 hours, half the number of men working at that point of time leave the job. Continuing this way if the job is finished in 16 hours, what is the value of K ? 4323 0

Answer : 4. "1250"
Explanation :
Answer: D) 1250 Explanation: Let initially 'X' ticket has been sold.So now in 2nd week 20% increases, so=> X x 120/100In 3rd week 16% increases, so=> X x (120/100) x (116/100)In 4th week 20% decrease, so=> X x (120/100) x (116/100) x (80/100) = 1392X = 1250.

Answer :
Explanation :
1. Answer (2) G 2. Answer (1) BE All other pairs are in same class. 3. Answer (3) ADF in class 9. 4. Answer (4) Linc pen.

Q: 5 years ago Sushma was 5 times as old as her Son. 5 years hence her age will be 8 less than three times the corresponding age of her Son. Find their ages ? 4281 0

Q: Which alphabet replaces the question mark ? 63 O 4972 T 3796 L 1514 ? 58 4231 0

Answer : 3. "C"
Explanation :
Answer: C) C Explanation: 6-3 = 3 9-4 = 5 (3x5=15) 15=O7-2 = 5 7-3 = 4 (5x4=20) 20=T9-6 = 3 5-1 = 4 (3x4=12) 12=L Similarly, 4-1 = 3 8-5 = 1 (3x1=3) 3=C

Q: If there are 150 questions in a 3 hr examination. Among these questions 50 are type A problems, which requires twice as much as time be spent on the rest of the type B problems. How many minutes should be spent on type A problems ? 4224 0

Q: Two solutions have milk & water in the ratio 7:5 and 6:11. Find the proportion in which these two solutions should Be mixed so that the resulting solution has 1 part milk and 2 parts water ? 4179 0

Answer : 2. "8 : 13"
Explanation :
Answer: B) 8 : 13 Explanation: To get the solution that contains 1 part of milk and two parts of water,they must be mixed in the ratio as7x+6x/5y+11y = 1/226x = 16yx/y = 16/26x/y = 8/13

Q: Ten years ago, Karan was thrice as old as Shiva was but 10 years hence, he will be only twice as old. Find Shiva’s present age ? 4178 0