GRE Practice Question and Answer
8Q: The intersection of a column and a row 3404 05b5cc651e4d2b4197774bcdb
5b5cc651e4d2b4197774bcdb- 1Celltrue
- 2Menufalse
- 3Keyfalse
- 4Fieldfalse
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Answer : 1. "Cell"
Explanation :
Answer: A) Cell Explanation: The intersection of a column and a row in a spread sheet is called as a cell or a bon.
Q: The basic operations performed by a computer are 3383 05b5cc651e4d2b4197774bcea
5b5cc651e4d2b4197774bcea- 1Logical operationfalse
- 2Storage and relativefalse
- 3Arithmetic operationfalse
- 4All the abovetrue
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Answer : 4. "All the above"
Explanation :
Answer: D) All the above Explanation: The basic operations performed by a computer are Arithmetic operation, Logical operation and Storage and relative.
Q: How many number of weights do you need to weight 31 kg of Rice if you have one kg of weight stone ? 3380 05b5cc736e4d2b4197774f879
5b5cc736e4d2b4197774f879- 13false
- 25true
- 37false
- 49false
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Answer : 2. "5"
Explanation :
Answer: B) 5 Explanation: There are total 5 ways.we have only one kg of weight so,2kg = 1kg + 1kg4kg = 1 + 2 + 18kg = 1 + 2 + 4 + 116kg = 1 + 2 + 4 + 8 + 131kg = 1 + 2 + 4 + 8 + 16So 5 weights are needed.
Q: If the rate increases by 2%, the simple interest received on a sum of money increases by Rs. 108. If the time period is increased by 2 years, the simple interest on the same sum increases by Rs.180. The sum is ? 3375 05b5cc767e4d2b4197774fe0b
5b5cc767e4d2b4197774fe0b- 1Rs. 540false
- 2Rs. 415false
- 3Rs. 404false
- 4Data is not sufficienttrue
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Answer : 4. "Data is not sufficient"
Explanation :
Answer: D) Data is not sufficient Explanation: Let the sum be Rs. p, rate be R% p.a. and time be T years. Then, P×T×(R+2)100-P×T×R100=108 ⇒2PT= 10800 ...... (1) And, P×R×(T+2)100-P×R×T100=180 ⇒2PR = 18000 ......(2) Clearly, from (1) and (2), we cannot find the value of pSo, the data is not sufficient.
Q: स्मृति से बनी होती है 3372 15b5cc651e4d2b4197774bd14
5b5cc651e4d2b4197774bd14- 1कोशिकाओं की बड़ी संख्याtrue
- 2तारों का सेटfalse
- 3सर्किट का सेटfalse
- 4इनमे से कोई भी नहींfalse
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Answer : 1. "कोशिकाओं की बड़ी संख्या"
Explanation :
Answer: A) बड़ी संख्या में सेल स्पष्टीकरण: कंप्यूटिंग में, मेमोरी कंप्यूटर हार्डवेयर एकीकृत सर्किट को संदर्भित करता है जो कंप्यूटर में तत्काल उपयोग के लिए जानकारी संग्रहीत करता है। अधिकांश सेमीकंडक्टर मेमोरी को मेमोरी सेल या बिस्टेबल फ्लिप-फ्लॉप में व्यवस्थित किया जाता है, प्रत्येक एक बिट (0 या 1) को स्टोर करता है।
Q: The circumferences of two circles are 264 meters and 352 meters. Find the difference between the areas of the larger and the smaller circles ? 3370 05b5cc6dee4d2b4197774ea79
5b5cc6dee4d2b4197774ea79- 12413 sq.mfalse
- 21234 sq.mfalse
- 34312 sq.mtrue
- 42143 sq.mfalse
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Answer : 3. "4312 sq.m"
Explanation :
Answer: C) 4312 sq.m Explanation: Let the radii of the smaller and the larger circles be 's' m and 'l' m respectively. 2πs = 264 and 2πl = 352 s = 2642π and l = 3522π Difference between the areas =πl2-πs2 = π1762π2-1322π2 = 1762π-1322π = (176 - 132)(176 + 132) / π = (44 x 308) / (22/7) = 4312 sq.m
Q: Careful is to Cautious as Boastful is to 3359 05b5cc6ade4d2b4197774d0e9
5b5cc6ade4d2b4197774d0e9- 1Surprisinglyfalse
- 2Happilyfalse
- 3Arroganttrue
- 4Humblefalse
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Answer : 3. "Arrogant"
Explanation :
Answer: C) Arrogant Explanation: Here the given words Careful and Cautious are related in such a way that they are Synonyms of each other. Therefore, Similarly Boastful is synonym to the word Arrogant. Happily and Humble are Antonyms of Boastful and Surprisingly is the word not related to Boastful in any way. So, Careful is to Cautious as Boastful is to Arrogant.
Q: A rectangular block has the dimensions 5x6x7 cm it is dropped into a cylindrical vessel of radius 6cm and height 10 cm. If the level of the fluid in the cylinder rises by 4 cm, What portion of the block is immersed in the fluid ? 3354 05b5cc70ee4d2b4197774f337
5b5cc70ee4d2b4197774f337- 122/7 x 24/35true
- 222/7 x 36 x 4false
- 322/7 x 36/5false
- 422/7 x 37/21false
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Answer : 1. "22/7 x 24/35"
Explanation :
Answer: A) 22/7 x 24/35 Explanation: Since level of water increased in cylinder by height 4. This is because of the rectangular block . Therefore , area of rectangular block immersed in water is = 227×6×6×4 Thats why portion of block immersed in water is = (22/7 * 36 * 4) / total vol. of rectangle = (22/7 * 36 * 4)/ (7*5*6) = (22/7 * 24)/ 35.