GRE Practice Question and Answer
8Q: If 4th december 1999 is Monday then what day is 3rd january 2000 ? 2874 05b5cc73ae4d2b4197774f8ba
5b5cc73ae4d2b4197774f8ba- 1Sundayfalse
- 2Mondayfalse
- 3Tuesdayfalse
- 4Wednesdaytrue
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Answer : 4. "Wednesday"
Explanation :
Answer: D) Wednesday Explanation: Here from 4th December 1999 to 3rd January 2000,there is a difference of 30 days.Number of odd days = 30/7 = 2 odd days Then no. of odd days = 2 => tuesday and wednesday(from monday). Hence on 3rd january it is wednesday.
Q: 20 men went to a restaurant. Ninteen of them paid Rs.70 each and the twentieth man paid Rs.90.25 more than the average of all the 20 men. What is the total bill ? 1920 05b5cc73ae4d2b4197774f8b5
5b5cc73ae4d2b4197774f8b5- 1Rs. 1495true
- 2Rs. 548false
- 3Rs. 850false
- 4Rs. 1750false
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Answer : 1. "Rs. 1495"
Explanation :
Answer: A) Rs. 1495 Explanation: Let the average bill paid by twenty members = 'x' But 19 men paid each = Rs. 70 20th man paid Rs. 90.25 more than the avg bill of 20 = x + 90.25 20x = 19(70) + x + 90.2519x = 1330 + 90.2519x = 1420.25x = 1420.25/19 = Rs. 74.75 But the total bill = 20 x 74.75 = Rs. 1495.
Q: What is the next number in series? 10, 9, 60, 90, 70, 66, ? 2160 05b5cc73ae4d2b4197774f8b0
5b5cc73ae4d2b4197774f8b0- 173false
- 219false
- 396true
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Answer : 3. "96"
Explanation :
Answer: C) 96 Explanation: ten = 3(number of letters)nine = 4(number of letters)sixty = 5(number of letters)ninety = 6(number of letters)seventy = 7(number of letters)sixtysix = 8(number of letters)ninetysix=96(number of letters) Then, likwise choose the number which has 9 letters in its Spelling.
Q: In a year, Holi was enjoyed on 6th March 9 AM and Deepawali was celebrated on 11th November 8 PM. The total time interval (in hours) between the two was ? 2289 05b5cc73ae4d2b4197774f8ab
5b5cc73ae4d2b4197774f8ab- 12101 hrsfalse
- 24125 hrsfalse
- 35124 hrsfalse
- 46011 hrstrue
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Answer : 4. "6011 hrs"
Explanation :
Answer: D) 6011 hrs Explanation: From March 6th to November 11th, there are 250 days and Thus 250 x 24 hoursSo from Mar 6th 9AM to Nov 11th 8PM, there will be 250 x 24 + 11 hours = 6011 hrs.
Q: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? 519 328 746 495 837 1684 05b5cc73ae4d2b4197774f8a6
5b5cc73ae4d2b4197774f8a6- 1146true
- 2203false
- 3345false
- 496false
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Answer : 1. "146"
Explanation :
Answer: A) 146 Explanation: From the given series of numbers, if half of the second highest number is subtracted from the third highest number, what will be the value ? Now arranging the given numbers in descending order.837 746 519 495 328 519 - 746/2 = 519 - 373 = 146.
Q: If the numerator of a fraction is increased by 150% and the denominator of the fraction is increased by 350%, the resultant fraction is 25/51. What is the original fraction ? 2235 05b5cc73ae4d2b4197774f8a1
5b5cc73ae4d2b4197774f8a1- 131/25false
- 215/17true
- 314/25false
- 411/16false
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Answer : 2. "15/17"
Explanation :
Answer: B) 15/17 Explanation: The original fraction is 2551 × 350+100150+100 = 15/17.
Q: Sonika invested an amount of Rs.5800 for 2 years. At what rate of compound interest will she get an amount of Rs.594.50 at the end of 2 years ? 2241 05b5cc73ae4d2b4197774f89c
5b5cc73ae4d2b4197774f89c- 16.5%false
- 26%false
- 35%true
- 44.5%false
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Answer : 3. "5%"
Explanation :
Answer: C) 5% Explanation: C.I = P1+r100t-1 594.5 = 58001+r1002-1 594.55800+1=1+r1002 r100=1.05-1=0.05=> r = 5 % .
Q: Statements : All keys are locks. All locks are bangles. All bangles are cars. Conclusion : a. Some cars are locks. b. Some bangles are keys. c. Some cars are keys. 2287 05b5cc736e4d2b4197774f897
5b5cc736e4d2b4197774f897- 1Only a followsfalse
- 2Only c followsfalse
- 3Only a & b followsfalse
- 4a, b & c followstrue
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Answer : 4. "a, b & c follows"
Explanation :
Answer: D) a, b & c follows Explanation: All locks are bangles + All bangles are cars = A + A = A= All locks are cars => Some cars are locks.Hence conclusion (a) follows.All keys are locks + All locks are bangles = A + A = A= All keys are bangles => some bangles are keys.Hence conclusion (b) follows.All keys are bangles + All bangles are cars = A + A = A= All keys are cars => Some cars are keys.Hence conclusion (C) follows. Thus all a, b and c follows.

