GRE Practice Question and Answer

Q: There are n boxes and m fruits. If we put 3 fruits in each box 3 fruits will be excess. If we put 4 fruits in each box 1 box will be excess. Find number of boxes and fruits ? 1582 0

  • 1
    3 & 9
    Correct
    Wrong
  • 2
    6 & 19
    Correct
    Wrong
  • 3
    7 & 24
    Correct
    Wrong
  • 4
    5 & 18
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "7 & 24"
Explanation :

Answer: C) 7 & 24 Explanation: 7 boxes & 24 Balls.Let, n = No. of boxes ; m = No. of fruits3n+3 = m---------->(1)4(n-1)= m---------->(2)=>4n-4 = 3n+3;=>4n-3n = 4+3n = 7Put n=7 in eqn(1)=> 3(7)+3 = m21+3 = mm = 24; Number of boxes = 7 and fruits = 24

Q: Which of the following is the largest unit of information? 1579 0

  • 1
    1 TB
    Correct
    Wrong
  • 2
    1 GB
    Correct
    Wrong
  • 3
    1 MB
    Correct
    Wrong
  • 4
    1 KB
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "1 TB"
Explanation :

Answer: A) 1 TB Explanation: 1 TB  >  1 GB  >  1 MB  >  1 KB   1 Tb (Tera Byte) = 1024 GB 1 GB (Giga Byte) = 1024 MB 1 MB (Mega Byte) = 1024 KB 1 KB (Kilo Byte) = 1024 Bytes 1 Byte = 8 Bit   Hence, largest unit of information is TB (Tera Byte) and smallest unit of information is Bit.

Q: A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ? 1578 0

  • 1
    107 kmph
    Correct
    Wrong
  • 2
    106 kmph
    Correct
    Wrong
  • 3
    72 kmph
    Correct
    Wrong
  • 4
    76 kmph
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 2. "106 kmph"
Explanation :

Answer: B) 106 kmph Explanation: As we know that Speed = Distance / Timefor average speed = Total Distance / Total Time TakenThus, Total Distance = 325 + 470 = 795 kmThus, Total Speed = 7.5 hrsAverage Speed = 795/7.5 => 106 kmph.

Q: Guess the word? 1574 0

  • Show AnswerHide Answer
  • Workspace

Answer :
Explanation :

SHORT is the required five letter word, which becomes SHORTER when two letters 'ER' are added to it.

Q: What least number must be substracted from 627349 so that the remaining number is divisible by 15 ? 1574 0

  • 1
    1
    Correct
    Wrong
  • 2
    2
    Correct
    Wrong
  • 3
    3
    Correct
    Wrong
  • 4
    4
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 4. "4"
Explanation :

Answer: D) 4 Explanation: On dividing 627349 by 15, we get remainder = 4.Therefore, the obtained remainder is the least number to be subtracted from the given number so that the the mnumber is divisible by 15.Here 4 is the least number to be subtracted from 627349 so that it is divisible by 15.

Q: Calculate the number of bricks, each measuring 25 cm x 15 cm x 8 cm required to construct a wall of dimensions 10 m x 4 m x 5 m when 10% of its volume is occupied by concrete ? 1574 0

  • 1
    6000
    Correct
    Wrong
  • 2
    5400
    Correct
    Wrong
  • 3
    3800
    Correct
    Wrong
  • 4
    4700
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 1. "6000"
Explanation :

Answer: A) 6000 Explanation: Let 'B' be the nuber of bricks. => 10 x 4/100 x 5 x 90/100 = 25/100 x 15/100 x 8/100 x B => 10 x 20 x 90 = 15 x 2 x B => B = 6000

Q: IF YOU HAVE ME, YOU WANT TO SHARE ME. IF YOU SHARE ME, YOU HAVEN'T GOT ME. WHAT AM I? 1572 0

  • Show AnswerHide Answer
  • Workspace

Answer :
Explanation :

A Secret.

Q: Makaibari is the costliest variety of what? 1571 0

  • 1
    Coffee
    Correct
    Wrong
  • 2
    Pepper
    Correct
    Wrong
  • 3
    Tea
    Correct
    Wrong
  • 4
    Water
    Correct
    Wrong
  • Show AnswerHide Answer
  • Workspace

Answer : 3. "Tea"
Explanation :

Answer: C) Tea Explanation: Makaibari is the world's first tea factory and was established in 1859 in Darjeeling, West Bengal.    It is most expensive tea in India which costs around 1.12 lakhs for 1 kg of tea.   Hence, Makaibari is the costliest variety of Tea.

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully

      Report Error

    Please Enter Message
    Error Reported Successfully